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Use this information to fill in all values in an analysis of variance for regression table as shown. $$ \begin{array}{|l|l|l|l|l|l|} \hline \text { Source } & \text { df } & \text { SS } & \text { MS } & \text { F-statistic } & \text { p-value } \\ \hline \text { Model } & & & & & \\ \hline \text { Error } & & & & & \\ \hline \text { Total } & & & & & \\ \hline \end{array} $$ SSModel \(=8.5\) with SSError \(=247.2\) and a sample size of \(n=25\).

Short Answer

Expert verified
The complete ANOVA table would be as follows: Model df=1, SS=8.5, MS=8.5, F-statistic calculated as per step 4, and p-value output from software; Error df=23, SS=247.2, MS calculated as per step 3; Total df=24, SS calculated as per step 2. Note: The F-statistic and p-value require additional computation/interpretation.

Step by step solution

01

Fill SS and df fields

Let's start by filling out the SS for Model and Error, and filling out the df using the sample size. In this instance, SSModel is given as \(8.5\) and SSError as \(247.2\). Degrees of freedom for Model (dfModel) is always 1 in simple regression, and degrees of freedom for Error (dfError) is calculated as \(n - 2\), where n is the sample size (25 in this case).
02

Calculate SSTotal and dfTotal

Next we'll calculate SSTotal and dfTotal. Sum of Squares Total (SSTotal) is the sum of SSModel and SSError, and Degrees of Freedom Total (dfTotal) is the sum of dfModel and dfError.
03

Calculate MSModel and MSError

Mean Square (MS) is calculated as SS divided by df. So, we can calculate MSModel as \(SSModel/dfModel\), and MSError as \(SSError/dfError\).
04

Calculate F-statistic

Now we'll compute F-statistic. In Analysis of Variance, F-statistic is calculated as \(MSModel/MSError\).
05

Determine P-value

P-value can be found from the F-distribution table with dfModel and dfError, given F-statistic. Alternatively, it can be computed with statistical software. This step involves interpretation and can't be computed analytically.

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Most popular questions from this chapter

The dataset OttawaSenators contains information on the number of points and the number of penalty minutes for 24 Ottawa Senators NHL hockey players. Computer output is shown for predicting the number of points from the number of penalty minutes: The regression equation is Points \(=29.53-0.113\) PenMins \(\begin{array}{lrrrr}\text { Predictor } & \text { Coef } & \text { SE Coef } & \text { T } & \text { P } \\ \text { Constant } & 29.53 & 7.06 & 4.18 & 0.000 \\ \text { PenMins } & -0.113 & 0.163 & -0.70 & 0.494\end{array}\) \(\mathrm{S}=21.2985 \quad \mathrm{R}-\mathrm{Sq}=2.15 \% \quad \mathrm{R}-\mathrm{Sq}(\mathrm{adj})=0.00 \%\) Analysis of Variance Source Regression Residual Error Total 2 \(\begin{array}{rrrrr}\text { DF } & \text { SS } & \text { MS } & \text { F } & \text { P } \\ 1 & 219.5 & 219.5 & 0.48 & 0.494 \\ 22 & 9979.8 & 453.6 & & \\ 23 & 10199.3 & & & \end{array}\) (a) Write down the equation of the least squares line and use it to predict the number of points for a player with 20 penalty minutes and for a player with 150 penalty minutes. (b) Interpret the slope of the regression equation in context. (c) Give the hypotheses, t-statistic, p-value, and conclusion of the t-test of the slope to determine whether penalty minutes is an effective predictor of number of points. (d) Give the hypotheses, F-statistic, p-value, and conclusion of the ANOVA test to determine whether the regression model is effective at predicting number of points. (e) How do the two p-values from parts (c) and (d) compare? (f) Interpret \(R^{2}\) for this model.

