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Influencing Voters When getting voters to support a candidate in an election, is there a difference between a recorded phone call from the candidate or a flyer about the candidate sent through the mail? A sample of 500 voters is randomly divided into two groups of 250 each, with one group getting the phone call and one group getting the flyer. The voters are then contacted to see if they plan to vote for the candidate in question. We wish to see if there is evidence that the proportions of support are different between the two methods of campaigning. (a) Define the relevant parameter(s) and state the null and alternative hypotheses. (b) Possible sample results are shown in Table 4.3 . Compute the two sample proportions: \(\hat{p}_{c},\) the proportion of voters getting the phone call who say they will vote for the candidate, and \(\hat{p}_{f},\) the proportion of voters getting the flyer who say they will vote for the candidate. Is there a difference in the sample proportions? (c) A different set of possible sample results are shown in Table 4.4. Compute the same two sample proportions for this table. (d) Which of the two samples seems to offer stronger evidence of a difference in effectiveness between the two campaign methods? Explain your reasoning. $$ \begin{array}{lcc} \hline & \begin{array}{c} \text { Will Vote } \\ \text { Sample A } \end{array} & \text { for Candidate } & \begin{array}{l} \text { Will Not Vote } \\ \text { for Candidate } \end{array} \\ \hline \text { Phone call } & 152 & 98 \\ \text { Flyer } & 145 & 105 \\ \hline \end{array} $$ $$ \begin{array}{lcc} \text { Sample B } & \begin{array}{c} \text { Will Vote } \\ \text { for Candidate } \end{array} & \begin{array}{c} \text { Will Not Vote } \\ \text { for Candidate } \end{array} \\ \hline \text { Phone call } & 188 & 62 \\ \text { Flyer } & 120 & 130 \\ \hline \end{array} $$

Short Answer

Expert verified
Based on the analysis, Sample B provides stronger evidence that the two campaign methods do not have the same effectiveness. The difference between the proportions of voters that will vote for the candidate under the phone call method and under the flyer method is larger in Sample B than in Sample A.

Step by step solution

01

Define Parameters

To analyze the given scenario, let's define the relevant parameters. We have \(p_c\) as the proportion of voters who received a phone call and said they would vote for the candidate, and \(p_f\) as the proportion of voters who received a flyer and said they would vote for the candidate.
02

State Hypotheses

We need to state our null hypothesis (\(H_0\)) and alternative hypothesis (\(H_1\)). \(H_0\) would be \(p_f = p_c\), meaning there is no difference in the proportions of those who would vote for the candidate between the two campaign methods. \(H_1\) would be \(p_f ≠ p_c\), signifying there is a difference in the proportions of those who would vote for the candidate among the two campaign methods.
03

Compute Sample Proportions: Sample A

We compute the proportion of voters who plan to vote for the candidate in both the phone calls and flyers methods, with data from Sample A. For phone calls, \(\hat{p}_{c}A = 152/250 = 0.608\) and for flyers, \(\hat{p}_{f}A = 145/250 = 0.58\). Thus, the proportion of voters that will vote for the candidate seems slightly higher for phone calls in Sample A.
04

Compute Sample Proportions: Sample B

We do a similar calculation for Sample B. For phone calls \(\hat{p}_{c}B = 188/250 = 0.752\) and for flyers, \(\hat{p}_{f}B = 120/250 = 0.48\). The proportion of voters that will vote for the candidate is significantly higher for phone calls in Sample B.
05

Compare Results

Comparing the two samples A and B, it appears that Sample B provides stronger evidence for a difference in effectiveness between the two campaign methods. The difference between the proportions \(\hat{p}_{c}\) and \(\hat{p}_{f}\) in Sample B is significantly larger than in Sample A.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypothesis Testing in Campaign Methods
Hypothesis testing is a statistical method used to decide whether there is enough evidence in a sample of data to infer that a certain condition is true for the entire population. In the context of campaigning methods, hypothesis testing is used to determine if one method, like a phone call, is more effective than another method, such as sending a flyer, in influencing voters' decisions.

Let's apply this to an election campaign scenario. We collect data from a sample of voters who have experienced each of these two campaigning techniques. Then, we perform hypothesis testing to decide if there is a statistically significant difference between the success rate of these methods or not. This process involves defining both a null hypothesis and an alternative hypothesis, carrying out calculations to find sample proportions, comparing these proportions, and then making a decision based on statistical evidence.
Understanding Sample Proportions
Sample proportions are statistics that provide estimates of the true proportion within the entire population. For example, when you're investigating the effectiveness of campaign methods, you calculate the sample proportion by dividing the number of voters who respond positively to a method by the total number of voters sampled for that method.

In our case, the sample proportions, denoted as \(\hat{p}_{c}\) for phone calls and \(\hat{p}_{f}\) for flyers, are essential for comparing the effectiveness of the two campaign methods. These proportions help us to quantify the level of support for the candidate and determine if there's a notable difference between the impacts of phone calls and flyers. Understandably, computing these correctly is paramount for drawing reliable conclusions from our hypothesis test.
Null and Alternative Hypotheses
In any hypothesis testing situation, we start by stating the null hypothesis, often denoted as \(H_0\), and the alternative hypothesis, denoted as \(H_1\) or \(H_a\). The null hypothesis is a statement of no effect or no difference. It's the hypothesis that we assume to be true unless the sample data provide strong evidence against it.

