Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

How well does a student's Verbal SAT score (on an 800 -point scale) predict future college grade point average (on a four-point scale)? Computer output for this regression analysis is shown, using the data in StudentSurvey: The regression equation is \(\mathrm{GPA}=2.03+0.00189\) VerbalSAT Analysis of Variance \(\begin{array}{lrrrrr}\text { Source } & \text { DF } & \text { SS } & \text { MS } & \text { F } & \text { P } \\ \text { Regression } & 1 & 6.8029 & 6.8029 & 48.84 & 0.000 \\ \text { Residual Error } & 343 & 47.7760 & 0.1393 & & \\ \text { Total } & 344 & 54.5788 & & & \end{array}\) (a) What is the predicted grade point average of a student who receives a 550 on the Verbal SAT exam? (b) Use the information in the ANOVA table to determine the number of students included in the dataset. (c) Use the information in the ANOVA table to compute and interpret \(R^{2}\). (d) Is the linear model effective at predicting grade point average? Use information from the computer output and state the conclusion in context.

Short Answer

Expert verified
a) The predicted GPA of a student who received a 550 on the Verbal SAT would be 3.0695. b) The dataset included 345 students. c) The \(R^{2}\) value is 0.1247, meaning about 12.47% of the GPA variance can be explained by SAT scores. d) The model is statistically significant, evidenced by the low P-value and high F-value; however, the \(R^{2}\) value suggests the model may not greatly predict GPA accurately using only SAT scores.

Step by step solution

01

Predict the GPA

Substitute the `Verbal SAT` value of `550` into the regression formula \(\mathrm{GPA}=2.03+0.00189\) VerbalSAT: the grade point average (GPA) is \(2.03+0.00189*550\).
02

Determine the number of students

The residual degrees of freedom (DF) is the number of data points minus 2 (one for the regression and one for the constant term). The ANOVA Table shows residual DF as `343`, so the number of students in the dataset is `343+2=345`.
03

Calculate and interpret \(R^{2}\)

\(\mathrm{R^{2}} = \frac{\mathrm{SS Regression}}{\mathrm{Total SS}} = \frac{6.8029}{54.5788}\). \(R^{2}\) represents the proportion of the variance for the dependent variable (GPA) that's explained by the independent variable (Verbal SAT). A higher \(R^{2}\) indicates a stronger relation between GPA and SAT scores.
04

Evaluate the model's effectiveness

The model's effectiveness can be evaluated based on the F value, the P-value, and the \(R^{2}\) value. A large F value (48.84), and a very small P-value (0.000) suggest that the regression model is statistically significant. However, while the \(R^{2}\) value indicates a certain degree of correlation, further evaluations need to be made to determine how precisely the SAT scores can predict GPA.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

SAT Score Prediction
When it comes to understanding how well a standardized test score like the SAT can predict a student's future academic performance, regression analysis is a valuable tool. In our exercise, the analysis aims to predict college grade point average (GPA) based on a student's Verbal SAT scores. A regression equation, such as \( \text{GPA} = 2.03 + 0.00189 \times \text{VerbalSAT} \), represents the relationship, with the coefficients indicating how much GPA is expected to increase with each point increase in Verbal SAT scores.

To use the equation for prediction, you simply substitute the specific SAT score into the equation. For example, with a Verbal SAT score of 550, the predicted GPA would be calculated as \( 2.03 + 0.00189 \times 550 \). This equates to a GPA prediction based on the provided regression model. Remember that this model assumes a linear relationship between SAT scores and GPA and does not account for other potential factors that might influence a student's GPA.
Grade Point Average (GPA)
Understanding GPA is essential when discussing academic performance. The Grade Point Average is a standardized method of assessing a student's academic achievement. It is often on a four-point scale, where 4.0 represents an 'A' average. In the context of our regression analysis exercise, GPA serves as the dependent variable, meaning it's the outcome we're trying to predict based on the independent variable (Verbal SAT scores).

When interpreting the data from an educational perspective, it's important to note that while the SAT score is a significant predictor, it's only one of many factors that can contribute to a student's GPA. Other variables, like study habits, course difficulty, or extracurricular activities, are also critical but are not included in the regression model.
ANOVA Table
An Analysis of Variance (ANOVA) table is a fundamental tool in statistics used to analyze the differences among group means in a sample. In the realm of regression, the ANOVA table breaks down the variance in the dependent variable into components attributable to the model (regression) and the residual variance (error).