Golf Scores In a professional golf tournament the players participate in four rounds of golf and the player with the lowest score after all four rounds is the champion. How well does a player's performance in the first round of the tournament predict the final score? Table 9.6 shows the first round score and final score for a random sample of 20 golfers who made the cut in a recent Masters tournament. The data are also stored in MastersGolf. Computer output for a regression model to predict the final score from the first-round score is shown. Use values from this output to calculate and interpret the following. Show your work. (a) Find a \(95 \%\) interval to predict the average final score of all golfers whoshoot a 0 on the first round at the Masters. (b) Find a \(95 \%\) interval to predict the final score of a golfer who shoots a -5 in the first round at the Masters. (c) Find a \(95 \%\) interval to predict the average final score of all golfers who shoot a +3 in the first round at the Masters. The regression equation is Final \(=0.162+1.48\) First \(\begin{array}{lrrrr}\text { Predictor } & \text { Coef } & \text { SE Coef } & \text { T } & \text { P } \\ \text { Constant } & 0.1617 & 0.8173 & 0.20 & 0.845 \\ \text { First } & 1.4758 & 0.2618 & 5.64 & 0.000 \\ S=3.59805 & R-S q=63.8 \% & \text { R-Sq }(a d j) & =61.8 \%\end{array}\) Analysis of Variance Source Regression Residual Error Total \(\begin{array}{rrrrr}\text { DF } & \text { SS } & \text { MS } & \text { F } & \text { P } \\ 1 & 411.52 & 411.52 & 31.79 & 0.000 \\ 18 & 233.03 & 12.95 & & \\ 19 & 644.55 & & & \end{array}\)

Teams in the National Football League (NFL) in the US play four pre-season games each year before the regular season starts. Do teams that do well in the pre-season tend to also do well in the regular season? We are interested in whether there is a positive linear association between the number of wins in the pre-season and the number of wins in the regular season for teams in the NFL. (a) What are the null and alternative hypotheses for this test? (b) The correlation between these two variables for the 32 NFL teams over the 10 year period from 2005 to 2014 is 0.067 . Use this sample (with \(n=320\) ) to calculate the appropriate test statistic and determine the p-value for the test. (c) State the conclusion in context, using a \(5 \%\) significance level. (d) When an NFL team goes undefeated in the pre-season, should the fans expect lots of wins in the regular season?

In Exercises 9.11 to \(9.14,\) test the correlation, as indicated. Show all details of the test. Test for a positive correlation; \(r=0.35 ; n=30\).

Exercise A .97 on page 189 , we introduce a study about mating activity of water striders. The dataset is available as WaterStriders and includes the variables FemalesHiding, which gives the proportion of time the female water striders were in hiding, and MatingActivity, which is a measure of mean mating activity with higher numbers meaning more mating. The study included 10 groups of water striders. (The study also included an examination of the effect of hyper-aggressive males and concludes that if a male wants mating success, he should not hang out with hyper-aggressive males.) Computer output for a model to predict mating activity based on the proportion of time females are in hiding is shown below, and a scatterplot of the data with the least squares line is shown in Figure 9.12 . The regression equation is MatingActivity \(=0.480-0.323\) FemalesHiding \(\begin{array}{lrrrr}\text { Predictor } & \text { Coef } & \text { SE Coef } & \text { T } & \text { P } \\ \text { Constant } & 0.48014 & 0.04213 & 11.40 & 0.000 \\ \text { FemalesHiding } & -0.3232 & 0.1260 & -2.56 & 0.033\end{array}\) \(\begin{array}{lll}S=0.101312 & \text { R-Sq }=45.1 \% & \text { R-Sq(adj) }=38.3 \%\end{array}\) Analysis of Variance \(\begin{array}{lrrrrr}\text { Source } & \text { DF } & \text { SS } & \text { MS } & \text { F } & \text { P } \\ \text { Regression } & 1 & 0.06749 & 0.06749 & 6.58 & 0.033 \\ \text { Residual Error } & 8 & 0.08211 & 0.01026 & & \\ \text { Total } & 9 & 0.14960 & & & \end{array}\) (a) While it is hard to tell with only \(n=10\) data points, determine whether we should have any serious concerns about the conditions for fitting a linear model to these data. (b) Write down the equation of the least squares line and use it to predict the mating activity of water striders in a group in which females spend \(50 \%\) of the time in hiding (FemalesHiding = 0.50) (c) Give the hypotheses, t-statistic, p-value, and conclusion of the t-test of the slope to determine whether time in hiding is an effective predictor of mating activity. (d) Give the hypotheses, F-statistic, p-value, and conclusion of the ANOVA test to determine whether the regression model is effective at predicting mating activity. (e) How do the two p-values from parts (c) and (d) compare? (f) Interpret \(R^{2}\) for this model.

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