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Income East and West of the Mississippi For a random sample of households in the US, we record annual household income, whether the location is east or west of the Mississippi River, and number of children. We are interested in determining whether there is a difference in average household income between those east of the Mississippi and those west of the Mississippi. (a) Define the relevant parameter(s) and state the null and alternative hypotheses. (b) What statistic(s) from the sample would we use to estimate the difference?

Short Answer

Expert verified
The parameter for households East of the Mississippi River is denoted as \( \mu1 \) and for households West of the Mississippi River as \( \mu2 \). The null hypothesis would be \( H0: \mu1 - \mu2 = 0 \), meaning there's no difference in average household income, and the alternative hypothesis is \( Ha: \mu1 - \mu2 \neq 0 \), meaning there is a difference. The sample means \( \bar{X1} \) and \( \bar{X2} \) are used to estimate the difference.

Step by step solution

01

Defining Parameters

The parameters of interest here would be \( \mu1 \), the population mean income of households located east of the Mississippi River, and \( \mu2 \), the population mean income of households located west of the Mississippi River.
02

Null and Alternative Hypothesis

The null hypothesis \( H0 \) is that there is no difference in average household income between the two locations. In mathematical terms, \( H0: \mu1 - \mu2 = 0 \). The alternative hypothesis \( Ha \) is that there is a difference in the average income: \( Ha: \mu1 - \mu2 \neq 0 \).
03

Identify Statistics

To estimate the difference in average household incomes, we would use the sample means from both locations. Thus, the statistics from the sample would be \( \bar{X1} \) and \( \bar{X2} \), where \( \bar{X1} \) represents the sample mean income of households located east of the Mississippi River and \( \bar{X2} \) represents the sample mean income of households located west of the Mississippi River.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null and Alternative Hypotheses
Understanding null and alternative hypotheses is crucial when embarking on statistical hypothesis testing. In essence, the null hypothesis (\( H_0 \)) is a statement of no effect or no difference. For instance, in comparing household incomes, the null hypothesis posits there is no significant difference in average incomes based on the location relative to the Mississippi River. That is to say, it predicts that the mean income to the east, \( \mu1 \), is equal to the mean income to the west, \( \mu2 \).

Contrarily, the alternative hypothesis (\( H_a \)) is the statement we are seeking to test and potentially validate. It essentially suggests the existence of an effect or a difference. In our example, the alternative hypothesis contends that there is a discrepancy in household incomes between the two regions (\( \mu1 eq \mu2 \)). It leaves open the direction of the difference; the incomes could be higher or lower on either side of the river, as long as they are not equal.
Sample Mean
The sample mean \( \bar{X} \) is a statistic that represents the average value of a sample from a population. It serves as an estimate for the population mean \( \mu \), and calculating it involves summing all the values for a particular variable in the sample and then dividing by the total number of observations.

When comparing two groups, as in the case with household incomes on either side of the Mississippi River, we calculate two sample means \( \bar{X1} \) and \( \bar{X2} \). These averages provide critical insights into the central tendencies of the respective datasets and lay the groundwork for hypothesis testing. They are essential in estimating the difference between the respective population means.
Population Mean
The population mean (\( \mu \) ) represents the average value of a particular variable for an entire population. Unlike the sample mean, which is derived from a subset of the population, the population mean includes every individual instance within the defined group. It's an ideal parameter that usually remains unknown and is estimated using the sample mean.

In the context of our household income example, we are observing two population means: \( \mu1 \) and \( \mu2 \), representing the average incomes east and west of the Mississippi River, respectively. Understanding these theoretical averages is vital as they serve as benchmarks for the true state of affairs in the entire population.
Estimation of Difference
Estimation of difference involves calculating the degree to which two sample statistics vary from each other. This is often used to infer whether there is a likely difference in the population parameters. For example, the estimated difference in average household incomes between the two locations would be the subtraction of the sample mean to the west \( \bar{X2} \) from the sample mean to the east \( \bar{X1} \) (e.g., \( \bar{X1} - \bar{X2} \)).

This estimate provides a snapshot of how incomes compare, while the significance of this difference will be addressed through statistical hypothesis testing. In practice, such estimations are accompanied by a measure of variability or uncertainty, like a confidence interval, that adds more context to the point estimate.
Statistical Hypothesis Testing
Statistical hypothesis testing is a method used to determine if there is enough statistical evidence in a sample of data to infer that a certain condition holds true for the entire population. The procedure involves several steps, beginning with the formulation of both null and alternative hypotheses. Then, a test statistic that represents the data is calculated, and its value is used to make a decision regarding the hypotheses.

