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A confidence interval for a sample is given, followed by several hypotheses to test using that sample. In each case, use the confidence interval to give a conclusion of the test (if possible) and also state the significance level you are using. A \(90 \%\) confidence interval for \(p_{1}-p_{2}: 0.07\) to 0.18 (a) \(H_{0}: p_{1}=p_{2}\) vs \(H_{a}: p_{1} \neq p_{2}\) (b) \(H_{0}: p_{1}=p_{2}\) vs \(H_{a}: p_{1}>p_{2}\) (c) \(H_{0}: p_{1}=p_{2}\) vs \(H_{a}: p_{1}

Short Answer

Expert verified
Based on the given 90% confidence interval, we reject the hypotheses \(H_{0}: p_{1}=p_{2}\) for alternatives \(H_{a}: p_{1} \neq p_{2}\) and \(H_{a}: p_{1}>p_{2}\), but fail to reject it for \(H_{a}: p_{1}<p_{2}\). The significance level used is 10%.

Step by step solution

01

Analysis of the 90% Confidence Interval

First of all, analyze the 90% confidence interval of \(p_{1}-p_{2}\) which ranges from 0.07 to 0.18. A \(90 \%\) confidence interval means that we can be \(90 \%\) confident that the true difference between \(p_{1}\) and \(p_{2}\) lies within this range.
02

Testing Hypothesis (a)

Test the hypothesis \(H_{0}: p_{1}=p_{2}\) against \(H_{a}: p_{1} \neq p_{2}\). If \(p_{1}=p_{2}\), then \(p_{1}-p_{2}=0\). However, 0 is not within the provided confidence interval of 0.07 to 0.18. Therefore, we reject \(H_{0}\) at the \(10 \%\) significance level.
03

Testing Hypothesis (b)

Now test the hypothesis \(H_{0}: p_{1}=p_{2}\) against \(H_{a}: p_{1}>p_{2}\). If \(p_{1}=p_{2}\), then \(p_{1}-p_{2}=0\). The entire confidence interval is above 0, so we reject \(H_{0}\) at the \(10 \%\) significance level.
04

Testing Hypothesis (c)

Lastly, test the hypothesis \(H_{0}: p_{1}=p_{2}\) against \(H_{a}: p_{1}<p_{2}\). If \(p_{1}<p_{2}\), then \(p_{1}-p_{2}<0\). The entire confidence interval is above 0, so we fail to reject \(H_{0}\) at the \(10 \%\) significance level.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Intervals
Confidence intervals are a range of values, derived from sample data, that are believed to contain the true parameter of the population with a certain probability. In hypothesis testing, they serve as an alternative way to test the hypothesis, especially when you do not have access to the original dataset or enough information to perform a standard test.

In the given exercise, a 90% confidence interval for the difference between two proportions, labeled as \( p_{1} \) and \( p_{2} \), was provided. The interval from 0.07 to 0.18 implies that we are 90% confident that the true difference between \( p_{1} \) and \( p_{2} \) lies within this range. By interpreting this confidence interval, one can draw conclusions about the plausibility of the null hypothesis (in this case, that \( p_{1} = p_{2} \) or \( p_{1}-p_{2} = 0 \) ). If the interval does not contain the value under the null hypothesis (0 in this scenario), we have evidence to reject the null hypothesis. Since the interval does not include 0, we can conclude that there is a statistically significant difference between \( p_{1} \) and \( p_{2} \).
Significance Level
The significance level, often denoted by \( \alpha \), is a threshold used to decide whether a statistical hypothesis should be rejected. It is the probability of making a Type I error, which occurs when the null hypothesis is true, but is incorrectly rejected.

