Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Could owning a cat as a child be related to mental illness later in life? Toxoplasmosis is a disease transmitted primarily through contact with cat feces, and has recently been linked with schizophrenia and other mental illnesses. Also, people infected with Toxoplasmosis tend to like cats more and are 2.5 times more likely to get in a car accident, due to delayed reaction times. The CDC estimates that about \(22.5 \%\) of Americans are infected with Toxoplasmosis (most have no symptoms), and this prevalence can be as high as \(95 \%\) in other parts of the world. A study \(^{37}\) randomly selected 262 people registered with the National Alliance for the Mentally Ill (NAMI), almost all of whom had schizophrenia, and for each person selected, chose two people from families without mental illness who were the same age, sex, and socioeconomic status as the person selected from NAMI. Each participant was asked whether or not they owned a cat as a child. The results showed that 136 of the 262 people in the mentally ill group had owned a cat, while 220 of the 522 people in the not mentally ill group had owned a cat. (a) This is known as a case-control study, where cases are selected as people with a specific disease or trait, and controls are chosen to be people without the disease or trait being studied. Both cases and controls are then asked about some variable from their past being studied as a potential risk factor. This is particularly useful for studying rare diseases (such as schizophrenia), because the design ensures a sufficient sample size of people with the disease. Can casecontrol studies such as this be used to infer a causal relationship between the hypothesized risk factor (e.g., cat ownership) and the disease (e.g., schizophrenia)? Why or why not? (b) In case-control studies, controls are usually chosen to be similar to the cases. For example, in this study each control was chosen to be the same age, sex, and socioeconomic status as the corresponding case. Why choose controls who are similar to the cases? (c) For this study, calculate the relevant difference in proportions; proportion of cases (those with schizophrenia) who owned a cat as a child minus proportion of controls (no mental illness) who owned a cat as a child. (d) For testing the hypothesis that the proportion of cat owners is higher in the schizophrenic group than the control group, use technology to generate a randomization distribution and calculate the p-value. (e) Do you think this provides evidence that there is an association between owning a cat as a child and developing schizophrenia? \(^{38}\) Why or why not?

Short Answer

Expert verified
Whether there is an association between owning a cat and developing schizophrenia can be inferred based on statistical analysis and will ultimately depend on the calculated p-value. Case-control studies can indicate an association but it cannot definitively determine causality. Further investigations are needed to account for potential confounding variables.

Step by step solution

01

Understanding Case-control Studies

In case-control studies, subjects are selected to have (cases) or not have (controls) a certain condition, in this case mental illness. Information is then gathered about their past exposure to potential risk factors, such as owning a cat. However, this study design cannot definitively determine causal relationships due to potential bias (recall or selection bias) and confounding variables that are not controlled.
02

The Necessity of Similar Controls

Controls are chosen to match the cases in certain other characteristics (age, sex, socioeconomic status in this study) in order to isolate the suspected risk factor and mitigate the effects of confounding variables. This helps to ensure that any observed differences are due to the factor of interest (cat ownership) and not other variables.
03

Calculate the Difference in Proportions

Let's calculate the proportion of cases who owned a cat: \(136/262 = 0.519\). Proportion of controls who owned a cat is: \(220/522 = 0.421\). The difference is then \(0.519 - 0.421 = 0.098\). So, the proportion of cases who owned a cat is 0.098 greater than the proportion of controls.
04

Calculating the p-value

For this step, one would need access to technology to generate a randomization distribution (simulation). This is beyond the scope of this JSON-format answer. The goal is to determine whether the observed difference in proportions could reasonably have occurred by chance under the null hypothesis.
05