In the election campaign example, the null hypothesis states that there is no difference in voter support between those contacted by phone call and those who received a flyer, \(p_f = p_c\). Conversely, the alternative hypothesis posits that there is a difference, \(p_f eq p_c\). During the analysis, we check whether the sample data provide enough evidence to reject the null hypothesis in favor of the alternative hypothesis.
Assessing Statistical Evidence
Assessing statistical evidence involves analyzing sample data to decide whether or not they support the null hypothesis. If the evidence strongly contradicts our null hypothesis, we might reject it in favor of the alternative hypothesis.

In our scenario with the campaign methods, we compare the sample proportions from two different sets of sample results. If the difference between the sample proportions \(\hat{p}_{c}\) and \(\hat{p}_{f}\) is substantial, it implies that one method may truly be more effective than the other. Statisticians typically use a significance level to determine if the observed evidence is strong enough to reject the null hypothesis. The concept of p-value also plays a crucial role here – if the p-value is less than our significance level, we reject the null hypothesis indicating that our statistical evidence points to a difference in campaign methods' effectiveness.

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Most popular questions from this chapter

Give null and alternative hypotheses for a population proportion, as well as sample results. Use StatKey or other technology to generate a randomization distribution and calculate a p-value. StatKey tip: Use "Test for a Single Proportion" and then "Edit Data" to enter the sample information. Hypotheses: \(H_{0}: p=0.7\) vs \(H_{a}: p<0.7\) Sample data: \(\hat{p}=125 / 200=0.625\) with \(n=200\)

A study \(^{20}\) conducted in June 2015 examines ownership of tablet computers by US adults. A random sample of 959 people were surveyed, and we are told that 197 of the 455 men own a tablet and 235 of the 504 women own a tablet. We want to test whether the survey results provide evidence of a difference in the proportion owning a tablet between men and women. (a) State the null and alternative hypotheses, and define the parameters. (b) Give the notation and value of the sample statistic. In the sample, which group has higher tablet ownership: men or women? (c) Use StatKey or other technology to find the pvalue.

How influenced are consumers by price and marketing? If something costs more, do our expectations lead us to believe it is better? Because expectations play such a large role in reality, can a product that costs more (but is in reality identical) actually be more effective? Baba Shiv, a neuroeconomist at Stanford, conducted a study \(^{25}\) involving 204 undergraduates. In the study, all students consumed a popular energy drink which claims on its packaging to increase mental acuity. The students were then asked to solve a series of puzzles. The students were charged either regular price ( \(\$ 1.89\) ) for the drink or a discount price \((\$ 0.89)\). The students receiving the discount price were told that they were able to buy the drink at a discount since the drinks had been purchased in bulk. The authors of the study describe the results: "the number of puzzles solved was lower in the reduced-price condition \((M=4.2)\) than in the regular-price condition \((M=5.8) \ldots p<.0001 . "\) (a) What can you conclude from the study? How strong is the evidence for the conclusion? (b) These results have been replicated in many similar studies. As Jonah Lehrer tells us: "According to Shiv, a kind of placebo effect is at work. Since we expect cheaper goods to be less effective, they generally are less effective, even if they are identical to more expensive products. This is why brand-name aspirin works better than generic aspirin and why Coke tastes better than cheaper colas, even if most consumers can't tell the difference in blind taste tests."26 Discuss the implications of this research in marketing and pricing.

Hypotheses for a statistical test are given, followed by several possible confidence intervals for different samples. In each case, use the confidence interval to state a conclusion of the test for that sample and give the significance level used. Hypotheses: \(H_{0}: \mu_{1}=\mu_{2}\) vs \(H_{a}: \mu_{1} \neq \mu_{2} .\) In addition, in each case for which the results are significant, state which group ( 1 or 2 ) has the larger mean. (a) \(95 \%\) confidence interval for \(\mu_{1}-\mu_{2}\) : 0.12 to 0.54 (b) \(99 \%\) confidence interval for \(\mu_{1}-\mu_{2}\) : -2.1 to 5.4 (c) \(90 \%\) confidence interval for \(\mu_{1}-\mu_{2}\) : -10.8 to -3.7

Eating Breakfast Cereal and Conceiving Boys Newscientist.com ran the headline "Breakfast Cereals Boost Chances of Conceiving Boys," based on an article which found that women who eat breakfast cereal before becoming pregnant are significantly more likely to conceive boys. \({ }^{42}\) The study used a significance level of \(\alpha=0.01\). The researchers kept track of 133 foods and, for each food, tested whether there was a difference in the proportion conceiving boys between women who ate the food and women who didn't. Of all the foods, only breakfast cereal showed a significant difference. (a) If none of the 133 foods actually have an effect on the gender of a conceived child, how many (if any) of the individual tests would you expect to show a significant result just by random chance? Explain. (Hint: Pay attention to the significance level.) (b) Do you think the researchers made a Type I error? Why or why not? (c) Even if you could somehow ascertain that the researchers did not make a Type I error, that is, women who eat breakfast cereals are actually more likely to give birth to boys, should you believe the headline "Breakfast Cereals Boost Chances of Conceiving Boys"? Why or why not?

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