Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

What sample size is needed to give the desired margin of error in estimating a population proportion with the indicated level of confidence? A margin of error within \(\pm 5 \%\) with \(95 \%\) confidence.

Short Answer

Expert verified
After computing the above equation, one finds that the minimum sample size needed to estimate the population proportion within the ±5% margin of error with 95% confidence is approximately 385.

Step by step solution

01

Identify Margin of Error

The margin of error presented is ±5%, which when converted to a decimal form is ±0.05.
02

Identify Confidence Level

The confidence level given is 95%. The Z-score of a 95% confidence level is 1.96.
03

Apply the Formula for Sample Size

The formula for determining the sample size needed for a given margin of error E and Z-score (Z) for a population proportion p, when we don't know the population standard deviation, is \(n = (Z^2 \cdot p \cdot ( 1-p )) / E^2\). However, since we don't know the population proportion p, we usually use the safe assumption of p=0.5 that maximizes the sample size, yielding \(n = (Z^2 \cdot 0.5 \cdot 0.5) / E^2\). Substituting the values into the sample size formula gives: \(n = (1.96^2 \cdot 0.5 \cdot 0.5) / 0.05^2\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Margin of Error
Understanding the margin of error is critical when analyzing the results of a survey or poll. It represents the span of values above and below the survey proportion, within which the true population proportion is estimated to lie. In simpler terms, the margin of error accounts for the uncertainties present in any form of statistical sampling. For instance, if the margin of error were to be ±5%, and your survey outcome indicated a 60% favorability rating, the true population favorability could be as low as 55% or as high as 65%.

In our example exercise, a margin of error of ±5% implies that the researcher is willing to accept a 5% potential discrepancy between the estimated proportion and the true value within the population. Lower margins of error require larger sample sizes, which makes the study potentially more accurate but also more resource-intensive. The margin of error is dependent on the sample size, the confidence level, and the variability within the population — in this case expressed by the population proportion.
Confidence Level
The confidence level signifies the degree of certainty we have that our sample accurately reflects the population. The most common confidence levels used in research are 90%, 95%, and 99%. A 95% confidence level, used in the exercise, means that if the survey or experiment were to be repeated multiple times, the calculated confidence interval would contain the true population parameter 95 out of 100 times.

In relation to the margin of error, the higher the confidence level you desire, the larger the sample size you'll need. This is because a higher confidence level increases the range of the confidence interval. The confidence level corresponds to a Z-score in the standard normal distribution — the number of standard deviations from the mean to capture the desired confidence interval. For a 95% confidence level, the Z-score is 1.96, which defines how far from the observed sample proportion we expect the true population proportion to fall, with the given level of confidence.
Population Proportion
The population proportion is a measure that represents the fraction of the population that possesses a certain characteristic or attribute. In surveying and research, we usually aim to estimate this proportion through sampling, due to the impracticality of surveying an entire population. The symbol 'p' denotes this value in the sample size formula.

When the true population proportion is unknown, which is often the case, a value of 0.5 (or 50%) is used to calculate the sample size, as this assumes maximum variability and therefore maximizes the required sample size. This is the most conservative estimate and ensures the sample size is large enough to account for an unknown level of variability within the population. In the case of our exercise, adopting 0.5 for the population proportion simplifies the sample size formula and ensures that our sample is representative enough for a reliable estimation of the true proportion with the given margin of error and confidence level.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

We examine the effect of different inputs on determining the sample size needed. Find the sample size needed to give a margin of error within ±3 with \(99 \%\) confidence. With \(95 \%\) confidence. With \(90 \%\) confidence. Assume that we use \(\tilde{\sigma}=30\) as our estimate of the standard deviation in each case. Comment on the relationship between the sample size and the confidence level desired.

A data collection method is described to investigate a difference in means. In each case, determine which data analysis method is more appropriate: paired data difference in means or difference in means with two separate groups. To study the effect of women's tears on men, levels of testosterone are measured in 50 men after they sniff women's tears and after they sniff a salt solution. The order of the two treatments was randomized and the study was double-blind.

Using Data 5.1 on page \(375,\) we find a significant difference in the proportion of fruit flies surviving after 13 days between those eating organic potatoes and those eating conventional (not organic) potatoes. ask you to conduct a hypothesis test using additional data from this study. \(^{40}\) In every case, we are testing $$\begin{array}{ll}H_{0}: & p_{o}=p_{c} \\\H_{a}: & p_{o}>p_{c}\end{array}$$ where \(p_{o}\) and \(p_{c}\) represent the proportion of fruit flies alive at the end of the given time frame of those eating organic food and those eating conventional food, respectively. Also, in every case, we have \(n_{1}=n_{2}=500 .\) Show all remaining details in the test, using a \(5 \%\) significance level. Effect of Organic Bananas after 15 Days After 15 days, 345 of the 500 fruit flies eating organic bananas are still alive, while 320 of the 500 eating conventional bananas are still alive.

Using Data 5.1 on page \(375,\) we find a significant difference in the proportion of fruit flies surviving after 13 days between those eating organic potatoes and those eating conventional (not organic) potatoes. Exercises 6.166 to 6.169 ask you to conduct a hypothesis test using additional data from this study. \(^{40}\) In every case, we are testing $$\begin{array}{ll}H_{0}: & p_{o}=p_{c} \\\H_{a}: & p_{o}>p_{c}\end{array}$$ where \(p_{o}\) and \(p_{c}\) represent the proportion of fruit flies alive at the end of the given time frame of those eating organic food and those eating conventional food, respectively. Also, in every case, we have \(n_{1}=n_{2}=500 .\) Show all remaining details in the test, using a \(5 \%\) significance level. Effect of Organic Raisins after 15 Days After 15 days, 320 of the 500 fruit flies eating organic raisins are still alive, while 300 of the 500 eating conventional raisins are still alive.

Is Gender Bias Influenced by Faculty Gender? Exercise 6.215 describes a study in which science faculty members are asked to recommend a salary for a lab manager applicant. All the faculty members received the same application, with half randomly given a male name and half randomly given a female name. In Exercise \(6.215,\) we see that the applications with female names received a significantly lower recommended salary. Does gender of the evaluator make a difference? In particular, considering only the 64 applications with female names, is the mean recommended salary different depending on the gender of the evaluating faculty member? The 32 male faculty gave a mean starting salary of \(\$ 27,111\) with a standard deviation of \(\$ 6948\) while the 32 female faculty gave a mean starting salary of \(\$ 25,000\) with a standard deviation of \(\$ 7966 .\) Show all details of the test.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free