Interpretation and Conclusion

Evaluating whether there is an association between owning a cat as a child and developing schizophrenia depends on the calculated p-value. If the p-value is small (less than \(0.05\), for example), one might conclude there is evidence to suggest an association. However, even if there is an association, it does not mean that owning a cat causes schizophrenia. Many other factors may be involved, and further investigation will be needed.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Toxoplasmosis and Mental Illness
Recent studies have sparked interest in the relationship between Toxoplasmosis, an infection mainly transmitted through cat feces, and mental illnesses such as schizophrenia. Toxoplasmosis infects about 22.5% of the American population, but many remain asymptomatic. Intriguingly, the condition is connected to unusual behaviors, such as increased fondness for cats and slowed reaction times, potentially leading to increased car accident risk. The presence of Toxoplasma gondii, the parasite responsible for Toxoplasmosis, in the human brain has led researchers to investigate its potential impact on mental health disorders. While studies suggest a higher prevalence of this parasitic infection among individuals with schizophrenia, a direct causal relationship is not established. A key challenge in such research is distinguishing between correlation and causation, which requires careful statistical analysis and consideration of other risk factors.

Understanding the nuanced relationship between Toxoplasmosis and mental illness is vital, particularly when considering the global variance in Toxoplasmosis prevalence, reaching up to 95% in some regions. These significant differences highlight the importance of context when evaluating potential links between infection and mental health outcomes.
Risk Factors in Mental Illness
Identifying risk factors for mental illness involves an intricate exploration of biological, environmental, social, and psychological influences. A risk factor indicates a higher likelihood of developing a disease but does not guarantee it. For instance, case-control studies like the one exploring cat ownership and schizophrenia aim to uncover potential risk factors by comparing individuals with a mental illness (cases) to those without (controls).

Controls are meticulously selected to match the cases in characteristics such as age, sex, and socioeconomic status. This approach minimizes the effects of confounding factors, allowing researchers to focus on the risk element of interest. Despite such methods, establishing that a factor is a risk for mental illness is complex. Confounding variables and biases, such as recall bias where participants may not accurately remember past exposures, present challenges to determining true risk factors.
Association vs Causality
In medical research, understanding the difference between association and causality is paramount. An association implies a statistical relationship between two variables, such as cat ownership and schizophrenia. However, causality goes further, suggesting that one factor (cat ownership) directly influences the occurrence of another (schizophrenia).

A case-control study, by its design, can typically only establish association, not causality. Factors such as temporal relationships, dose-response, and ruling out alternative explanations must be considered to establish causation. In the cat ownership study, even if a significant association is observed, it does not confirm that owning a cat causes mental illness, as other unmeasured factors could influence the result. Demonstrating causality would require more rigorous designs, such as longitudinal cohort studies and randomized controlled trials, along with consistent findings from multiple studies.
Statistical Analysis in Medical Research
Statistical analysis plays a critical role in medical research, enabling scientists to evaluate hypotheses and draw conclusions from data. In the discussed case-control study, statistical methods are used to compare the proportion of cases with cat ownership in childhood against controls. Calculating differences in proportions and generating a randomization distribution are examples of such analyses.

The p-value, derived from these analyses, helps determine the likelihood of observing the results if there were no true association. A low p-value suggests that the observed association is unlikely to have occurred by chance, thus supporting the existence of an association. However, it's essential to recognize that statistical significance does not equate to clinical or practical relevance, and it does not prove causation. Medical researchers must interpret statistical findings in the broader context of the study design, known risk factors, and biological plausibility to make informed conclusions about health outcomes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Significant and Insignificant Results (a) If we are conducting a statistical test and determine that our sample shows significant results, there are two possible realities: We are right in our conclusion or we are wrong. In each case, describe the situation in terms of hypotheses and/or errors. (b) If we are conducting a statistical test and determine that our sample shows insignificant results, there are two possible realities: We are right in our conclusion or we are wrong. In each case, describe the situation in terms of hypotheses and/or errors. (c) Explain why we generally won't ever know which of the realities (in either case) is correct.

Exercises 4.29 on page 271 and 4.76 on page 287 describe a historical scenario in which a British woman, Muriel BristolRoach, claimed to be able to tell whether milk had been poured into a cup before or after the tea. An experiment was conducted in which Muriel was presented with 8 cups of tea, and asked to guess whether the milk or tea was poured first. Our null hypothesis \(\left(H_{0}\right)\) is that Muriel has no ability to tell whether the milk was poured first. We would like to create a randomization distribution for \(\hat{p},\) the proportion of cups out of 8 that Muriel guesses correctly under \(H_{0}\). Describe a possible approach to generate randomization samples for each of the following scenarios: (a) Muriel does not know beforehand how many cups have milk poured first. (b) Muriel knows that 4 cups will have milk poured first and 4 will have tea poured first.