This breakdown includes degrees of freedom (DF), sum of squares (SS), mean square (MS), the F statistic (F), and the significance level (P). In simple terms, the ANOVA table helps us determine how well our model explains the variation in the data. If the P-value is sufficiently low (commonly less than 0.05), we can reject the null hypothesis that the regression coefficient is zero, suggesting the model has statistical significance.
R-Squared Interpretation
The \( R^2 \) value, or coefficient of determination, is a statistical measure of how close the data are to the fitted regression line. It is the proportion of the variance in the dependent variable that is predictable from the independent variable(s).

In the given exercise, we calculate \( R^2 \) by dividing the regression SS by the total SS. A higher \( R^2 \) usually indicates a better fit for the model to the data. However, it's essential to understand that while it tells us the proportion of variance explained by the model, it does not tell us about the accuracy of the predictions or whether the model is appropriate for the data. For instance, a high \( R^2 \) value in the context of GPA prediction might look promising, but we must also consider the practical significance and the real-world applicability when advising students or predicting academic outcomes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Exercises 9.66 and 9.67 refer to the regression line (given in Exercise 9.46 ): Cognition \(=102.3-3.34 \cdot\) Years using years playing football to predict the score on a cognition test. In each exercise, (a) Find the predicted cognition score for that case. (b) Two intervals are shown: one is a \(95 \%\) confidence interval for the mean response and the other is a \(95 \%\) prediction interval for the response. Which is which? A person who has played football for 8 years. \(\begin{array}{ll}\text { Interval I: }(22.7,128.5) & \text { Interval II: }(63.4,87.8)\end{array}\)

Life Expectancy In Exercise 9.27 on page 607 , we consider a regression equation to predict life expectancy from percent of government expenditure on health care, using data for a sample of 50 countries in SampCountries. Using technology and this dataset, find and interpret a \(95 \%\) prediction interval for each of the following situations: (a) A country which puts only \(3 \%\) of its expenditure into health care. (b) A country which puts \(10 \%\) of its expenditure into health care. (c) A country which puts \(50 \%\) of its expenditure into health care. (d) Calculate the widths of the intervals from (a), (b), and (c). What do you notice about these widths? (Note that for this sample, government expenditures on health care go from a minimum of \(4.0 \%\) to a maximum of \(20.89 \%\), with a mean of \(12.31 \% .)\)

FIBER IN CEREALS AS A PREDICTOR OF CALORIES In Example 9.10 on page \(592,\) we look at a model to predict the number of calories in a cup of breakfast cereal using the number of grams of sugars. In Exercises 9.64 and 9.65 , we give computer output with two regression intervals and information about a specific amount of sugar. Interpret each of the intervals in the context of this data situation. (a) The \(95 \%\) confidence interval for the mean response (b) The \(95 \%\) prediction interval for the response The intervals given are for cereals with 16 grams of sugars: Sugars 95 \(\mathrm{P}\) \(\begin{array}{rrr}\text { rs Fit } & \text { SE Fit } \\\ 6 & 157.88 & 7.10 & \text { (143.3 }\end{array}\) \(95 \% \mathrm{Cl}\) 35,172.42) \(9 \%\) \(\begin{array}{lllll}16 & 15788 & 7.10 & (143.35,172.42) & (101.46\end{array}\) 214.31)

In Exercises 9.62 and 9.63 , we give computer output with two regression intervals and information about the percent of calories eaten during the day. Interpret each of the intervals in the context of this data situation. (a) The \(95 \%\) confidence interval for the mean response (b) The \(95 \%\) prediction interval for the response The intervals given are for mice that eat \(50 \%\) of their calories during the day: \(\begin{array}{rrrrr}\text { DayPct } & \text { Fit } & \text { SE Fit } & 95 \% \mathrm{Cl} & 95 \% \mathrm{PI} \\ 50.0 & 7.476 & 0.457 & (6.535,8.417) & (2.786,12.166)\end{array}\)

Use the computer output (from different computer packages) to estimate the intercept \(\beta_{0},\) the slope \(\beta_{1},\) and to give the equation for the least squares line for the sample. Assume the response variable is \(Y\) in each case. $$ \begin{array}{lrrrr} \text { Coefficients: } & \text { Estimate } & \text { Std.Error } & \mathrm{t} \text { value } & \operatorname{Pr}(>|\mathrm{t}|) \\ \text { (Intercept) } & 77.44 & 14.43 & 5.37 & 0.000 \\ \text { Score } & -15.904 & 5.721 & -2.78 & 0.012 \end{array} $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free