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In Exercises 9.11 to \(9.14,\) test the correlation, as indicated. Show all details of the test. Test for a positive correlation; \(r=0.35 ; n=30\).

Short Answer

Expert verified
To conclude if there's a positive correlation, we need to compare the calculated t-value (using the provided correlation coefficient and sample size) to the critical t-value for a one-tailed test at a significance level of 0.05. We reject the null hypothesis of no positive correlation if the calculated t-value exceeds the critical t-value, indicating a significant positive correlation. Otherwise, we fail to reject the null hypothesis, signifying no significant positive correlation.

Step by step solution

01

State the Hypotheses

Firstly, we identify our null and alternative hypotheses. The null hypothesis ( \( H_0 \) ) posits no positive correlation, so it would state that the correlation coefficient is equal to 0. The alternative hypothesis ( \( H_1 \) ) claims a positive correlation, therefore, it would state that the correlation coefficient is greater than 0. Expressed mathematically, this would be: \( H_0: r = 0 \) and \( H_1: r > 0 \).
02

Calculate the Test Statistic

We use the given correlation coefficient ( \( r = 0.35 \) ) and sample size ( \( n = 30 \) ), along with the equation for the t-test for correlation coefficients to calculate our test statistic. This equation is \( t = r \sqrt{\frac{n-2}{1-r^2}} \). Substituting our given values into this equation yields \( t = 0.35 \sqrt{\frac{30-2}{1-0.35^2}} \).
03

Compare to Critical Value

Next, we find the critical t-value for a one-tailed test (since we are only interested in determining whether the correlation is greater than 0) at a significance level of 0.05 with \( n-2 \) degrees of freedom. Using a t-table, we find the one-tailed critical t-value to be approximately 1.699. Then, we compare our calculated t-value to this critical value.
04

State the Conclusion

If our calculated t-value is greater than the critical t-value, we reject the null hypothesis in favor of the alternative hypothesis. This would indicate a significant positive correlation. If our calculated t-value is less than or equal to the critical t-value, we do not reject the null hypothesis. This would indicate that the correlation is not significantly different from 0.

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Test the correlation, as indicated. Show all details of the test. Test for a negative correlation; \(r=-0.41\); \(n=18\).

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