How influenced are consumers by price and marketing? If something costs more, do our expectations lead us to believe it is better? Because expectations play such a large role in reality, can a product that costs more (but is in reality identical) actually be more effective? Baba Shiv, a neuroeconomist at Stanford, conducted a study \(^{25}\) involving 204 undergraduates. In the study, all students consumed a popular energy drink which claims on its packaging to increase mental acuity. The students were then asked to solve a series of puzzles. The students were charged either regular price ( \(\$ 1.89\) ) for the drink or a discount price \((\$ 0.89)\). The students receiving the discount price were told that they were able to buy the drink at a discount since the drinks had been purchased in bulk. The authors of the study describe the results: "the number of puzzles solved was lower in the reduced-price condition \((M=4.2)\) than in the regular-price condition \((M=5.8) \ldots p<.0001 . "\) (a) What can you conclude from the study? How strong is the evidence for the conclusion? (b) These results have been replicated in many similar studies. As Jonah Lehrer tells us: "According to Shiv, a kind of placebo effect is at work. Since we expect cheaper goods to be less effective, they generally are less effective, even if they are identical to more expensive products. This is why brand-name aspirin works better than generic aspirin and why Coke tastes better than cheaper colas, even if most consumers can't tell the difference in blind taste tests."26 Discuss the implications of this research in marketing and pricing.

Do you think that students undergo physiological changes when in potentially stressful situations such as taking a quiz or exam? A sample of statistics students were interrupted in the middle of a quiz and asked to record their pulse rates (beats for a 1-minute period). Ten of the students had also measured their pulse rate while sitting in class listening to a lecture, and these values were matched with their quiz pulse rates. The data appear in Table 4.18 and are stored in QuizPulse10. Note that this is paired data since we have two values, a quiz and a lecture pulse rate, for each student in the sample. The question of interest is whether quiz pulse rates tend to be higher, on average, than lecture pulse rates. (Hint: Since this is paired data, we work with the differences in pulse rate for each student between quiz and lecture. If the differences are \(D=\) quiz pulse rate minus lecture pulse rate, the question of interest is whether \(\mu_{D}\) is greater than zero.) Table 4.18 Quiz and Lecture pulse rates for I0 students $$\begin{array}{lcccccccccc} \text { Student } & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 \\ \hline \text { Quiz } & 75 & 52 & 52 & 80 & 56 & 90 & 76 & 71 & 70 & 66 \\\ \text { Lecture } & 73 & 53 & 47 & 88 & 55 & 70 & 61 & 75 & 61 & 78 \\\\\hline\end{array}$$ (a) Define the parameter(s) of interest and state the null and alternative hypotheses. (b) Determine an appropriate statistic to measure and compute its value for the original sample. (c) Describe a method to generate randomization samples that is consistent with the null hypothesis and reflects the paired nature of the data. There are several viable methods. You might use shuffled index cards, a coin, or some other randomization procedure. (d) Carry out your procedure to generate one randomization sample and compute the statistic you chose in part (b) for this sample. (e) Is the statistic for your randomization sample more extreme (in the direction of the alternative) than the original sample?

Influencing Voters: Is a Phone Call More Effective? Suppose, as in Exercise \(4.38,\) that we wish to compare methods of influencing voters to support a particular candidate, but in this case we are specifically interested in testing whether a phone call is more effective than a flyer. Suppose also that our random sample consists of only 200 voters, with 100 chosen at random to get the flyer and the rest getting a phone call. (a) State the null and alternative hypotheses in this situation. (b) Display in a two-way table possible sample results that would offer clear evidence that the phone call is more effective. (c) Display in a two-way table possible sample results that offer no evidence at all that the phone call is more effective. (d) Display in a two-way table possible sample results for which the outcome is not clear: there is some evidence in the sample that the phone call is more effective but it is possibly only due to random chance and likely not strong enough to generalize to the population.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free