Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Only \(4 \%\) of people have Type AB blood. a) On average, how many donors must be checked to find someone with Type \(\mathrm{AB}\) blood? b) What's the probability that there is a Type \(\mathrm{AB}\) donor among the first 5 people checked? c) What's the probability that the first Type \(\mathrm{AB}\) donor will be found among the first 6 people? d) What's the probability that we won't find a Type \(\mathrm{AB}\) donor before the 10 th person?

Short Answer

Expert verified
a) 25 donors. b) 18.5%. c) 21.77%. d) 66.48%.

Step by step solution

01

Determine the Probability of a Type AB Donor

The probability of a donor having Type AB blood is given as \( p = 0.04 \). This means that \( 4\% \) of the population is expected to have Type AB blood.
02

Calculate the Average Number of Donors Checked (Part a)

The average number of donors that need to be checked to find someone with Type AB blood can be modeled using the concept of 'expected value'. The expected number of trials to get the first success in a geometric distribution is given by \( \frac{1}{p} \). Thus, we calculate \( \frac{1}{0.04} = 25 \). On average, 25 donors must be checked.
03

Calculate the Probability Among First 5 (Part b)

To find the probability that there is at least one Type AB donor in the first 5 donors, we use the complement rule. First, find the probability that none of the first 5 donors have Type AB blood: \( (1 - p)^5 = 0.96^5 \). Thus, the probability of at least one is \( 1 - 0.96^5 \). This calculates to about \( 0.185 \) or \( 18.5\% \).
04

Determine Probability of First 6 Trials (Part c)

The probability that the first Type AB donor is found within the first 6 donors is \( 1 - (1 - p)^6 = 1 - 0.96^6 \), which is about \( 0.2177 \) or \( 21.77\% \).
05

Calculate Probability No AB until 10th (Part d)

The probability that we do not find a Type AB donor before the 10th person means all first 9 donors do not have Type AB blood. This is \( (1-p)^9 = 0.96^9 \), which calculates to approximately \( 0.6648 \) or \( 66.48\% \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory is a mathematical framework that helps us understand randomness and uncertainty in various situations. It provides the tools to quantify the likelihood of different outcomes. Using probability, we can make informed guesses about the occurrence of events.

For instance, if you know that the probability of a donor having Type AB blood is 4%, you can predict how often this blood type will appear in a group of donors. In probability theory, these chances are usually represented by the symbol \( p \).

In our exercise, \( p = 0.04 \), indicating a 4% chance. Probability is essential for calculating the likelihood of events, such as finding a Type AB blood donor among a group of potential donors.
  • Probabilities range from 0 to 1.
  • A probability of 1 means an event is certain to happen.
  • A probability of 0 means an event is impossible.
Understanding the basics of probability can aid us in various real-world scenarios, including making decisions under uncertainty.
Expected Value
The expected value is a key concept in probability and statistics, providing a measure of the center of a probability distribution. In simpler terms, it's like an average outcome you can expect from a random event.

In the context of our blood donor example, if we want to know how many donors we need to check on average to find someone with Type AB blood, we calculate the expected value. When dealing with a geometric distribution, which models the number of trials until the first success, the formula is \( \frac{1}{p} \).

For this exercise, with \( p = 0.04 \), the expected number of donors is \( \frac{1}{0.04} = 25 \). This means that on average, 25 donors need to be checked to find someone with Type AB blood.
  • The expected value helps predict long-term average outcomes.
  • It simplifies the decision-making process in uncertain situations.
Using the expected value can give us a clear picture of what to expect in repeated or similar situations.
Complement Rule
The complement rule is a handy tool in probability, especially when it's easier to calculate the likelihood of an event not happening rather than happening directly. The rule states that the probability of an event occurring is \( 1 \) minus the probability of it not occurring.

Applying this rule is crucial in problems like ours. To find the probability of at least one Type AB donor among the first 5 people checked, we first calculate the probability that none of them has Type AB blood. This is given by \( (1-p)^5 = 0.96^5 \).

Then using the complement rule, we find \( 1 - (1-p)^5 = 1 - 0.96^5 \), which equates to approximately 18.5%. This gives us the likelihood of our desired scenario happening.
  • The complement rule simplifies complex probability calculations.
  • It is particularly useful when dealing with multiple trials or events.
  • The sum of the probability of an event and its complement equals 1.
The complement rule is an essential technique for tackling probability questions efficiently and correctly.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Police estimate that \(80 \%\) of drivers now wear their seatbelts. They set up a safety roadblock, stopping cars to check for seatbelt use. a) How many cars do they expect to stop before finding a driver whose seatbelt is not buckled? b) What's the probability that the first unbelted driver is in the 6 th car stopped? c) What's the probability that the first 10 drivers are all wearing their seatbelts? d) If they stop 30 cars during the first hour, find the mean and standard deviation of the number of drivers expected to be wearing seatbelts. e) If they stop 120 cars during this safety check, what's the probability they find at least 20 drivers not wearing their seatbelts?

An Olympic archer is able to hit the bull's-eye \(80 \%\) of the time. Assume each shot is independent of the others. If she shoots 6 arrows, what's the probability of each of the following results? a) Her first bull's-eye comes on the third arrow. b) She misses the bull's-eye at least once. c) Her first bull's-eye comes on the fourth or fifth arrow. d) She gets exactly 4 bull's-eyes. e) She gets at least 4 bull's-eyes. f) She gets at most 4 bull's-eyes.

Do these situations involve Bernoulli trials? Explain. a) We roll 50 dice to find the distribution of the number of spots on the faces. b) How likely is it that in a group of 120 the majority may have Type A blood, given that Type A is found in \(43 \%\) of the population? c) We deal 7 cards from a deck and get all hearts. How likely is that? d) We wish to predict the outcome of a vote on the school budget, and poll 500 of the 3000 likely voters to see how many favor the proposed budget. e) A company realizes that about \(10 \%\) of its packages are not being sealed properly. In a case of 24, is it likely that more than 3 are unsealed?

At a certain college, \(6 \%\) of all students come from outside the United States. Incoming students there are assigned at random to freshman dorms, where students live in residential clusters of 40 freshmen sharing a common lounge area. How many international students would you expect to find in a typical cluster? With what standard deviation?

An airline, believing that \(5 \%\) of passengers fail to show up for flights, overbooks (sells more tickets than there are seats). Suppose a plane will hold 265 passengers, and the airline sells 275 tickets. What's the probability the airline will not have enough seats, so someone gets bumped?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free