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Match the four \(\mathrm{p}\) -values with the appropriate conclusion: (a) The evidence against the null hypothesis is significant, but only at the \(10 \%\) level. (b) The evidence against the null and in favor of the alternative is very strong. (c) There is not enough evidence to reject the null hypothesis, even at the \(10 \%\) level. (d) The result is significant at a \(5 \%\) level but not at a \(1 \%\) level. I. 0.0875 II. 0.5457 III. 0.0217 IV. \(\quad 0.00003\)

Short Answer

Expert verified
The appropriate conclusions matched with the given p-values are: (a) matches with II. 0.0875, (b) matches with IV. 0.00003, (c) matches with II. 0.5457 and (d) matches with III. 0.0217.

Step by step solution

01

Match to Statement (a)

In statement (a), the evidence is significant at the 10% level. This implies a p-value less than 0.10 but greater than 0.05 (so it's not significant at the 5% level). From the options given, the corresponding p-value is 0.0875. Hence, II. 0.0875 matches with (a).
02

Match to Statement (b)

In statement (b), the evidence against the null hypothesis is very strong. Such strong evidence will be associated with a very low p-value. The smallest p-value offered here is IV. 0.00003. Hence, IV. 0.00003 matches with (b).
03

Match to Statement (c)

In statement (c), there is not enough evidence to reject the null hypothesis even at the 10% level, meaning the p-value here should be greater than 0.10. The only option available that fits this criterion is II. 0.5457. Hence, II. 0.5457 matches with (c).
04

Match to Statement (d)

In statement (d), a significant result at a 5% level but not the 1% level implies that the p-value is less than 0.05 and greater than 0.01. Therefore, the only remaining p-value, III. 0.0217, matches with (d).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis Significance Testing
Understanding null hypothesis significance testing is crucial for interpreting p-values. The null hypothesis, often represented by the symbol H0, is a general statement or default position that there is no relationship between two measured phenomena. In the context of statistical testing, when we perform an experiment or a study, we measure this through a p-value, which tells us the probability of obtaining test results at least as extreme as the observed results, assuming that the null hypothesis is correct.

When performing the test, if the p-value is low, it suggests that the observed data are unlikely if the null hypothesis were true, and thus, provides evidence against the null hypothesis. For example, in a clinical trial testing a new drug, the null hypothesis might be that the new drug has no effect on patients, compared to a placebo. If the results show a very low p-value, it would suggest that the effect observed (or even a more extreme one) is improbable due to chance alone, hinting that the drug may indeed have an effect.

In practice, we use a threshold, or alpha value, to decide whether to reject the null hypothesis. If the p-value is less than the chosen threshold, the null hypothesis is rejected in favor of an alternative hypothesis (H1 or Ha), which is the opposite of the null hypothesis. The example with the p-value of 0.0875 in the exercise above falls into a situation where the evidence against the null hypothesis is significant, but only at a less stringent level of 10%.
Statistical Evidence
Statistical evidence refers to the strength of the data in supporting or refuting a hypothesis. In hypothesis testing, the p-value quantifies this evidence. A low p-value indicates strong evidence against the null hypothesis, while a high p-value suggests weak evidence.

It's important to note that while the p-value can inform us about the strength of the evidence, it does not measure the probability that the hypothesis is true or false. For example, a p-value of 0.5457, as seen with statement (c) in the exercise, indicates that there is a 54.57% chance of observing the test results, or something more extreme, if the null hypothesis is true. This high p-value indicates there is not enough evidence to reject the null hypothesis.

Understanding statistical evidence is essential in research as it helps prevent incorrect conclusions. Strong evidence against the null hypothesis, like a p-value of 0.00003, leads to greater confidence in the validity of the research findings, potentially influencing further scientific inquiry or real-world decisions.
Hypothesis Testing Thresholds
Hypothesis testing thresholds are predetermined levels of significance used to decide whether to reject the null hypothesis. Commonly used thresholds or alpha levels are 0.05 (5%), 0.01 (1%), and 0.10 (10%). These values denote the probability of incorrectly rejecting a true null hypothesis, also known as the Type I error rate.

Choosing an appropriate threshold is a critical part of the experimental design and depends on the field of study, the standard of evidence required, and the potential consequences of making a Type I error. For example, higher stakes decisions often require a lower threshold (such as 1%) to minimize the chance of error. Conversely, in exploratory research, a higher threshold (such as 10%) might be acceptable.

