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For each situation described, indicate whether it makes more sense to use a relatively large significance level (such as \(\alpha=0.10\) ) or a relatively small significance level (such as \(\alpha=0.01\) ). Using your statistics class as a sample to see if there is evidence of a difference between male and female students in how many hours are spent watching television per week.

Short Answer

Expert verified
Considering the context of this exercise, which doesn't seem to carry high stakes, using a relatively larger significance level such as alpha = 0.10 may be appropriate as it minimizes the risk of Type II error, and gives a better chance of detecting a difference if one truly exists.

Step by step solution

01

Understanding the Null and Alternate Hypotheses

In any statistical study, the first step is often to formulate the null and alternate hypotheses. In this case, the null hypothesis can be that there is no difference in the average television watching time between male and female students. The alternative hypothesis is the opposite of the null hypothesis and in this case, it would be that there is a significant difference between the averages.
02

Assessing the Potential Risks of Type I and Type II errors

The choice of significance level (alpha) is linked to the risks of type I and type II errors. As a researcher, one needs to understand the implications of committing either of these errors. In the context of this exercise, a Type I error (false positives) would incorrectly suggest that there is a difference in the watching habits of male and female students when in reality there isn't. In contrast, a Type II error (false negatives) would incorrectly suggest that there are no differences between the two groups when in fact there are.
03

Choose the Appropriate Significance Level

Now, considering the potential effects of type I and II errors, one can decide on the most appropriate significance level. If claiming a difference where none exists (false positives, Type I) would significantly impact the subsequent actions or decisions, a smaller alpha, say 0.01, should be used. If failing to detect a difference where one exists (false negatives, Type II) would carry more consequences, a larger alpha of 0.10 might be chosen. As this statistic belongs to a classroom research and likely doesn't carry high stakes, a larger α=0.10 could be used as it would minimize the probability of a Type II error, giving a better chance of detecting a difference if it truly exists.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null and Alternate Hypotheses
Understanding the null and alternate hypotheses is essential in any statistical analysis, as it lays the foundation for testing a theory. The null hypothesis (\(H_0\)) is a statement of no effect or no difference, typically representing the status quo or a position of skepticism. For example, if we were testing if a drug has an effect on a health condition, the null hypothesis would state that the drug has no effect.

Conversely, the alternate hypothesis (\(H_1\) or \(H_a\)), proposes that there is an effect or a difference. Continuing with our example, the alternate hypothesis would contend that the drug does improve the health condition. When conducting a test of hypothesis, statistical evidence is used to determine whether to reject the null hypothesis in favor of the alternate hypothesis. The outcome hinges on the level of significance and the data collected. In educational settings, such as comparing study hours between genders as in our exercise, these hypotheses guide the investigation and conclusions drawn about student behaviors.
Type I and Type II Errors
In the realm of statistics, not all errors are made equal. There are two specific kinds of errors to consider when testing hypotheses: Type I and Type II errors. A Type I error occurs when the null hypothesis is true, but is incorrectly rejected. It’s akin to a false positive in medical tests, where someone is told they have a condition when they do not. The significance level (\( \(\alpha\) \) ), directly controls the probability of a Type I error; a lower significance level means a lower chance of making this error.

In contrast, a Type II error, symbolized by \(\beta\), happens when the null hypothesis is false, but we fail to reject it. This is similar to a false negative, where a real effect is missed. The power of the test, which is 1 - \(\beta\), determines the test's ability to detect an effect when there is one. Consequently, scientists and researchers must carefully balance the risks of these errors when deciding the appropriate significance level, often prioritizing which error is more critical to avoid in the context of their study.
Statistical Significance
Statistical significance is a determination of whether the observed effect or difference in a test is unlikely to have occurred by chance. It is an indicator of how confident we can be in the results of our statistical analysis. A result is said to be statistically significant if it is unlikely to have happened under the null hypothesis, typically assessed by a p-value. The p-value represents the probability of observing the data, or something more extreme, assuming that the null hypothesis is true.

If the p-value is less than or equal to the chosen significance level (\( \(\alpha\) \) ), we reject the null hypothesis, suggesting that there is statistically significant evidence against it. Selecting an \(\alpha\) level is subjective, but common values are 0.05, 0.01, or 0.10, as mentioned in the exercise. It depends on the context of the study and how serious a Type I error would be. Research with significant consequences often uses a more stringent significance level, such as 0.01, to minimize the risk of false positives. In contrast, exploratory or preliminary research, where the aim is to detect possible signals that warrant further investigation, may use a higher threshold like 0.10.

