Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In Exercises 6.11 to 6.14, use the normal distribution to find a confidence interval for a proportion \(p\) given the relevant sample results. Give the best point estimate for \(p,\) the margin of error, and the confidence interval. Assume the results come from a random sample. A \(95 \%\) confidence interval for \(p\) given that \(\hat{p}=\) 0.38 and \(n=500\)

Short Answer

Expert verified
The best point estimate for \(p\) is 0.38, the margin of error is 0.0437 and the 95% confidence interval for \(p\) is [0.3363, 0.4237]

Step by step solution

01

Point Estimate

The best point estimate for the population proportion \(p\) is the sample proportion \(\hat{p}\). Therefore, the best point estimate for \(p\) is 0.38 in this case.
02

Calculate Standard Error

We calculate the standard error of the proportion (SEP) using the formula SEP = \(\sqrt{ \hat{p}(1-\hat{p}) / n}\) where \(n\) is the sample size, and \(\hat{p}\) is the sample proportion. Substituting the given values, SEP = \(\sqrt{0.38(1-0.38)/500} = 0.0223\)
03

Margin of Error

Next, we calculate the margin of error using the formula: Margin of Error = Z * SEP. For a 95% confidence interval, the z-score is 1.96 (from z-table). Hence, Margin of Error = 1.96 * 0.0223 = 0.0437
04

Confidence Interval

Finally, we calculate the confidence interval using the point estimate and the margin of error. The confidence interval = \(\hat{p}\pm\) Margin of Error. Hence, Confidence interval = [0.38 - 0.0437, 0.38 + 0.0437] = [0.3363, 0.4237]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
When we talk about the confidence interval for a proportion, we are often considering the normal distribution as the basis for our calculations. Normal distribution, also known as the Gaussian distribution, is a symmetric, bell-shaped distribution where most of the observations cluster around the central peak and the probabilities for values further away from the mean taper off equally in both directions.

It’s important to note that the normal distribution is used in the context of confidence intervals when certain conditions are met. Typically, these conditions require a sufficiently large sample size (usually a rule of thumb is n > 30) such that the sampling distribution of the proportion can be approximated as normal based on the Central Limit Theorem, regardless of the distribution of the population from which the sample was drawn.
Margin of Error
The margin of error is crucial to understanding the range within which we expect the population proportion to lie, given a certain level of confidence. It reflects how much we can expect our estimate to vary if we were to take many samples. A smaller margin of error indicates a more precise estimate.

The formula for the margin of error includes the standard error and a multiplier derived from the z-score: Margin of Error = Z * SEP. Essentially, it adjusts the width of the confidence interval. For a 95% confidence level, common in statistical analysis, the z-score is 1.96, representing the standard deviation limits on either side of a normal distribution curve that contains 95% of the data.
Standard Error of the Proportion
The standard error of the proportion (SEP) quantifies how much we would expect the sample proportion to vary from one random sample to another. It is a pivotal component in calculating the margin of error and, subsequently, the confidence interval.

The SEP is calculated using the formula \( SEP = \sqrt{ \frac{\hat{p}(1-\hat{p})}{n} } \) where \( \hat{p} \) is the sample proportion and \(n\) is the sample size. A key point to remember is that the SEP decreases as the sample size increases, indicating that larger samples give us more precise estimates of the population proportion.
Z-Score
The z-score is a statistical measure that describes a value's relationship to the mean of a group of values, measured in terms of standard deviations. In the context of confidence intervals, z-scores are used to determine the margin of error by indicating how many standard deviations away from the point estimate the interval extends.

For different confidence levels, there are corresponding z-scores: 1.96 for 95%, 2.58 for 99%, and so on. These scores are critical when working with the normal distribution, as they help us understand the spread and probability of the data within a given range in relation to the mean.
Point Estimate
A point estimate provides an actual value as an estimate of a population parameter based on sample data. When we calculate a confidence interval for a proportion, our point estimate is the sample proportion, often denoted as \( \hat{p} \).

The point estimate is the starting center of the confidence interval, and by itself, it does not convey information about the precision or reliability of the estimate; that's why we use it with the margin of error to construct the confidence interval. The interval thus signifies a range within which we believe the true population proportion may fall, with a certain level of confidence.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A survey of 1000 adults in the US conducted in March 2011 asked "Do you favor or oppose 'sin taxes' on soda and junk food?" The proportion in favor of taxing these foods was \(32 \% .10\) (a) Find a \(95 \%\) confidence interval for the proportion of US adults favoring taxes on soda and junk food. (b) What is the margin of error? (c) If we want a margin of error of only \(1 \%\) (with \(95 \%\) confidence \()\), what sample size is needed?

Find a \(95 \%\) confidence interval for the proportion two ways: using StatKey or other technology and percentiles from a bootstrap distribution, and using the normal distribution and the formula for standard error. Compare the results. Proportion of Reese's Pieces that are orange, using \(\hat{p}=0.48\) with \(n=150\)

In Exercises 6.203 and \(6.204,\) use Stat Key or other technology to generate a bootstrap distribution of sample differences in means and find the standard error for that distribution. Compare the result to the standard error given by the Central Limit Theorem, using the sample standard deviations as estimates of the population standard deviations. Difference in mean commuting time (in minutes) between commuters in Atlanta and commuters in St. Louis, using \(n_{1}=500, \bar{x}_{1}=29.11,\) and \(s_{1}=20.72\) for Atlanta and \(n_{2}=500, \bar{x}_{2}=21.97,\) and \(s_{2}=14.23\) for St. Louis

Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the proportion in a t-distribution above 2.1 if the samples have sizes \(n_{1}=12\) and \(n_{2}=12\).

In Exercises 6.150 and \(6.151,\) use StatKey or other technology to generate a bootstrap distribution of sample differences in proportions and find the standard error for that distribution. Compare the result to the value obtained using the formula for the standard error of a difference in proportions from this section. Sample A has a count of 90 successes with \(n=120\) and Sample \(\mathrm{B}\) has a count of 180 successes with \(n=300\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free