Who Exercises More: Males or Females? The dataset StudentSurvey has
information from males and females on the number of hours spent exercising in
a typical week. Computer output of descriptive statistics for the number of
hours spent exercising, broken down by gender, is given:
\(\begin{array}{l}\text { Descriptive Statistics: Exercise } \\ \text {
Variable } & \text { Gender } & \mathrm{N} & \text { Mean } & \text { StDev }
\\\ \text { Exercise } & \mathrm{F} & 168 & 8.110 & 5.199 \\ & \mathrm{M} &
193 & 9.876 & 6.069\end{array}\)
\(\begin{array}{rrrrr}\text { Minimum } & \text { Q1 } & \text { Median } &
\text { Q3 } & \text { Maximum } \\ 0.000 & 4.000 & 7.000 & 12.000 & 27.000
\\\ 0.000 & 5.000 & 10.000 & 14.000 & 40.000\end{array}\)
(a) How many females are in the dataset? How many males?
(b) In the sample, which group exercises more, on average? By how much?
(c) Use the summary statistics to compute a \(95 \%\) confidence interval for
the difference in mean number of hours spent exercising. Be sure to define any
parameters you are estimating.
(d) Compare the answer from part (c) to the confidence interval given in the
following computer output for the same data:
Two-sample \(\mathrm{T}\) for Exercise Gender N Mean StDev SE Mean
\(\begin{array}{lllll}\mathrm{F} & 168 & 8.11 & 5.20 & 0.40 \\ \mathrm{M} &
193 & 9.88 & 6.07 & 0.44\end{array}\)
Difference \(=\operatorname{mu}(F)-\operatorname{mu}(M)\)
Estimate for difference: -1.766 \(95 \%\) Cl for difference: (-2.932,-0.599)