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Most popular questions from this chapter

Hypotheses for a statistical test are given, followed by several possible confidence intervals for different samples. In each case, use the confidence interval to state a conclusion of the test for that sample and give the significance level used. Hypotheses: \(H_{0}: \rho=0\) vs \(H_{a}: \rho \neq 0\). In addition, in each case for which the results are significant, give the sign of the correlation. (a) \(95 \%\) confidence interval for \(\rho: 0.07\) to 0.15 . (b) \(90 \%\) confidence interval for \(\rho:-0.39\) to -0.78 . (c) \(99 \%\) confidence interval for \(\rho:-0.06\) to 0.03 .

The data in Hurricanes contains the number of hurricanes that made landfall on the eastern coast of the United States over the 101 years from 1914 to 2014 . Suppose we are interested in testing whether the number of hurricanes is increasing over time. (a) State the null and alternative hypotheses for testing whether the correlation between year and number of hurricanes is positive, which would indicate the number of hurricanes is increasing. (b) Describe in detail how you would create a randomization distribution to test this claim (if you had many more hours to do this exercise and no access to technology).

The same sample statistic is used to test a hypothesis, using different sample sizes. In each case, use StatKey or other technology to find the p-value and indicate whether the results are significant at a \(5 \%\) level. Which sample size provides the strongest evidence for the alternative hypothesis? Testing \(H_{0}: p=0.5\) vs \(H_{a}: p>0.5\) using \(\hat{p}=0.55\) with each of the following sample sizes: (a) \(\hat{p}=55 / 100=0.55\) (b) \(\hat{p}=275 / 500=0.55\) (c) \(\hat{p}=550 / 1000=0.55\)

Exercise 4.19 on page 269 describes a study investigating the effects of exercise on cognitive function. \({ }^{31}\) Separate groups of mice were exposed to running wheels for \(0,2,4,7,\) or 10 days. Cognitive function was measured by \(Y\) maze performance. The study was testing whether exercise improves brain function, whether exercise reduces levels of BMP (a protein which makes the brain slower and less nimble), and whether exercise increases the levels of noggin (which improves the brain's ability). For each of the results quoted in parts (a), (b), and (c), interpret the information about the p-value in terms of evidence for the effect. (a) "Exercise improved Y-maze performance in most mice by the 7 th day of exposure, with further increases after 10 days for all mice tested \((p<.01)\) (b) "After only two days of running, BMP ... was reduced \(\ldots\) and it remained decreased for all subsequent time-points \((p<.01)\)." (c) "Levels of noggin ... did not change until 4 days, but had increased 1.5 -fold by \(7-10\) days of exercise \((p<.001)\)." (d) Which of the tests appears to show the strongest statistical effect? (e) What (if anything) can we conclude about the effects of exercise on mice?

Mating Choice and Offspring Fitness Does the ability to choose a mate improve offspring fitness in fruit flies? Researchers have studied this by taking female fruit flies and randomly dividing them into two groups; one group is put into a cage with a large number of males and able to freely choose who to mate with, while flies in the other group are each put into individual vials, each with only one male, giving no choice in who to mate with. Females are then put into egg laying chambers, and a certain number of larvae collected. Do the larvae from the mate choice group exhibit higher survival rates? A study \(^{44}\) published in Nature found that mate choice does increase offspring fitness in fruit flies (with p-value \(<0.02\) ), yet this result went against conventional wisdom in genetics and was quite controversial. Researchers attempted to replicate this result with a series of related experiments, \({ }^{45}\) with data provided in MateChoice. (a) In the first replication experiment, using the same species of fruit fly as the original Nature study, 6067 of the 10000 larvae from the mate choice group survived and 5976 of the 10000 larvae from the no mate choice group survived. Calculate the p-value. (b) Using a significance level of \(\alpha=0.05\) and \(\mathrm{p}\) -value from (a), state the conclusion in context. (c) Actually, the 10,000 larvae in each group came from a series of 50 different runs of the experiment, with 200 larvae in each group for each run. The researchers believe that conditions dif- fer from run to run, and thus it makes sense to treat each \(\mathrm{run}\) as a case (rather than each fly). In this analysis, we are looking at paired data, and the response variable would be the difference in the number of larvae surviving between the choice group and the no choice group, for each of the 50 runs. The counts (Choice and NoChoice and difference (Choice \(-\) NoChoice) in number of surviving larva are stored in MateChoice. Using the single variable of differences, calculate the p-value for testing whether the average difference is greater than \(0 .\) (Hint: this is a single quantitative variable, so the corresponding test would be for a single mean.) (d) Using a significance level of \(\alpha=0.05\) and the p-value from (c), state the conclusion in context. (e) The experiment being tested in parts (a)-(d) was designed to mimic the experiment from the original study, yet the original study yielded significant results while this study did not. If mate choice really does improve offspring fitness in fruit flies, did the follow-up study being analyzed in parts (a)-(d) make a Type I, Type II, or no error? (f) If mate choice really does not improve offspring fitness in fruit flies, did the original Nature study make a Type I, Type II, or no error?

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