Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In Exercises \(\mathrm{P} .74\) to \(\mathrm{P} .77\), fill in the \(?\) to make \(p(x)\) a probability function. If not possible, say so. $$ \begin{array}{lcccc} \hline x & 10 & 20 & 30 & 40 \\ \hline p(x) & 0.2 & 0.2 & ? & 0.2 \\ \hline \end{array} $$

Short Answer

Expert verified
The missing probability value at x=30 should be 0.4 to make \(p(x)\) a valid probability function.

Step by step solution

01

Sum the known probabilities

Firstly, sum up all known probabilities given in the table, which include 0.2 at x=10, 0.2 at x=20, and 0.2 at x=40 which totals to 0.6.
02

Calculate the unknown probability

Since the total probability must equal to 1 under the axiom of probability, you subtract the sum of known probabilities from 1 to find the missing probability:\n 1 - 0.6 = 0.4\n Therefore, the missing probability value for x=30 is 0.4.
03

Check the conditions of probability

Finally, check the two conditions of probability with this filled value. Here, the computed probability value for x=30 is not negative, so it satisfies the 1st condition. Moreover, if we add up all probabilities in the table now, it equals to 1 which satisfies the 2nd condition. Therefore, these values make \(p(x)\) a valid probability function.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free