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Give null and alternative hypotheses for a population proportion, as well as sample results. Use StatKey or other technology to generate a randomization distribution and calculate a p-value. StatKey tip: Use "Test for a Single Proportion" and then "Edit Data" to enter the sample information. Hypotheses: \(H_{0}: p=0.5\) vs \(H_{a}: p \neq 0.5\) Sample data: \(\hat{p}=42 / 100=0.42\) with \(n=100\)

Short Answer

Expert verified
Given a null hypothesis \(H_{0}: p = 0.5\) and alternative hypothesis \(H_{a}: p \neq 0.5\). The sample data is \(\hat{p} = 0.42\) and \(n = 100\). The randomization distribution is obtained, and a p-value can be calculated using StatKey or other technology. Note: The computed p-value will depend on the simulated results from the randomization distribution.

Step by step solution

01

Construct Hypotheses

For hypothesis testing of a population proportion, there are two types of hypotheses: a null hypothesis \(H_{0}\) and an alternative hypothesis \(H_{a}\). The null hypothesis is the statement being tested, usually representing no effect or status quo. The alternative hypothesis is the statement that we'll accept if the data provide strong enough evidence against the null hypothesis. Given:Null hypothesis (H_0): \(p = 0.5\) Alternative hypothesis (H_a): \(p \neq 0.5\)
02

Provide Sample Data

The sample data consist of the observed sample proportion \(\hat{p}\) and the sample size \(n\). Given:Sample Proportion (\(\hat{p}\)): 42/100 = 0.42 (meaning 42% of observations)Sample Size (\(n\)): 100
03

Generate Randomization Distribution & Calculate the P-value Using StatKey

StatKey (or a similar statistical tool) should be used to create a randomization distribution and calculate the p-value for the situation. In StatKey, choose 'Test for a Single Proportion', and use 'Edit Data' to input the sample information. The randomization distribution will generate many scenarios (e.g., 5000 scenarios) under the null hypothesis, showing the proportion of successes in the sample size. This will allow us to see the number of scenarios out of the total that have a proportion of successes as extreme or more extreme than what was observed. The p-value will be calculated as \(P-value = \frac{\text{Number of Scenarios as Extreme or More Extreme than Observed}}{\text{Total Number of Scenarios}}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
The null hypothesis, denoted as \(H_{0}\), is a statement in hypothesis testing that implies no effect or no difference. It is the default or status quo condition that a researcher aims to test against experimental data. In the context of testing a population proportion, the null hypothesis might suggest that the proportion of a characteristic within a population is equal to a specific value. For example, if we want to test whether a coin is fair, we could set our null hypothesis as \(H_{0}: p = 0.5\), which states that the probability (proportion) of getting heads is 50%.
When we conduct hypothesis testing, we are essentially looking for evidence that can lead us to reject the null hypothesis. The absence of such evidence means that we do not have enough reason to doubt the null condition, and thus, we fail to reject the null hypothesis.
Alternative Hypothesis
In contrast to the null hypothesis, the alternative hypothesis, denoted as \(H_{a}\) or \(H_{1}\), represents what a researcher wants to prove. It is the assertion that there is an effect or a difference, contrasting the null hypothesis's claim. Going back to our coin example, if we suspect the coin to be biased, the alternative hypothesis might be expressed as \(H_{a}: p eq 0.5\).
This means we believe that the probability of obtaining heads is not 50%. The alternative hypothesis could be one-sided or two-sided, indicating whether we are looking for evidence of a specific direction of the effect or any significant effect in either direction.
Population Proportion
The population proportion, denoted as \(p\), refers to the percentage of a specific characteristic within a whole population. It's what we aim to estimate or make inferences about through hypothesis testing.
For instance, if we're exploring the proportion of left-handed individuals in a certain country, \(p\) would represent the true proportion of left-handers in the entire population. Obtaining an exact value for \(p\) is often impractical due to the large size of populations, so we estimate it using sample proportions from smaller, representative groups.
P-Value Calculation
The p-value is a crucial concept in hypothesis testing. It represents the probability of obtaining a sample result at least as extreme as the one observed, assuming that the null hypothesis is true. A lower p-value suggests that the observed data are unlikely under the null hypothesis and thus provide evidence against it.
To calculate the p-value, we compare our observed sample proportion to a distribution of sample proportions we would expect to see if the null hypothesis were true, known as the randomization distribution. The calculation can be expressed as \( P-value = \frac{\text{Number of Scenarios as Extreme or More Extreme than Observed}}{\text{Total Number of Scenarios}} \). Generally, a p-value lower than a predetermined significance level (commonly 0.05) means that we reject the null hypothesis.
Randomization Distribution
A randomization distribution is a probability distribution that represents the possible outcomes for a statistic if the null hypothesis were true. It's constructed by taking a sample statistic and repeatedly simulating random sampling from the population under the null hypothesis conditions.
For example, if our null hypothesis states that the true population proportion is 0.5, we create a randomization distribution by simulating many random samples (e.g., flipping a coin) and recording the proportion in each sample. This distribution helps us understand how unusual our observed sample proportion is within the context of the null hypothesis.
Sample Proportion
The sample proportion, denoted as \(\hat{p}\), is the percentage of a characteristic within a sample drawn from a population. It serves as an estimate of the true population proportion. In the given exercise, the sample proportion is \(\hat{p} = 42/100 = 0.42\), meaning in a sample of 100 people, 42% have the characteristic being tested.
Obtaining the sample proportion is a critical step in hypothesis testing as it provides the observed value to be compared against the expected outcomes under the null hypothesis. It is the basis for deciding whether the provided data can refute the null hypothesis.
StatKey Software
StatKey is a software tool specifically designed to facilitate teaching and learning statistics. It provides users with a simplified interface to conduct various statistical analyses, including hypothesis tests for population proportions. Using ‘Test for a Single Proportion’ and ‘Edit Data’ features, students can easily input their sample information and simulate randomization distributions for their hypothesis tests.
It serves as a valuable educational resource as it allows students to visualize the randomization distribution, compute p-values, and understand the concepts of statistical inference in a hands-on manner. For instructors and learners, such tools make the process of learning statistics more interactive and grounded in practical experience.

