Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The family. Many couples want to have both a boy and a girl. If they decide to continue to have children until they have one child of each sex, what would the average family size be? Assume that boys and girls are equally likely.

Short Answer

Expert verified
The average family size would be 3 children.

Step by step solution

01

Understanding the Problem

We need to calculate the average number of children a couple would have if they continue having children until they have at least one boy and one girl. This can be modeled as a probability problem where each child's gender is independent and equally likely.
02

Modeling the Situation

For this scenario, we'll consider a sequence of "trials" where each trial represents the birth of a child. There are precisely two outcomes: a boy (B) or a girl (G), each with probability 0.5. The process stops as soon as we have one boy and one girl.
03

Calculating Probabilities

The key to this problem is recognizing that the family can stop having children when they either have a series of boys followed by a girl or vice versa. An example sequence could be GBBG (2 boys and 2 girls), or BBGG (2 boys and 2 girls), and so forth.
04

Using Expected Value Formula

We need to find the expected value, or average, of the number of children needed. For this, compute the probabilities of all possible sequences that result in one of each gender, and weigh them by their length. Denote the expected number of trials (children) until a boy and girl are present as E.
05

Expectation Formula in Action

For any sequence that stops when a boy and a girl are present, consider the sequences B-G, G-B, BB-G, GG-B, BGB, GBG, etc. The probability of B-G or G-B is 0.5 * 0.5 = 0.25, with 2 children involved, thus their contribution to the expectation is 2 * 0.25 each. Sequences like BB-G and GG-B similarly involve more children but are less probable.
06

Solving the Expected Value Equation

Summing the infinite geometric series for expected value, considering all possibilities, it resolves to E = 1/0.5 = 2 for each gender; the total is E = 2 + 2 = 4. Thus, couples generally have around 4 children on average when aiming for at least one boy and one girl.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Expected Value
Expected value is a fundamental concept in probability theory, representing the average outcome if an experiment is repeated many times. In the context of our exercise, the expected value helps us determine the average family size when couples continue having children until they have both a boy and a girl.

To calculate the expected value, you consider all possible outcomes where parents stop having children: one boy and one girl. Each outcome has its own probability and number of children involved. You multiply each probability by the corresponding number of children and sum these products.

For instance, the sequences B-G or G-B both result in families with two children. Since the probability of having either is 0.25, both add up to 0.5 to the expected value. Longer sequences will add more children but occur less frequently, thus having a smaller impact.
  • This process helps account for scenarios that involve more than two children in the family.
  • Adding up all possible sequence probabilities gives the total expected number of children.
Understanding expected value in this problem highlights how probability theory can predict real-world scenarios.
Geometric Series
The geometric series plays a crucial role in solving our exercise by providing a method to sum infinitely many terms. In probability, this series often arises when dealing with events that repeat until a certain condition is met, such as continuing to have children until both a boy and a girl are born.

The general form of a geometric series is:\[S = a + ar + ar^2 + ar^3 + \ldots = \frac{a}{1-r}\]where \(a\) is the first term and \(r\) is the common ratio between terms. In our scenario, the geometric series allows us to calculate the expected number of trials (or births), capturing all possible ways families could achieve the desired boy-girl outcome.

Often in probability, \(r\) is a constant probability, such as 0.5 when each child being a boy or a girl is equally likely. The geometric series simplifies the process:
  • Helps handle sums over infinite sequences, common in statistical predictions.
  • Offers a compact way to compute probabilities and expected values across repeated trials.
This use of the geometric series consolidates the unpredictability of repeated child-gender outcomes into a manageable calculation.
Gender Prediction
Gender prediction in probability exercises refers to predicting outcomes where gender is an unknown, independent variable. In our exercise, we focused on determining the duration of childbearing until a couple has one child of each gender.

This exercise simplifies gender prediction to pure chance: equal odds for each birth being a boy or a girl. This assumption models a fair coin toss scenario, where each outcome (boy or girl) has a 50% probability.

By setting this initial probability of 0.5 for both outcomes, couples can statistically plan expectations around likely family sizes when aiming to have both gendered children using the expected value calculated:
  • Provides a framework to think about gender likelihoods as independent events.
  • Allows for clear probabilistic modeling of family planning scenarios.
Gender prediction, through probability theory, gives insights into managing real-life decisions around family and expectations, underlining the utility of mathematical predictions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Driving test. You are about to take the road test for your driver's license. You hear that only \(34 \%\) of candidates pass the test the first time, but the percentage rises to \(72 \%\) on subsequent retests. Estimate the average number of tests drivers take in order to get a license. Your simulation should use at least 20 runs.

Colorblind. By some estimates, about \(10 \%\) of all males have some color perception defect, most commonly redgreen colorblindness. How would you assign random numbers to conduct a simulation based on this statistic?

Basketball strategy. Late in a basketball game, the team that is behind often fouls someone in an attempt to get the ball back. Usually the opposing player will get to shoot foul shots "one and one," meaning he gets a shot, and then a second shot only if he makes the first one. Suppose the opposing player has made \(72 \%\) of his foul shots this season. Estimate the number of points he will score in a one-and-one situation.

Free groceries. To attract shoppers, a supermarket runs a weekly contest that involves "scratch-off" cards. With each purchase, customers get a card with a black spot obscuring a message. When the spot is scratched away, most of the cards simply say, "Sorry-please try again." But during the week, 100 customers will get cards that make them eligible for a drawing for free groceries. Ten of the cards say they may be worth \(\$ 200,10\) others say \(\$ 100,20\) may be worth \(\$ 50\), and the rest could be worth \(\$ 20\). To register those cards, customers write their names on them and put them in a barrel at the front of the store. At the end of the week the store manager draws cards at random, awarding the lucky customers free groceries in the amount specified on their card. The drawings continue until the store has given away more than \(\$ 500\) of free groceries. Estimate the average number of winners each week.

A bigger family. Suppose a couple will continue having children until they have at least two children of each sex (two boys and two girls). How many children might they expect to have?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free