In the scenario of comparing household incomes across different regions, a test statistic derived from the sample means \( \bar{X1} \) and \( \bar{X2} \) would be evaluated against a critical value. If the test statistic falls within a certain range (typically determined by a significance level, commonly 0.05), we would reject the null hypothesis, suggesting that there is a statistically significant difference in household incomes by geography.

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Most popular questions from this chapter

Numerous studies have shown that a high fat diet can have a negative effect on a child's health. A new study \(^{22}\) suggests that a high fat diet early in life might also have a significant effect on memory and spatial ability. In the double-blind study, young rats were randomly assigned to either a high-fat diet group or to a control group. After 12 weeks on the diets, the rats were given tests of their spatial memory. The article states that "spatial memory was significantly impaired" for the high-fat diet rats, and also tells us that "there were no significant differences in amount of time exploring objects" between the two groups. The p-values for the two tests are 0.0001 and 0.7 . (a) Which p-value goes with the test of spatial memory? Which p-value goes with the test of time exploring objects? (b) The title of the article describing the study states "A high-fat diet causes impairment" in spatial memory. Is the wording in the title justified (for rats)? Why or why not?

Interpreting a P-value In each case, indicate whether the statement is a proper interpretation of what a p-value measures. (a) The probability the null hypothesis \(H_{0}\) is true. (b) The probability that the alternative hypothesis \(H_{a}\) is true. (c) The probability of seeing data as extreme as the sample, when the null hypothesis \(H_{0}\) is true. (d) The probability of making a Type I error if the null hypothesis \(H_{0}\) is true. (e) The probability of making a Type II error if the alternative hypothesis \(H_{a}\) is true.

The same sample statistic is used to test a hypothesis, using different sample sizes. In each case, use StatKey or other technology to find the p-value and indicate whether the results are significant at a \(5 \%\) level. Which sample size provides the strongest evidence for the alternative hypothesis? Testing \(H_{0}: p_{1}=p_{2}\) vs \(H_{a}: p_{1}>p_{2}\) using \(\hat{p}_{1}-\hat{p}_{2}=0.8-0.7=0.10\) with each of the following sample sizes: (a) \(\hat{p}_{1}=24 / 30=0.8\) and \(\hat{p}_{2}=14 / 20=0.7\) (b) \(\hat{p}_{1}=240 / 300=0.8\) and \(\hat{p}_{2}=140 / 200=0.7\)

Hypotheses for a statistical test are given, followed by several possible confidence intervals for different samples. In each case, use the confidence interval to state a conclusion of the test for that sample and give the significance level used. Hypotheses: \(H_{0}: \mu_{1}=\mu_{2}\) vs \(H_{a}: \mu_{1} \neq \mu_{2} .\) In addition, in each case for which the results are significant, state which group ( 1 or 2 ) has the larger mean. (a) \(95 \%\) confidence interval for \(\mu_{1}-\mu_{2}\) : 0.12 to 0.54 (b) \(99 \%\) confidence interval for \(\mu_{1}-\mu_{2}\) : -2.1 to 5.4 (c) \(90 \%\) confidence interval for \(\mu_{1}-\mu_{2}\) : -10.8 to -3.7

Eating Breakfast Cereal and Conceiving Boys Newscientist.com ran the headline "Breakfast Cereals Boost Chances of Conceiving Boys," based on an article which found that women who eat breakfast cereal before becoming pregnant are significantly more likely to conceive boys. \({ }^{42}\) The study used a significance level of \(\alpha=0.01\). The researchers kept track of 133 foods and, for each food, tested whether there was a difference in the proportion conceiving boys between women who ate the food and women who didn't. Of all the foods, only breakfast cereal showed a significant difference. (a) If none of the 133 foods actually have an effect on the gender of a conceived child, how many (if any) of the individual tests would you expect to show a significant result just by random chance? Explain. (Hint: Pay attention to the significance level.) (b) Do you think the researchers made a Type I error? Why or why not? (c) Even if you could somehow ascertain that the researchers did not make a Type I error, that is, women who eat breakfast cereals are actually more likely to give birth to boys, should you believe the headline "Breakfast Cereals Boost Chances of Conceiving Boys"? Why or why not?

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