Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In Exercise 17 we suggested the model \(N(1152,84)\) for weights in pounds of yearling Angus steers. What weight would you consider to be unusually low for such an animal? Explain.

Short Answer

Expert verified
A weight below 984 pounds is unusually low for yearling Angus steers.

Step by step solution

01

Understanding the Problem

We're given a normal distribution model for the weights of yearling Angus steers, specifically, normally distributed with a mean (\(\mu\)) of 1152 pounds and a standard deviation (\(\sigma\)) of 84 pounds. The task is to find a weight that would be considered unusually low.
02

Identifying Unusual Values

In statistics, values that fall outside 2 standard deviations from the mean are typically considered unusual. We will calculate 2 standard deviations below the mean to find the unusually low weight.
03

Calculating Lower Boundary

We calculate the lower boundary using the formula: \[x = \mu - 2\sigma\]Substituting the given values, we have \[1152 - 2 \times 84 = 1152 - 168 = 984\]Thus, any weight below 984 pounds is considered unusually low.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Deviation
Standard deviation is a fundamental concept in statistics, representing the amount of variability or spread in a dataset. When we have a set of data points, some of them might deviate from the average, or mean, value more than others. This is where the standard deviation comes in. It gives us an average distance that these data points lie from the mean.

For example, in the normal distribution mentioned in the exercise, the weights of yearling Angus steers have a standard deviation of 84 pounds. This number quantifies how much the weights vary from the mean weight of 1152 pounds.
  • Low standard deviation: Data points are close to the mean.
  • High standard deviation: Data spreads over a wide range of values.
Standard deviation helps in understanding if the data is tightly clustered around the mean or more dispersed. When finding usual or unusual values, like an unusually low weight, standard deviation assists in setting the boundaries by indicating the typical spread.
Mean Value
The mean value, often simply referred to as the 'average' or \(\mu\), is a measure of central tendency in a data set. It represents the central point of a set of numbers. You calculate the mean by adding up all the values and dividing by their count. In the context of a normal distribution, it is the peak of the bell curve where most data points tend to cluster.

For the problem at hand, the mean weight of yearling Angus steers is given as 1152 pounds. This is the expected weight around which most of the steers will weigh.
  • Mean helps in summarizing a data set with a single value.
  • It is sensitive to the specific values and can shift with outliers.
When analyzing data through statistical modeling, the mean helps provide a baseline or reference point. In practical applications, knowing whether a specific data point is unusually high or low often depends first on comparing it to the mean value.
Statistical Modeling
Statistical modeling involves creating mathematical representations of real-world processes. These models help predict and understand variability in data. A normal distribution model, like the one used for the Angus steers, is a type of statistical model that assumes data points are dispersed in a characteristic bell-shaped curve around the mean.

Using statistical models, we can deduce patterns and make inferences about large data populations.
  • They offer predictions based on sampled data.
  • Statistical models can identify and label data as expected or unusual.
In the exercise, the mean and standard deviation are employed to construct a normal distribution model. It helps us identify what is considered a typical or atypical weight for this population of steers. Essentially, statistical modeling allows us to make educated judgments from data, enhancing decision-making processes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

People with \(z\) -scores above \(2.5\) on an IQ test are sometimes classified as geniuses. If IQ scores have a mean of 100 and a standard deviation of 16 points, what IQ score do you need to be considered a genius?

The mean score on the Stats exam was 75 points with a standard deviation of 5 points, and Gregor's z-score was \(-2\). How many points did he score?

Some IQ tests are standardized to a Normal model, with a mean of 100 and a standard deviation of \(16 .\) a) Draw the model for these IQ scores. Clearly label it, showing what the \(68-95-99.7\) Rule predicts. b) In what interval would you expect the central \(95 \%\) of IQ scores to be found? c) About what percent of people should have IQ scores above \(116 ?\) d) About what percent of people should have IQ scores between 68 and 84 ? e) About what percent of people should have IQ scores above \(132 ?\)

A popular band on tour played a series of concerts in large venues. They always drew a large crowd, averaging 21,359 fans. While the band did not announce (and probably never calculated) the standard deviation, which of these values do you think is most likely to be correct: \(20,200,2000\), or 20,000 fans? Explain your choice.

Here are the summary statistics for the weekly payroll of a small company: lowest salary \(=\$ 300\), mean salary \(=\$ 700\), median \(=\$ 500\), range \(=\$ 1200, \mathrm{IQR}=\) \(\$ 600\), first quartile \(=\$ 350\), standard deviation \(=\$ 400\). a) Do you think the distribution of salaries is symmetric, skewed to the left, or skewed to the right? Explain why. b) Between what two values are the middle \(50 \%\) of the salaries found? c) Suppose business has been good and the company gives every employee a \(\$ 50\) raise. Tell the new value of each of the summary statistics. d) Instead, suppose the company gives each employee a \(10 \%\) raise. Tell the new value of each of the summary statistics.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free