The exercise provided illustrates different outcomes based on these thresholds. In statement (d), a result was significant at the 5% threshold (p-value less than 0.05) but not at the stricter 1% threshold (p-value still greater than 0.01). This differentiation emphasizes that researchers must consider the proper threshold for their specific scientific questions and the implications of their hypothesis tests.

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Most popular questions from this chapter

Influencing Voters Exercise 4.39 on page 272 describes a possible study to see if there is evidence that a recorded phone call is more effective than a mailed flyer in getting voters to support a certain candidate. The study assumes a significance level of \(\alpha=0.05\) (a) What is the conclusion in the context of thisstudy if the p-value for the test is \(0.027 ?\) (b) In the conclusion in part (a), which type of error are we possibly making: Type I or Type II? Describe what that type of error means in this situation. (c) What is the conclusion if the p-value for the test is \(0.18 ?\)

Studies have shown that omega-3 fatty acids have a wide variety of health benefits. Omega- 3 oils can be found in foods such as fish, walnuts, and flaxseed. A company selling milled flaxseed advertises that one tablespoon of the product contains, on average, at least \(3800 \mathrm{mg}\) of ALNA, the primary omega-3. (a) The company plans to conduct a test to ensure that there is sufficient evidence that its claim is correct. To be safe, the company wants to make sure that evidence shows the average is higher than \(3800 \mathrm{mg} .\) What are the null and alternative hypotheses? (b) Suppose, instead, that a consumer organization plans to conduct a test to see if there is evidence against the claim that the product contains an average of \(3800 \mathrm{mg}\) per tablespoon. The consumer organization will only take action if it finds evidence that the claim made by the company is false and that the actual average amount of omega- 3 is less than \(3800 \mathrm{mg}\). What are the null and alternative hypotheses?

Exercise 2.19 on page 58 introduces a study examining whether giving antibiotics in infancy increases the likelihood that the child will be overweight. Prescription records were examined to determine whether or not antibiotics were prescribed during the first year of a child's life, and each child was classified as overweight or not at age 12. (Exercise 2.19 looked at the results for age 9.) The researchers compared the proportion overweight in each group. The study concludes that: "Infants receiving antibiotics in the first year of life were more likely to be overweight later in childhood compared with those who were unexposed \((32.4 \%\) versus \(18.2 \%\) at age 12 \(P=0.002) "\) (a) What is the explanatory variable? What is the response variable? Classify each as categorical or quantitative. (b) Is this an experiment or an observational study? (c) State the null and alternative hypotheses and define the parameters. (d) Give notation and the value of the relevant sample statistic. (e) Use the p-value to give the formal conclusion of the test (Reject \(H_{0}\) or Do not reject \(H_{0}\) ) and to give an indication of the strength of evidence for the result. (f) Can we conclude that whether or not children receive antibiotics in infancy causes the difference in proportion classified as overweight?

The Ignorance Surveys were conducted in 2013 using random sampling methods in four different countries under the leadership of Hans Rosling, a Swedish statistician and international health advocate. The survey questions were designed to assess the ignorance of the public to global population trends. The survey was not just designed to measure ignorance (no information), but if preconceived notions can lead to more wrong answers than would be expected by random guessing. One question asked, "In the last 20 years the proportion of the world population living in extreme poverty has \(\ldots, "\) and three choices were provided: 1) "almost doubled" 2) "remained more or less the same," and 3) "almost halved." Of 1005 US respondents, just \(5 \%\) gave the correct answer: "almost halved." 34 We would like to test if the percent of correct choices is significantly different than what would be expected if the participants were just randomly guessing between the three choices. (a) What are the null and alternative hypotheses? (b) Using StatKey or other technology, construct a randomization distribution and compute the p-value. (c) State the conclusion in context.

Exercise 4.113 refers to a survey used to assess the ignorance of the public to global population trends. A similar survey was conducted in the United Kingdom, where respondents were asked if they had a university degree. One question asked, "In the last 20 years the proportion of the world population living in extreme poverty has \(\ldots, "\) and three choices 2) "remained more or were provided: 1\()^{\text {6i }}\) increased" less the same," and 3) "decreased." Of 373 university degree holders, 45 responded with the correct answer: decreased; of 639 non-degree respondents, 57 responded with the correct answer. \({ }^{35}\) We would like to test if the percent of correct answers is significantly different between degree holders and non- degree holders. (a) What are the null and alternative hypotheses? (b) Using StatKey or other technology, construct a randomization distribution and compute the p-value. (c) State the conclusion in context.

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