Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A study suggests that exposure to UV rays through the car window may increase the risk of skin cancer. \(^{52}\) The study reviewed the records of all 1,050 skin cancer patients referred to the St. Louis University Cancer Center in 2004\. Of the 42 patients with melanoma, the cancer occurred on the left side of the body in 31 patients and on the right side in the other 11 . (a) Is this an experiment or an observational study? (b) Of the patients with melanoma, what proportion had the cancer on the left side? (c) A bootstrap \(95 \%\) confidence interval for the proportion of melanomas occurring on the left is 0.579 to \(0.861 .\) Clearly interpret the confidence interval in the context of the problem. (d) Suppose the question of interest is whether melanomas are more likely to occur on the left side than on the right. State the null and alternative hypotheses. (e) Is this a one-tailed or two-tailed test? (f) Use the confidence interval given in part (c) to predict the results of the hypothesis test in part (d). Explain your reasoning. (g) A randomization distribution gives the p-value as 0.003 for testing the hypotheses given in part (d). What is the conclusion of the test in the context of this study? (h) The authors hypothesize that skin cancers are more prevalent on the left because of the sunlight coming in through car windows. (Windows protect against UVB rays but not UVA rays.) Do the data in this study support a conclusion that more melanomas occur on the left side because of increased exposure to sunlight on that side for drivers?

Short Answer

Expert verified
The statistical analysis suggests that melanomas are likely more prevalent on the left side. While the study's authors hypothesize this may be due to increased exposure to sunlight from car windows, note that only a correlation is shown in this study, not causation.

Step by step solution

01

Determine the Study Type

The study being discussed is an observational study as it records data without influencing the conditions or manipulating any variables.
02

Calculate the Proportion of Patients

The proportion of patients with melanoma who had the cancer on the left side is computed by dividing the number of patients with the cancer on the left side by the total patients with melanoma. Thus, proportion \(= \frac{31}{42} = 0.738\)
03

Interpret Confidence Interval

The \(95\%\) confidence interval for the proportion of melanomas occurring on the left side is \(0.579\) to \(0.861\). This means we are \(95\%\) sure that if the study were repeated, the true proportion of left-sided melanomas among patients would be between \(0.579\) and \(0.861\).
04

Null and Alternative Hypotheses

The null hypothesis (\(H_0\)) is that melanomas are equally likely to occur on the left side as on the right. The alternative hypothesis (\(H_1\)) is that melanomas are more likely to occur on the left side.
05

Determine the Type of Test

This is a one-tailed test because we are specifically looking for whether one side (left) is more affected than the other (right). It is not a two-tailed test since we are not checking both sides for being more affected.
06

Predict the Results of the Hypothesis Test

Given that the \(95\%\) confidence interval for the proportion of melanomas occurring on the left side is \(0.579\) to \(0.861\) and does not include \(0.5\) (which is the value assumed under the null hypothesis), we can predict that the result of the hypothesis test will reject the null hypothesis.
07

Interpret the p-value

The p-value of \(0.003\) means there is only a \(0.003\) probability of obtaining a result as or more extreme compared to the observed data, if the null hypothesis was true. Generally, a p-value less than \(0.05\) is considered statistically significant. Therefore, we reject the null hypothesis and conclude that melanomas are likely more prevalent on the left side.
08

Reason the Outcome Based on Given Hypothesis

The authors hypothesize that skin cancers are more prevalent on the left side due to sunlight exposure from car windows, and the statistical results seem to support this. However, correlation is not causation and other factors may be at play. More detailed study is needed to establish causation.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Observational Study vs Experiment
Understanding the difference between observational studies and experiments is vital in statistics. An observational study, like the one conducted on UV exposure and skin cancer risk, involves monitoring and recording data without interfering in the process. Researchers observe subjects in their natural setting and do not manipulate the study variables. In contrast, an experiment involves intentionally changing one or more variables to observe the effect of these manipulations on other variables.

In the skin cancer research, the scientists reviewed medical records, which is a hallmark of an observational study, as they did not influence the exposure or the development of melanoma. This type of study is essential for identifying associations but cannot establish a cause-and-effect relationship due to potential confounding variables.
Confidence Interval Interpretation
A confidence interval provides a range of values, which likely includes the true parameter being estimated within a certain level of confidence. In the context of the skin cancer study, a 95% confidence interval for the proportion of left-side melanomas ranging from 0.579 to 0.861 translates to a very high level of certainty—95 out of 100 times, to be exact—that the true proportion will fall within this range if we were to repeat the study multiple times.

This interval indicates that the proportion of melanomas on the left side is significantly above what would be expected if there were no preference (which would be 0.5 for an equal chance), suggesting a potential association with left-side UV exposure from car windows.
Null and Alternative Hypothesis
In research, it's crucial to articulate the null and alternative hypotheses. The null hypothesis, denoted as H0, represents a statement of no effect or no difference, serving as the benchmark for analysis. Here, the null hypothesis asserts that the likelihood of melanoma occurrence is the same on both the left and right sides of the body.

