Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

What Proportion of Adults and Teens Text Message? A study of \(n=2252\) adults age 18 or older found that \(72 \%\) of the cell phone users send and receive text messages. \({ }^{15}\) A study of \(n=800\) teens age 12 to 17 found that \(87 \%\) of the teen cell phone users send and receive text messages. What is the best estimate for the difference in the proportion of cell phone users who use text messages, between adults (defined as 18 and over) and teens? Give notation (as a difference with a minus sign) for the quantity we are trying to estimate, notation for the quantity that gives the best estimate, and the value of the best estimate. Be sure to clearly define any parameters in the context of this situation.

Short Answer

Expert verified
The estimated difference in the proportion of adults and teens who text is -0.15 (-indicating a higher proportion of teens). The target quantity is denoted as \( D = P_{a} - P_{t} \) and the best estimate for this quantity is denoted as \( d = p_{a} - p_{t} \), with \( p_{a} = 0.72 \) and \( p_{t} = 0.87 \) being the observed sample proportions of adults and teens respectively.

Step by step solution

01

Identify the Variables

We have two variables to consider: the proportion of adults and the proportion of teens who send and receive text messages. Let's denote the population proportion of adults who text as \( P_{a} \) and the population proportion of teens who text as \( P_{t} \). Our goal is to estimat1e the difference \( D = P_{a} - P_{t} \). The given data provides us with estimates for these proportions, known as sample proportions: for adults, \( p_{a} = 0.72 \), and for teens, \( p_{t} = 0.87 \).
02

Calculate the Difference in Proportions

To estimate the difference between the two proportions, we simply subtract the sample proportion of the adults from the sample proportion of the teens. This results in the sample estimate of the difference \( d = p_{a} - p_{t} = 0.72 - 0.87 = -0.15 \). This negative value indicates that the proportion of teens who text is higher than the proportion of adults who text.
03

Explain the Notations and the Parameters

Let's now clarify the notations: \( P_{a} \) and \( P_{t} \) are the population proportions of adults and teens (respectively) who use text messages -- these are parameters we'd like to know, but don't have enough information to find exactly. \( p_{a} = 0.72 \) and \( p_{t} = 0.87 \) are the sample proportions of adults and teens who text -- these are estimates based on the sample data. \( D = P_{a} - P_{t} \) is the difference in population proportions, and \( d = -0.15 \) is the observed difference in sample proportions -- this is our best estimate for D in this situation.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

SKILL BUILDER 2 In Exercises 3.45 to 3.48 , construct an interval giving a range of plausible values for the given parameter using the given sample statistic and margin of error. For \(\mu,\) using \(\bar{x}=25\) with margin of error 3 .

What Proportion Believe in One True Love? In Data 2.1 on page 48 , we describe a study in which a random sample of 2625 US adults were asked whether they agree or disagree that there is "only one true love for each person." The study tells us that 735 of those polled said they agree with the statement. The standard error for this sample proportion is \(0.009 .\) Define the parameter being estimated, give the best estimate, the margin of error, and find and interpret a \(95 \%\) confidence interval.

\(\mathbf{3 . 1 2 3}\) What Proportion Have Pesticides Detected? In addition to the quantitative variable pesticide concentration, the researchers also report whether or not the pesticide was detected in the urine (at standard detection levels). Before the participants started eating organic, 111 of the 240 measurements (combining all pesticides and people) yielded a positive pesticide detection. While eating organic, only 24 of the 240 measurements resulted in a positive pesticide detection. (a) Calculate the sample difference in proportions: proportion of measurements resulting in pesticide detection while eating non- organic minus proportion of measurements resulting in pesticide detection while eating organic. (b) Figure 3.33 gives a bootstrap distribution for the difference in proportions, based on \(1000 \mathrm{sim}-\) ulated bootstrap samples. Approximate a \(98 \%\) confidence interval. (c) Interpret this interval in context.

Downloading Apps for Your Smartphone A random sample of \(n=461\) smartphone users in the US in January 2015 found that 355 of them have downloaded an app. \(^{10}\) (a) Give notation for the parameter of interest, and define the parameter in this context. (b) Give notation for the quantity that gives the best estimate and give its value. (c) What would we have to do to calculate the parameter exactly?

Have You Ever Been Arrested? According to a recent study of 7335 young people in the US, \(30 \%\) had been arrested \(^{28}\) for a crime other than a traffic violation by the age of 23. Crimes included such things as vandalism, underage drinking, drunken driving, shoplifting, and drug possession. (a) Is the \(30 \%\) a parameter or a statistic? Use the correct notation. (b) Use the information given to estimate a parameter, and clearly define the parameter being estimated. (c) The margin of error for the estimate in part (b) is \(0.01 .\) Use this information to give a range of plausible values for the parameter. (d) Given the margin of error in part (c), if we asked all young people in the US if they have ever been arrested, is it likely that the actual proportion is less than \(25 \% ?\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free