Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

What Proportion Believe in One True Love? In Data 2.1 on page 48 , we describe a study in which a random sample of 2625 US adults were asked whether they agree or disagree that there is "only one true love for each person." The study tells us that 735 of those polled said they agree with the statement. The standard error for this sample proportion is \(0.009 .\) Define the parameter being estimated, give the best estimate, the margin of error, and find and interpret a \(95 \%\) confidence interval.

Short Answer

Expert verified
The parameter being estimated is the proportion of all US adults who believe in 'only one true love for each person'. The best estimate of this parameter is 0.28 or 28%. The margin of error for this estimate is 0.018 or 1.8%. Thus, a 95% confidence interval for the proportion of all US adults who agree with the statement is from 26.2% to 29.8%.

Step by step solution

01

Defining the Parameter

The parameter being estimated in this problem is the proportion of all US adults who believe that 'there is only one true love for each person'.
02

Calculating the Best Estimate

The best estimate of the parameter is the sample proportion, \(p\). We can calculate this by dividing the number of people who agreed with the statement (735) by the total number of people surveyed (2625). So, \(p = 735 / 2625 = 0.28\). This suggests that 28% of the surveyed population agree with the statement.
03

Computing the Margin of Error

The margin of error can be calculated using the formula for a 95% confidence interval, which is ± 1.96 times the standard error. Given that the standard error, \(SE\), is 0.009, our margin of error is \(1.96*SE = 1.96*0.009 = 0.018\). This gives us a margin of error of 0.018 or 1.8%.
04

Constructing and Interpreting a 95% Confidence Interval

A 95% confidence interval is constructed around the best estimate and extends the margin of error on either side. The lower limit of the confidence interval will be \(p - error = 0.28 - 0.018 = 0.262\) and the upper limit will be \(p + error = 0.28 + 0.018 = 0.298\). So, we are 95% confident that the true proportion of all US adults who agree with the statement falls between 26.2% and 29.8%.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Gender in the Rock and Roll Hall of Fame From its founding through \(2015,\) the Rock and Roll Hall of Fame has inducted 303 groups or individuals. Forty-seven of the inductees have been female or have included female members. \(^{20}\) The full dataset is available in RockandRoll. (a) What proportion of inductees have been female or have included female members? Use the correct notation with your answer. (b) If we took many samples of size 50 from the population of all inductees and recorded the proportion female or with female members for each sample, what shape do we expect the distribution of sample proportions to have? Where do we expect it to be centered?

Many Europeans Don't Recognize Signs of Stroke or Heart Attack Across nine European countries in a large-scale survey, people had a hard time identifying signs of a stroke or heart attack. The survey \(^{51}\) included 10,228 inhabitants of Austria, France, Germany, Italy, the Netherlands, Poland, Russia, Spain, and the United Kingdom. Participants ages ranged from 14 to 98 . Of those surveyed, less than half (4910) linked arm or shoulder pain to heart attacks. Use StatKey to find and interpret a \(99 \%\) confidence interval for the proportion of Europeans (from these nine countries) who can identify arm or shoulder pain as a symptom of a heart attack. Can we be \(99 \%\) confident that the proportion is less than half?

Standard Deviation of NHL Penalty Minutes Exercise 3.102 describes data on the number of penalty minutes for Ottawa Senators NHL players. The sample has a fairly large standard deviation, \(s=27.3\) minutes. Use StatKey or other technology to create a bootstrap distribution, estimate the standard error, and give a \(95 \%\) confidence interval for the standard deviation of penalty minutes for NHL players. Assume that the data in OttawaSenators can be viewed as a reasonable sample of all NHL players.

In Exercises 3.51 to 3.56 , information about a sample is given. Assuming that the sampling distribution is symmetric and bell-shaped, use the information to give a \(95 \%\) confidence interval, and indicate the parameter being estimated. \(\bar{x}_{1}-\bar{x}_{2}=3.0\) and the margin of error for \(95 \%\) confidence is 1.2

Moose Drool Makes Grass More Appetizing Different species can interact in interesting ways. One type of grass produces the toxin ergovaline at levels about 1.0 part per million in order to keep grazing animals away. However, a recent study \(^{27}\) has found that the saliva from a moose counteracts these toxins and makes the grass more appetizing (for the moose). Scientists estimate that, after treatment with moose drool, mean level of the toxin ergovaline (in ppm) on the grass is \(0.183 .\) The standard error for this estimate is 0.016 . (a) Give notation for the quantity being estimated, and define any parameters used. (b) Give notation for the quantity that gives the best estimate, and give its value. (c) Give a \(95 \%\) confidence interval for the quantity being estimated. Interpret the interval in context.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free