Conversely, the alternative hypothesis, denoted as H1 or Ha, represents what the researcher aims to demonstrate, in this case, that melanomas are more frequently found on the left side. A hypothesis test determines whether the observed data provide sufficient evidence to reject the null hypothesis in favor of the alternative.
One-tailed and Two-tailed Tests
Choosing between a one-tailed and two-tailed test hinges on the research question. A one-tailed test, also known as a directional test, looks for an effect in only one direction. The skin cancer study used a one-tailed test since the hypothesis specifically targeted an increase in left-side melanoma occurrences versus the right side.

In contrast, a two-tailed test is non-directional and examines whether there is a significant difference in either direction, without specifying which direction beforehand. In scenarios where researchers are looking for any difference or when deviations in both directions have implications, a two-tailed test is appropriate.
P-value Significance
The p-value is a fundamental concept in statistics, indicating the probability of observing data at least as extreme as the sample data, under the assumption that the null hypothesis is true. If the p-value is low, it suggests that the observed data are unlikely under the null hypothesis.

In the UV exposure and skin cancer study, a p-value of 0.003 strongly implies that the observed higher proportion of left-side melanomas—which the confidence interval also supported—is unlikely due to random chance. Therefore, with a significance level typically set at 0.05, the p-value here is low enough to reject the null hypothesis and conclude that there's statistical evidence supporting more frequent left-side melanoma occurrences.
Correlation and Causation
Discerning between correlation and causation is a common issue in interpreting study outcomes. Correlation implies that two variables are related but doesn't mean that one variable causes the changes in another. For instance, in the observed study, while there's a correlation between left-side melanomas and UV exposure through car windows, it does not prove causation.

To make a causal assertion, factors that could confound the results must be controlled for, typically through a well-designed experiment. Although the statistical tests support an association, additional research with controlled experimental designs would be needed to conclusively determine that increased exposure to UV rays while driving is a causal factor for skin cancer.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The same sample statistic is used to test a hypothesis, using different sample sizes. In each case, use StatKey or other technology to find the p-value and indicate whether the results are significant at a \(5 \%\) level. Which sample size provides the strongest evidence for the alternative hypothesis? Testing \(H_{0}: p=0.5\) vs \(H_{a}: p>0.5\) using \(\hat{p}=0.55\) with each of the following sample sizes: (a) \(\hat{p}=55 / 100=0.55\) (b) \(\hat{p}=275 / 500=0.55\) (c) \(\hat{p}=550 / 1000=0.55\)

Giving a Coke/Pepsi taste test to random people in New York City to determine if there is evidence for the claim that Pepsi is preferred.

4.151 Does Massage Really Help Reduce Inflammation in Muscles? In Exercise 4.112 on page \(301,\) we learn that massage helps reduce levels of the inflammatory cytokine interleukin-6 in muscles when muscle tissue is tested 2.5 hours after massage. The results were significant at the \(5 \%\) level. However, the authors of the study actually performed 42 different tests: They tested for significance with 21 different compounds in muscles and at two different times (right after the massage and 2.5 hours after). (a) Given this new information, should we have less confidence in the one result described in the earlier exercise? Why? (b) Sixteen of the tests done by the authors involved measuring the effects of massage on muscle metabolites. None of these tests were significant. Do you think massage affects muscle metabolites? (c) Eight of the tests done by the authors (including the one described in the earlier exercise) involved measuring the effects of massage on inflammation in the muscle. Four of these tests were significant. Do you think it is safe to conclude that massage really does reduce inflammation?

Exercise 4.19 on page 269 describes a study investigating the effects of exercise on cognitive function. \({ }^{31}\) Separate groups of mice were exposed to running wheels for \(0,2,4,7,\) or 10 days. Cognitive function was measured by \(Y\) maze performance. The study was testing whether exercise improves brain function, whether exercise reduces levels of BMP (a protein which makes the brain slower and less nimble), and whether exercise increases the levels of noggin (which improves the brain's ability). For each of the results quoted in parts (a), (b), and (c), interpret the information about the p-value in terms of evidence for the effect. (a) "Exercise improved Y-maze performance in most mice by the 7 th day of exposure, with further increases after 10 days for all mice tested \((p<.01)\) (b) "After only two days of running, BMP ... was reduced \(\ldots\) and it remained decreased for all subsequent time-points \((p<.01)\)." (c) "Levels of noggin ... did not change until 4 days, but had increased 1.5 -fold by \(7-10\) days of exercise \((p<.001)\)." (d) Which of the tests appears to show the strongest statistical effect? (e) What (if anything) can we conclude about the effects of exercise on mice?

Translating Information to Other Significance Levels Suppose in a two-tailed test of \(H_{0}: \rho=0\) vs \(H_{a}: \rho \neq 0,\) we reject \(H_{0}\) when using a \(5 \%\) significance level. Which of the conclusions below (if any) would also definitely be valid for the same data? Explain your reasoning in each case. (a) Reject \(H_{0}: \rho=0\) in favor of \(H_{a}: \rho \neq 0\) at a \(1 \%\) significance level. (b) Reject \(H_{0}: \rho=0\) in favor of \(H_{a}: \rho \neq 0\) at a \(10 \%\) significance level. (c) Reject \(H_{0}: \rho=0\) in favor of the one-tail alternative, \(H_{a}: \rho>0,\) at a \(5 \%\) significance level, assuming the sample correlation is positive.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free