Chapter 12: Problem 50
The mean weight of a group of 9 students is \(19 \mathrm{~kg}\). If a boy of weight \(29 \mathrm{~kg}\) is joined in the group, then find the mean weight of 10 students. The following are the steps involved in solving the above problem. Arrange them in sequential order. (a) The mean weight of 10 students \(=\frac{200}{10} \mathrm{~kg}\) (b) The total weight of 9 students \(=9 \times 19 \mathrm{~kg}=171 \mathrm{~kg}\) (c) The total weight of 10 students \(=(171+29) \mathrm{kg}=200 \mathrm{~kg}\) (d) \(\therefore\) The mean weight \(=20 \mathrm{~kg}\) (1) bcad (2) bdac (3) bdca (4) bcda
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.