Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Effect of Overeating for One Month: Average Long-Term Weight Gain Overeating for just four weeks can increase fat mass and weight over two years later, a Swedish study shows \(^{35}\) Researchers recruited 18 healthy and normal-weight people with an average age of \(26 .\) For a four-week period, participants increased calorie intake by \(70 \%\) (mostly by eating fast food) and limited daily activity to a maximum of 5000 steps per day (considered sedentary). Not surprisingly, weight and body fat of the participants went up significantly during the study and then decreased after the study ended. Participants are believed to have returned to the diet and lifestyle they had before the experiment. However, two and a half years after the experiment, the mean weight gain for participants was 6.8 lbs with a standard error of 1.2 lbs. A control group that did not binge had no change in weight. (a) What is the relevant parameter? (b) How could we find the actual exact value of the parameter? (c) Give a \(95 \%\) confidence interval for the parameter and interpret it. (d) Give the margin of error and interpret it.

Short Answer

Expert verified
a) The relevant parameter is the long-term average weight gain.\nb) The actual exact value of the parameter can theoretically be found by measuring the weight gain of all individuals who overeat for a month.\nc) The 95% confidence interval of the weight gain is \(6.8 \pm 1.96*1.2\) lbs.\nd) The margin of error is \(1.96 * 1.2\) lbs. It indicates the range within which the true mean weight gain would fall 95% of the time if the study were repeated many times.

Step by step solution

01

Identify the Relevant Parameter

The relevant parameter for this study is the long-term weight gain of the participants. Parameter is a quantity that is a property of the population that is being studied. In this case, they are interested in how much weight on average a person will gain if they overeat for a month. The mean weight gain reported for participants after two and a half years is 6.8 lbs.
02

Finding the Actual Exact Value of the Parameter

The actual exact value of this parameter would require data from all individuals who have overeaten for a month to see how that affects their weight gain over the long term. In reality, this is nearly impossible because it would require measuring the weight gain of every single individual who overeats for a month, which is unfeasible. Therefore, we use the sample data (e.g., the 18 healthy and normal-weight people in the study) as a way to estimate the parameter of interest. The mean weight gain reported in the study is an estimate of the parameter.
03

Calculate the 95% Confidence Interval for the Parameter

A 95% confidence interval can be calculated using the formula \(confidence \, interval = sample \, mean \pm Z * SE \), where \(Z\) is the Z-value from the standard normal distribution corresponding to the desired level of confidence (1.96 for 95% confidence) and \(SE\) is the standard error. The standard error is given as 1.2 lbs. Therefore, the confidence interval is \(6.8 \pm 1.96*1.2\).
04

Calculate the Margin of Error and Interpret It

The margin of error for the 95% confidence level can be calculated using the formula \(MOE = Z * SE \). Using the values from the previous step, \(MOE = 1.96 * 1.2\). The margin of error indicates how much uncertainty there is in our estimate of the parameter. It says that if we were to repeat the study many times, then 95% of the time the average weight gain would fall within this interval.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Give information about the proportion of a sample that agrees with a certain statement. Use StatKey or other technology to estimate the standard error from a bootstrap distribution generated from the sample. Then use the standard error to give a \(95 \%\) confidence interval for the proportion of the population to agree with the statement. StatKey tip: Use "CI for Single Proportion" and then "Edit Data" to enter the sample information. In a random sample of 400 people, 112 agree and 288 disagree.

In Exercises 3.51 to 3.56 , information about a sample is given. Assuming that the sampling distribution is symmetric and bell-shaped, use the information to give a \(95 \%\) confidence interval, and indicate the parameter being estimated. $$ r=0.34 \text { and the standard error is } 0.02 \text { . } $$

Adolescent Brains Are Different Researchers continue to find evidence that brains of adolescents behave quite differently than either brains of adults or brains of children. In particular, adolescents seem to hold on more strongly to fear associations than either children or adults, suggesting that frightening connections made during the teen years are particularly hard to unlearn. In one study, \({ }^{25}\) participants first learned to associate fear with a particular sound. In the second part of the study, participants heard the sound without the fear-causing mechanism, and their ability to "unlearn" the connection was measured. A physiological measure of fear was used, and larger numbers indicate less fear. We are estimating the difference in mean response between adults and teenagers. The mean response for adults in the study was 0.225 and the mean response for teenagers in the study was \(0.059 .\) We are told that the standard error of the estimate is 0.091 . (a) Give notation for the quantity being estimated. (b) Give notation for the quantity that gives the best estimate, and give its value. (c) Give a \(95 \%\) confidence interval for the quantity being estimated. (d) Is this an experiment or an observational study?

How Many Apps for Your Smartphone? Exercise 3.20 describes a study about smartphone users in the US downloading apps for their smartphone. Of the \(n=355\) smartphone users who had downloaded an app, the average number of apps downloaded was 19.7 (a) Give notation for the parameter of interest, and define the parameter in this context. (b) Give notation for the quantity that gives the best estimate and give its value. (c) What would we have to do to calculate the parameter exactly?

Do You Find Solitude Distressing? "For many people, being left alone with their thoughts is a most undesirable activity," says a psychologist involved in a study examining reactions to solitude. \({ }^{26}\) In the study, 146 college students were asked to hand over their cell phones and sit alone, thinking, for about 10 minutes. Afterward, 76 of the participants rated the experience as unpleasant. Use this information to estimate the proportion of all college students who would find it unpleasant to sit alone with their thoughts. (This reaction is not limited to college students: in a follow-up study involving adults ages 18 to 77 , a similar outcome was reported.) (a) Give notation for the quantity being estimated, and define any parameters used. (b) Give notation for the quantity that gives the best estimate, and give its value. (c) Give a \(95 \%\) confidence interval for the quantity being estimated, given that the margin of error for the estimate is \(8 \%\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free