Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Give the correct notation for the quantity described and give its value. Proportion of families in the US who were homeless in 2010 . The number of homeless families \(^{5}\) in 2010 was about 170,000 while the total number of families is given in the 2010 Census as 78 million.

Short Answer

Expert verified
The notation for the quantity described is \(P = \frac{170000}{78000000}\) and its value is approximately 0.00218.

Step by step solution

01

Understanding the definition of proportion

Proportion is a type of ratio that compares a part to a whole. It is a relational value that shows how the number of specific instances (in this case, the number of homeless families) relates to the total number of instances (total number of families). In mathematical terms, the proportion can be expressed as: Proportion = (Part/Whole)
02

Conversion of millions to actual numbers

To have a consistent unit for the calculation, we need to convert 78 million families to its numerical equivalent. One million is equal to \(10^6\), so 78 million is equal to \(78 \times 10^6\) = 78,000,000
03

Calculation of the Proportion

Now we calculate the proportion of homeless families to the total families: Proportion = (170,000/78,000,000)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Exercises 3.49 and 3.50 , a \(95 \%\) confidence interval is given, followed by possible values of the population parameter. Indicate which of the values are plausible values for the parameter and which are not. A \(95 \%\) confidence interval for a mean is 112.1 to \(128.2 .\) Is the value given a plausible value of \(\mu ?\) (a) \(\mu=121\) (b) \(\mu=113.4\) (c) \(\mu=105.3\)

Have You Ever Been Arrested? According to a recent study of 7335 young people in the US, \(30 \%\) had been arrested \(^{28}\) for a crime other than a traffic violation by the age of 23. Crimes included such things as vandalism, underage drinking, drunken driving, shoplifting, and drug possession. (a) Is the \(30 \%\) a parameter or a statistic? Use the correct notation. (b) Use the information given to estimate a parameter, and clearly define the parameter being estimated. (c) The margin of error for the estimate in part (b) is \(0.01 .\) Use this information to give a range of plausible values for the parameter. (d) Given the margin of error in part (c), if we asked all young people in the US if they have ever been arrested, is it likely that the actual proportion is less than \(25 \% ?\)

To create a confidence interval from a bootstrap distribution using percentiles, we keep the middle values and chop off a certain percent from each tail. Indicate what percent of values must be chopped off from each tail for each confidence level given. (a) \(95 \%\) (b) \(90 \%\) (c) \(98 \%\) (d) \(99 \%\)

Use data from a study designed to examine the effect of doing synchronized movements (such as marching in step or doing synchronized dance steps) and the effect of exertion on many different variables, such as pain tolerance and attitudes toward others. In the study, 264 high school students in Brazil were randomly assigned to one of four groups reflecting whether or not movements were synchronized (Synch= yes or no) and level of activity (Exertion= high or low). \(^{49}\) Participants rated how close they felt to others in their group both before (CloseBefore) and after (CloseAfter) the activity, using a 7-point scale (1=least close to \(7=\) most close ). Participants also had their pain tolerance measured using pressure from a blood pressure cuff, by indicating when the pressure became too uncomfortable (up to a maximum pressure of \(300 \mathrm{mmHg}\) ). Higher numbers for this Pain Tolerance measure indicate higher pain tolerance. The full dataset is available in SynchronizedMovement. For each of the following problems: (a) Give notation for the quantity we are estimating, and define any relevant parameters. (b) Use StatKey or other technology to find the value of the sample statistic. Give the correct notation with your answer. (c) Use StatKey or other technology to find the standard error for the estimate. (d) Use the standard error to give a \(95 \%\) confidence interval for the quantity we are estimating. (e) Interpret the confidence interval in context. Does Exertion Boost Pain Tolerance? Use the pain tolerance ratings after the activity to estimate the difference in mean pain tolerance between those who just completed a high exertion activity and those who completed a low exertion activity.

Average Salary of NFL Players The dataset NFLContracts2015 contains the yearly salary (in millions of dollars) from the contracts of all players on a National Football League (NFL) roster at the start of the 2015 season. \({ }^{19}\) (a) Use StatKey or other technology to select a random sample of 5 NFL contract YearlySalary values. Indicate which players you've selected and compute the sample mean. (b) Repeat part (a) by taking a second sample of 5 values, again indicating which players you selected and computing the sample mean. (c) Find the mean for the entire population of players. Include notation for this mean. Comment on the accuracy of using the sample means found in parts (a) and (b) to estimate the population mean.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free