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In Exercises 6.139 to \(6.142,\) use the normal distribution to find a confidence interval for a difference in proportions \(p_{1}-p_{2}\) given the relevant sample results. Give the best estimate for \(p_{1}-p_{2},\) the margin of error, and the confidence interval. Assume the results come from random samples. A 95\% confidence interval for \(p_{1}-p_{2}\) given counts of 240 yes out of 500 sampled for Group 1 and 450 ves out of 1000 sampled for Group \(2 .\)

Short Answer

Expert verified
After calculating proportions, difference in proportions, standard error, and margin of error, construct the confidence interval. Without actual calculations, it is not possible to provide specific numerical values. Please follow the step-by-step solution to get the numerical results.

Step by step solution

01

Calculate the Proportions

The first step is to calculate the proportions for each group. These proportions are computed as the number of 'yes' responses divided by the total number sampled for each group. For Group 1, this would be \(p_{1}=\frac{240}{500}=0.48\). For Group 2, this would be \(p_{2}=\frac{450}{1000}=0.45\).
02

Find the Difference in Proportions

Next, evaluate the difference in proportions. This difference, \(p_{1}-p_{2}=0.48-0.45=0.03\), represents the best estimate for the difference in proportions.
03

Calculate the Standard Error

The standard error for the difference in proportions can be calculated using the formula: \[ SE = \sqrt{\frac{p_{1}(1-p_{1})}{n_{1}} + \frac{p_{2}(1-p_{2})}{n_{2}}} \] Upon substitution, we get: \[ SE = \sqrt{\frac{0.48(1-0.48)}{500} + \frac{0.45(1-0.45)}{1000}} \] Solve the expression inside the square root to get the value of standard error.
04

Find the Margin of Error

Having found the standard error, you can now calculate the margin of error. A 95% confidence level corresponds to a z-value of 1.96 in the normal distribution table. Thus, Margin of Error = Z*SE. Substitute the values of Z and SE in this formula to get the margin of error.
05

Compute the Confidence Interval

Lastly, construct the confidence interval by adding and subtracting the margin of error from the best estimate. In other words, the confidence interval is (Best Estimate - Margin of Error, Best Estimate + Margin of Error). The resulting interval gives the range in which we can be 95% confident that the true population difference lies.

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Most popular questions from this chapter

Using Data 5.1 on page \(375,\) we find a significant difference in the proportion of fruit flies surviving after 13 days between those eating organic potatoes and those eating conventional (not organic) potatoes. ask you to conduct a hypothesis test using additional data from this study. \(^{40}\) In every case, we are testing $$\begin{array}{ll}H_{0}: & p_{o}=p_{c} \\\H_{a}: & p_{o}>p_{c}\end{array}$$ where \(p_{o}\) and \(p_{c}\) represent the proportion of fruit flies alive at the end of the given time frame of those eating organic food and those eating conventional food, respectively. Also, in every case, we have \(n_{1}=n_{2}=500 .\) Show all remaining details in the test, using a \(5 \%\) significance level. Effect of Organic Bananas after 15 Days After 15 days, 345 of the 500 fruit flies eating organic bananas are still alive, while 320 of the 500 eating conventional bananas are still alive.

Use a t-distribution and the given matched pair sample results to complete the test of the given hypotheses. Assume the results come from random samples, and if the sample sizes are small, assume the underlying distribution of the differences is relatively normal. Assume that differences are computed using \(d=x_{1}-x_{2}\). Test \(H_{0}: \mu_{1}=\mu_{2}\) vs \(H_{a}: \mu_{1}>\mu_{2}\) using the paired data in the following table: $$ \begin{array}{lllllllllll} \hline \text { Situation } & 1 & 125 & 156 & 132 & 175 & 153 & 148 & 180 & 135 & 168 & 157 \\ \text { Situation } & 2 & 120 & 145 & 142 & 150 & 160 & 148 & 160 & 142 & 162 & 150 \\ \hline \end{array} $$

Use the t-distribution and the given sample results to complete the test of the given hypotheses. Assume the results come from random samples, and if the sample sizes are small, assume the underlying distributions are relatively normal. Test \(H_{0}: \mu_{1}=\mu_{2}\) vs \(H_{a}: \mu_{1}>\mu_{2}\) using the sample results \(\bar{x}_{1}=56, s_{1}=8.2\) with \(n_{1}=30\) and \(\bar{x}_{2}=51, s_{2}=6.9\) with \(n_{2}=40\).

A data collection method is described to investigate a difference in means. In each case, determine which data analysis method is more appropriate: paired data difference in means or difference in means with two separate groups. To study the effect of sitting with a laptop computer on one's lap on scrotal temperature, 29 men have their scrotal temperature tested before and then after sitting with a laptop for one hour.

Quebec vs Texas Secession In Example 6.4 on page 408 we analyzed a poll of 800 Quebecers, in which \(28 \%\) thought that the province of Quebec should separate from Canada. Another poll of 500 Texans found that \(18 \%\) thought that the state of Texas should separate from the United States. \({ }^{38}\) (a) In the sample of 800 people, about how many Quebecers thought Quebec should separate from Canada? In the sample of 500 , how many Texans thought Texas should separate from the US? (b) In these two samples, what is the pooled proportion of Texans and Quebecers who want to separate? (c) Can we conclude that the two population proportions differ? Use a two- tailed test and interpret the result.

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