Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Consider the Angus weights model \(N(1152,84)\) one last time. a) What weight represents the 40 th percentile? b) What weight represents the 99 th percentile? c) What's the IQR of the weights of these Angus steers?

Short Answer

Expert verified
40th percentile: 1130.75, 99th percentile: 1348.72, IQR: 113.4

Step by step solution

01

Identify the Parameters

The Angus weights model is a normal distribution with mean \(\mu = 1152\) and standard deviation \(\sigma = 84\). This is represented as \(N(1152,84)\).
02

Define the 40th Percentile

To find the weight at the 40th percentile, we need to find the value \(x\) such that the cumulative distribution function (CDF) for \(N(1152,84)\) at \(x\) is 0.40.
03

Calculate the Z-Score for the 40th Percentile

We look up the 40th percentile in the standard normal distribution table to find the z-score. The z-score corresponding to the 40th percentile is approximately \(z = -0.253\).
04

Convert Z-Score to X Value for 40th Percentile

Use the formula \(x = \mu + z\sigma\) to find the x-value. Substitute \(\mu = 1152\), \(z = -0.253\), and \(\sigma = 84\):\[x = 1152 + (-0.253)(84) = 1130.748\]
05

Define the 99th Percentile

To find the weight at the 99th percentile, we need to find the value \(x\) such that the CDF for \(N(1152,84)\) at \(x\) is 0.99.
06

Calculate the Z-Score for the 99th Percentile

We look up the 99th percentile in the standard normal distribution table to find the z-score. The z-score corresponding to the 99th percentile is approximately \(z = 2.33\).
07

Convert Z-Score to X Value for 99th Percentile

Use the formula \(x = \mu + z\sigma\) to find the x-value. Substitute \(\mu = 1152\), \(z = 2.33\), and \(\sigma = 84\):\[x = 1152 + (2.33)(84) = 1348.72\]
08

Define IQR (Interquartile Range)

The IQR is the difference between the 75th and 25th percentiles. We must first find these percentiles.
09

Calculate Z-Score for 25th Percentile

The z-score for the 25th percentile (first quartile, \(Q_1\)) is approximately \(z = -0.675\).
10

Convert Z-Score to X Value for 25th Percentile

Use the formula \(x = \mu + z\sigma\) to find the x-value. Substitute \(\mu = 1152\), \(z = -0.675\), and \(\sigma = 84\):\[x = 1152 + (-0.675)(84) = 1095.3\]
11

Calculate Z-Score for 75th Percentile

The z-score for the 75th percentile (third quartile, \(Q_3\)) is approximately \(z = 0.675\).
12

Convert Z-Score to X Value for 75th Percentile

Use the formula \(x = \mu + z\sigma\) to find the x-value. Substitute \(\mu = 1152\), \(z = 0.675\), and \(\sigma = 84\):\[x = 1152 + (0.675)(84) = 1208.7\]
13

Calculate the IQR

The IQR is given by \(Q_3 - Q_1\). Substitute the values previously calculated:\[IQR = 1208.7 - 1095.3 = 113.4\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Percentile
In statistics, a percentile indicates the relative standing of a value within a data set. It shows you the percentage of data points that fall below a particular value. For example, if a weight falls in the 40th percentile, it means that 40% of the weights are below this value.
Understanding percentiles is crucial for grasping how data is spread out in a normal distribution. A normal distribution is symmetric, so percentiles can help identify variations in the dataset.
  • How to find a percentile: In a normal distribution, utilize the cumulative distribution function (CDF) to find the value corresponding to a specific percentile.
  • Example: For the Angus weights, the 40th percentile is calculated using a z-score of -0.253, yielding a weight of about 1130.748 pounds.
Knowing how to compute percentiles can provide valuable insights into where certain values lie in relation to others, making it easier to interpret data sets.
Z-Score
The z-score is a measure that describes a value's position relative to the mean of a group of values, measured in units of standard deviation. It tells us how many standard deviations away a particular value is from the mean.
The ability to calculate a z-score is essential for understanding the normal distribution, as it allows you to determine how typical or atypical a particular data point is.
  • Z-score formula: The formula is given by \( z = \frac{x - \mu}{\sigma} \), where \( x \) is the data point, \( \mu \) is the mean, and \( \sigma \) is the standard deviation.
  • Application: For the Angus weights, using a z-score of 2.33 for the 99th percentile allows us to find the weight of 1348.72 pounds, which is very high relative to the average.
Mastering z-scores is key to interpreting and comparing different data sets within the context of a normal distribution pattern.
Interquartile Range (IQR)
The interquartile range (IQR) measures the middle 50% spread of data, providing a sense of variability. It's the difference between the 75th percentile (Q3) and the 25th percentile (Q1).
This concept is crucial for identifying the concentration of data around the median and for understanding how data is distributed across a range.
  • IQR calculation: Using the formulas for Q3 and Q1 with their corresponding z-scores helps us compute the IQR. For instance, in the Angus weights, the IQR is calculated as \( Q3 - Q1 = 1208.7 - 1095.3 = 113.4 \) pounds.
  • Significance: A smaller IQR suggests less variability, while a larger IQR indicates more spread within the data.
Understanding the IQR helps you describe the spread of data and identify potential outliers in a dataset structured by a normal distribution.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Exercise 17 we suggested the model \(N(1152,84)\) for weights in pounds of yearling Angus steers. What weight would you consider to be unusually low for such an animal? Explain.

Recall that the beef cattle described in Exercise 17 had a mean weight of 1152 pounds, with a standard deviation of 84 pounds. a) Cattle buyers hope that yearling Angus steers will weigh at least 1000 pounds. To see how much over (or under) that goal the cattle are, we could subtract 1000 pounds from all the weights. What would the new mean and standard deviation be? b) Suppose such cattle sell at auction for 40 cents a pound. Find the mean and standard deviation of the sale prices for all the steers.

Consider the IQ model \(N(100,16)\) one last time. a) What IQ represents the 15 th percentile? b) What IQ represents the 98 th percentile? c) What's the IQR of the IQs?

People with \(z\) -scores above \(2.5\) on an IQ test are sometimes classified as geniuses. If IQ scores have a mean of 100 and a standard deviation of 16 points, what IQ score do you need to be considered a genius?

Each year thousands of high school students take either the SAT or the ACT, standardized tests used in the college admissions process. Combined SAT Math and Verbal scores go as high as 1600, while the maximum ACT composite score is 36 . Since the two exams use very different scales, comparisons of performance are difficult. A convenient rule of thumb is \(S A T=40 \times A C T+150\); that is, multiply an ACT score by 40 and add 150 points to estimate the equivalent SAT score. An admissions officer reported the following statistics about the ACT scores of 2355 students who applied to her college one year. Find the summaries of equivalent SAT scores. Lowest score \(=19 \quad\) Mean \(=27\) Standard deviation \(=3\) \(\mathrm{Q} 3=30\) Median \(=28 \quad \mathrm{IQR}=6\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free