Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Day trading. An option to buy a stock is priced at \(\$ 200\). If the stock closes above 30 on May 15 , the option will be worth \(\$ 1000\). If it closes below 20 , the option will be worth nothing, and if it closes between 20 and 30 (inclusively), the option will be worth \(\$ 200\), A trader thinks there is a \(50 \%\) chance that the stock will close in the \(20-30\) range, a \(20 \%\) chance that it will close above 30 , and a \(30 \%\) chance that it will fall below 20 on May 15 .a) Should she buy the stock option? b) How much does she expect to gain? c) What is the standard deviation of her gain?

Short Answer

Expert verified
a) Yes, buy it for an expected gain. b) Expected gain is $100. c) Standard deviation is approximately $284.6.

Step by step solution

01

Calculate Expected Gain

To determine whether the trader should buy the option, calculate the expected gain. Use the formula for expected value:\[ E(X) = \sum (X_i \cdot P_i) \]where \(X_i\) is the gain in each outcome and \(P_i\) is the probability of each outcome. The gain for each scenario is:- If the stock closes above 30: Gain is \\(1000 - \\)200 = \\(800.- If the stock closes between 20 and 30: Gain is \\)200 - \\(200 = \\)0.- If the stock closes below 20: Gain is \\(0 - \\)200 = -\$200.Plug in these values:\[ E(X) = (800 \times 0.20) + (0 \times 0.50) + (-200 \times 0.30) \]\[ E(X) = 160 + 0 - 60 = 100 \].
02

Interpret Expected Gain

The expected gain calculated in Step 1 is \\(100. This means that, on average, the trader gains \\)100 by buying the option. Therefore, it is financially beneficial for her to purchase the option, assuming she repeats situations like this many times.
03

Calculate Standard Deviation

The standard deviation measures the variation of the outcomes. Use the formula for standard deviation:\[ SD(X) = \sqrt{\sum ((X_i - E(X))^2 \cdot P_i)} \]With \(E(X) = 100\), the calculations for each outcome are:- For closing above 30:\( (800 - 100)^2 \times 0.20 = 49000 \).- For closing between 20 and 30:\( (0 - 100)^2 \times 0.50 = 5000 \).- For closing below 20:\( (-200 - 100)^2 \times 0.30 = 27000 \).Adding these:\[ SD(X) = \sqrt{49000 + 5000 + 27000} = \sqrt{81000} \approx 284.6 \].
04

Final Step: Conclusion

With an expected gain of \\(100 and a standard deviation of approximately \\)284.6, the trader should recognize both the potential for an average profit and the associated risk. The decision to buy would depend on her risk preference, given that the gain is positive.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Deviation
Standard deviation is a way to measure how much variation or spread there is from the expected value in different scenarios. In the context of stock options, it helps understand the level of risk involved.

When calculating the standard deviation for a stock option, you consider the difference between each possible outcome and the expected gain. You then factor in how likely each outcome is. This can be calculated using the formula:
  • \[ SD(X) = \sqrt{\sum ((X_i - E(X))^2 \cdot P_i)} \]
Here, \(X_i\) is each individual outcome, \(E(X)\) is the expected gain, and \(P_i\) is the probability of each outcome.

In our example, the calculated standard deviation was approximately 284.6, indicating a notable variation in possible profits and losses. This high figure suggests that while there is a chance for substantial profit, there's also a risk of significant loss. So, while an option might have a good expected value, it's crucial to weigh that against its standard deviation to understand your risk.
Probability
Probability is a measure of how likely an event is to occur and is expressed as a percentage or a fraction. When calculating expected values in scenarios like stock options, probability helps determine the weight of each possible outcome.

To find the expected gain from buying a stock option, you take each potential gain or loss and multiply it by the probability that particular outcome will occur. Consider this simplified example:
  • If stock closes above 30 with 20% probability, the outcome is a gain of \(800.
  • If stock closes between 20 and 30 with 50% probability, the gain is \)0.
  • If stock closes below 20 with a 30% probability, it results in a loss of \(200.
Combining these probabilities with the corresponding outcomes gives the expected gain:\[ E(X) = (800 \times 0.20) + (0 \times 0.50) + (-200 \times 0.30) = 100 \].

This means that, on average, if these trades were repeated many times, the trader could expect to make \)100 per transaction.
Stock Options
Stock options give investors the right, but not the obligation, to buy or sell a stock at a specified price within a particular time frame. Options can be complex, as their value is influenced by multiple factors including the stock's current price, expected future price movements, and time until expiration.

When deciding whether to purchase a stock option, an investor will consider factors such as expected value and risk indicated by standard deviation. The potential for financial reward is evident when the option's increase in value exceeds its purchase price and associated fees. However, if the stock performs contrary to expectations, the investor may face losses.
  • An option to buy (call option) is profitable if the stock's market price exceeds the option's strike price after accounting for the cost of the option itself.
  • Conversely, an option becomes worthless if the stock price moves unfavorably past the expiration date.
Thus, a trader must carefully analyze both the risk and potential gain associated with the purchase, examining probabilities and the variation of potential outcomes, as seen from the standard deviation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Tickets. A delivery company's trucks occasionally get parking tickets, and based on past experience, the company plans that the trucks will average \(1.3\) tickets a month, with a standard deviation of \(0.7\) tickets. a) If they have 18 trucks, what are the mean and standard deviation of the total number of parking tickets the company will have to pay this month? b) What assumption did you make in answering?

Fire! An insurance company estimates that it should make an annual profit of \(\$ 150\) on each homeowner's policy written, with a standard deviation of \(\$ 6000\). a) Why is the standard deviation so large? b) If it writes only two of these policies, what are the mean and standard deviation of the annual profit? c) If it writes 10,000 of these policies, what are the mean and standard deviation of the annual profit? d) Is the company likely to be profitable? Explain. e) What assumptions underlie your analysis? Can you think of circumstances under which those assumptions might be violated? Explain.

Farmers' market. A farmer has \(100 \mathrm{lb}\) of apples and \(50 \mathrm{lb}\) of potatoes for sale. The market price for apples (per pound) each day is a random variable with a mean of \(0.5\) dollars and a standard deviation of \(0.2\) dollars. Similarly, for a pound of potatoes, the mean price is \(0.3\) dollars and the standard deviation is \(0.1\) dollars. It also costs him 2 dollars to bring all the apples and potatoes to the market. The market is busy with eager shoppers, so we can assume that he'll be able to sell all of each type of produce at that day's price. a) Define your random variables, and use them to express the farmer's net income. b) Find the mean. c) Find the standard deviation of the net income. d) Do you need to make any assumptions in calculating the mean? How about the standard deviation?

You bet! You roll a die. If it comes up a 6 , you win \(\$ 100\). If not, you get to roll again. If you get a 6 the second time, you win \(\$ 50\). If not, you lose. a) Create a probability model for the amount you win. b) Find the expected amount you'll win. c) What would you be willing to pay to play this game?

Racehorse. A man buys a racehorse for \(\$ 20,000\) and enters it in two races. He plans to sell the horse afterward, hoping to make a profit. If the horse wins both races, its value will jump to \(\$ 100,000\). If it wins one of the races, it will be worth \(\$ 50,000\). If it loses both races, it will be worth only \(\$ 10,000\). The man believes there's a \(20 \%\) chance that the horse will win the first race and a \(30 \%\) chance it will win the second one. Assuming that the two races are independent events, find the man's expected profit.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free