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Most popular questions from this chapter

In Exercise 4.16 on page 268 , we describe an observational study investigating a possible relationship between exposure to organophosphate pesticides as measured in urinary metabolites (DAP) and diagnosis of ADHD (attention-deficit/hyperactivity disorder). In reporting the results of this study, the authors \(^{28}\) make the following statements: \- "The threshold for statistical significance was set at \(P<.05 . "\) \- "The odds of meeting the \(\ldots\) criteria for \(\mathrm{ADHD}\) increased with the urinary concentrations of total DAP metabolites" \- "The association was statistically significant." (a) What can we conclude about the p-value obtained in analyzing the data? (b) Based on these statements, can we distinguish whether the evidence of association is very strong vs moderately strong? Why or why not? (c) Can we conclude that exposure to pesticides is related to the likelihood of an ADHD diagnosis? (d) Can we conclude that exposure to pesticides causes more cases of ADHD? Why or why not?

In Exercise 3.129 on page \(254,\) we see that the home team was victorious in 70 games out of a sample of 120 games in the FA premier league, a football (soccer) league in Great Britain. We wish to investigate the proportion \(p\) of all games won by the home team in this league. (a) Use StatKeyor other technology to find and interpret a \(90 \%\) confidence interval for the proportion of games won by the home team. (b) State the null and alternative hypotheses for a test to see if there is evidence that the proportion is different from 0.5 . (c) Use the confidence interval from part (a) to make a conclusion in the test from part (b). State the confidence level used. (d) Use StatKey or other technology to create a randomization distribution and find the p-value for the test in part (b). (e) Clearly interpret the result of the test using the p-value and using a \(10 \%\) significance level. Does your answer match your answer from part (c)? (f) What information does the confidence interval give that the p-value doesn't? What information does the p-value give that the confidence interval doesn't? (g) What's the main difference between the bootstrap distribution of part (a) and the randomization distribution of part (d)?

Interpreting a P-value In each case, indicate whether the statement is a proper interpretation of what a p-value measures. (a) The probability the null hypothesis \(H_{0}\) is true. (b) The probability that the alternative hypothesis \(H_{a}\) is true. (c) The probability of seeing data as extreme as the sample, when the null hypothesis \(H_{0}\) is true. (d) The probability of making a Type I error if the null hypothesis \(H_{0}\) is true. (e) The probability of making a Type II error if the alternative hypothesis \(H_{a}\) is true.

Give null and alternative hypotheses for a population proportion, as well as sample results. Use StatKey or other technology to generate a randomization distribution and calculate a p-value. StatKey tip: Use "Test for a Single Proportion" and then "Edit Data" to enter the sample information. Hypotheses: \(H_{0}: p=0.5\) vs \(H_{a}: p<0.5\) Sample data: \(\hat{p}=38 / 100=0.38\) with \(n=100\)

Influencing Voters: Is a Phone Call More Effective? Suppose, as in Exercise \(4.38,\) that we wish to compare methods of influencing voters to support a particular candidate, but in this case we are specifically interested in testing whether a phone call is more effective than a flyer. Suppose also that our random sample consists of only 200 voters, with 100 chosen at random to get the flyer and the rest getting a phone call. (a) State the null and alternative hypotheses in this situation. (b) Display in a two-way table possible sample results that would offer clear evidence that the phone call is more effective. (c) Display in a two-way table possible sample results that offer no evidence at all that the phone call is more effective. (d) Display in a two-way table possible sample results for which the outcome is not clear: there is some evidence in the sample that the phone call is more effective but it is possibly only due to random chance and likely not strong enough to generalize to the population.

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