Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In Exercises \(\mathrm{P} .95\) to \(\mathrm{P} .99,\) determine whether the process describes a binomial random variable. If it is binomial, give values for \(n\) and \(p .\) If it is not binomial, state why not. Worldwide, the proportion of babies who are boys is about 0.51 . We randomly sample 100 babies born and count the number of boys.

Short Answer

Expert verified
This process describes a binomial random variable. The number of trials \(n\) is 100 and the probability of success \(p\) is 0.51.

Step by step solution

01

Determine the fixed number of trials

In the given scenario, 100 babies are randomly sampled. So, the number of trials is fixed and defined as \(n=100\).
02

Determine the success and failure

The scenario deals with determining the gender of babies which has only two possible outcomes - either the baby is a boy (success) or not (failure). Hence, the second condition of a binomial process is also satisfied.
03

Verify the independence of trials

Since the births of individuals are independent events, selecting one baby does not affect the probability of the gender of the next baby. Thus, the trials are independent.
04

Check uniform probability of success

The problem states that the global proportion of male babies is approximately 0.51. This probability remains the same for every birth, satisfying the fourth condition of a binomial process. Hence, the probability of success is defined as \(p=0.51\).
05

Final evaluation

Since all four conditions for a binomial process are met, we can conclude that the described scenario represents a binomial random variable.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Heights of Men in the US Heights of adult males in the US are approximately normally distributed with mean 70 inches \((5 \mathrm{ft} 10 \mathrm{in})\) and standard deviation 3 inches. (a) What proportion of US men are between \(5 \mathrm{ft}\) 8 in and \(6 \mathrm{ft}\) tall \((68\) and 72 inches, respectively)? (b) If a man is at the 10 th percentile in height, how tall is he?

Getting to the Finish In a certain board game participants roll a standard six-sided die and need to hit a particular value to get to the finish line exactly. For example, if Carol is three spots from the finish, only a roll of 3 will let her win; anything else and she must wait another turn to roll again. The chance of getting the number she wants on any roll is \(p=1 / 6\) and the rolls are independent of each other. We let a random variable \(X\) count the number of turns until a player gets the number needed to win. The possible values of \(X\) are \(1,2,3, \ldots\) and the probability function for any particular count is given by the formula $$ P(X=k)=p(1-p)^{k-1} $$ (a) Find the probability a player finishes on the third turn. (b) Find the probability a player takes more than three turns to finish.

Approximately \(7 \%\) of men and \(0.4 \%\) of women are red-green color-blind (as in Exercise P.38). Assume that a statistics class has 15 men and 25 women. (a) What is the probability that nobody in the class is red-green color-blind? (b) What is the probability that at least one person in the class is red-green color-blind? (c) If a student from the class is selected at random, what is the probability that he or she will be redgreen color-blind?

Mean and Standard Deviation of a Proportion To find the proportion of times something occurs, we divide the count (often a binomial random variable) by the number of trials \(n\). Using the formula for the mean and standard deviation of a binomial random variable, derive the mean and standard deviation of a proportion resulting from \(n\) trials and probability of success \(p\).

Owner-Occupied Housing Units In the 2010 US Census, we learn that \(65 \%\) of all housing units are owner-occupied while the rest are rented. If we take a random sample of 20 housing units, find the probability that: (a) Exactly 15 of them are owner-occupied (b) 18 or more of them are owner-occupied

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free