In hypothesis testing, if the p-value is less than \( \alpha \), the null hypothesis is rejected. A common significance level used is 0.05, but in the provided exercise, a 90% confidence interval corresponds to a significance level of \( \alpha = 0.10 \). This means there is a 10% risk of wrongly rejecting the null hypothesis \( H_{0}: p_{1} = p_{2} \). When deciding whether to reject \( H_{0} \) based on the confidence interval, you're essentially testing it at the 10% significance level.
Difference Between Two Proportions
When dealing with two separate groups, researchers often want to compare the proportions between these groups, for example, the proportion of success in one group versus another. The difference between two proportions is a measure of how much the proportions in two groups differ from one another.

In this context, the hypothesis tests are structured to examine whether the proportions from two different populations, \( p_{1} \) and \( p_{2} \), are the same or not (null hypothesis) or whether one is larger or smaller than the other (alternative hypothesis). The exercise provided uses a 90% confidence interval to test three different hypotheses related to the difference between two proportions. Each hypothesis (a, b, and c) examines a different relationship (equal, greater than, or less than) between \( p_{1} \) and \( p_{2} \) and draws conclusions based on whether 0 is included in the confidence interval.

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Most popular questions from this chapter

Polling 1000 people in a large community to determine if there is evidence for the claim that the percentage of people in the community living in a mobile home is greater then \(10 \%\).

In Exercise 3.129 on page \(254,\) we see that the home team was victorious in 70 games out of a sample of 120 games in the FA premier league, a football (soccer) league in Great Britain. We wish to investigate the proportion \(p\) of all games won by the home team in this league. (a) Use StatKeyor other technology to find and interpret a \(90 \%\) confidence interval for the proportion of games won by the home team. (b) State the null and alternative hypotheses for a test to see if there is evidence that the proportion is different from 0.5 . (c) Use the confidence interval from part (a) to make a conclusion in the test from part (b). State the confidence level used. (d) Use StatKey or other technology to create a randomization distribution and find the p-value for the test in part (b). (e) Clearly interpret the result of the test using the p-value and using a \(10 \%\) significance level. Does your answer match your answer from part (c)? (f) What information does the confidence interval give that the p-value doesn't? What information does the p-value give that the confidence interval doesn't? (g) What's the main difference between the bootstrap distribution of part (a) and the randomization distribution of part (d)?

Give null and alternative hypotheses for a population proportion, as well as sample results. Use StatKey or other technology to generate a randomization distribution and calculate a p-value. StatKey tip: Use "Test for a Single Proportion" and then "Edit Data" to enter the sample information. Hypotheses: \(H_{0}: p=0.7\) vs \(H_{a}: p<0.7\) Sample data: \(\hat{p}=125 / 200=0.625\) with \(n=200\)

Flaxseed and Omega-3 Exercise 4.30 on page 271 describes a company that advertises that its milled flaxseed contains, on average, at least \(3800 \mathrm{mg}\) of ALNA, the primary omega-3 fatty acid in flaxseed, per tablespoon. In each case below, which of the standard significance levels, \(1 \%\) or \(5 \%\) or \(10 \%,\) makes the most sense for that situation? (a) The company plans to conduct a test just to double-check that its claim is correct. The company is eager to find evidence that the average amount per tablespoon is greater than 3800 (their alternative hypothesis), and is not really worried about making a mistake. The test is internal to the company and there are unlikely to be any real consequences either way. (b) Suppose, instead, that a consumer organization plans to conduct a test to see if there is evidence against the claim that the product contains at least \(3800 \mathrm{mg}\) per tablespoon. If the organization finds evidence that the advertising claim is false, it will file a lawsuit against the flaxseed company. The organization wants to be very sure that the evidence is strong, since if the company is sued incorrectly, there could be very serious consequences.

Match the four \(\mathrm{p}\) -values with the appropriate conclusion: (a) The evidence against the null hypothesis is significant, but only at the \(10 \%\) level. (b) The evidence against the null and in favor of the alternative is very strong. (c) There is not enough evidence to reject the null hypothesis, even at the \(10 \%\) level. (d) The result is significant at a \(5 \%\) level but not at a \(1 \%\) level. I. 0.0875 II. 0.5457 III. 0.0217 IV. \(\quad 0.00003\)

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