Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

State whether the two events (A and B) described are disjoint, independent, and/or complements. (It is possible that the two events fall into more than one of the three categories, or none of them.) South Africa plays Australia for the championship in the Rugby World Cup. Let \(\mathrm{A}\) be the event that Australia wins and \(\mathrm{B}\) be the event that South Africa wins. (The game cannot end in a tie.)

Short Answer

Expert verified
Event A and Event B are disjoint and complementary, but not independent.

Step by step solution

01

- Identify disjoint events

Two events are disjoint if they can't happen at the same time. Here, Australia and South Africa can't both win the game at the same time. That means these events are disjoint.
02

- Identify independent events

Two events are independent if the occurrence of one doesn't affect the likelihood of the other. Since there can be only one winner, if Australia wins (Event A), South Africa cannot win (Event B). So, Event A and Event B are not independent.
03

- Identify Complement Events

Two events are said to be complementary if the occurrence of one implies the non-occurrence of the other. Here, if Australia wins (Event A) it means South Africa (Event B) doesn't win and vice versa. Hence, these two events are complementary.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Disjoint Events
Disjoint events are like oil and water; they don't mix. In probability, when we talk about disjoint events, we mean occurrences that cannot happen at the same time. Think of it as being exclusive. For example, consider flipping a coin. You can get heads or tails, but not both at once. Similarly, when a rugby match between Australia and South Africa is played without the possibility of a draw, only one team can be victor. If Australia wins, South Africa can't, making these two outcomes disjoint events.

Disjoint events always have one thing in common: their intersection (the probability of both events happening together) is zero. Mathematically, we represent it as: \( P(A \cap B) = 0 \) where \( A \) and \( B \) are two disjoint events. Understanding this concept helps you predict outcomes when you're dealing with exclusive scenarios in games, experiments, or real-life situations.
Independent Events
Now imagine you have two light switches. Turning one on or off has no bearing on whether the other is on or off. Independent events work much the same. In probability, two events are independent if the occurrence (or non-occurrence) of one has no effect on the other. This concept is fundamental in scenarios where multiple outcomes don't interfere with each other.

To check for independence, we look at the probabilities: if \( P(A \text{ given } B) = P(A) \) and \( P(B \text{ given } A) = P(B) \) then \( A \) and \( B \) are independent. But remember, during the Rugby World Cup game between Australia and South Africa, one team's victory completely determines the other team's defeat; hence, their chances of winning are not independent. Knowing helping you to understand when one occurrence doesn't necessarily predict another.
Complement Events
Complement events behave like two sides of the same coin. In probability, the complement of event \( A \) is the event that \( A \) does not occur, often denoted by \( A^c \). Think of it as a 'totally or nothing' situation. When it comes to our Rugby game, Australia winning is the complement of South Africa not winning, and vice versa. One complements the other to make up all possible outcomes.

Here's the trick: The probabilities of an event and its complement always add up to 1 (or 100%). So, if you know the probability of Australia winning, \( P(A) \), the probability of them not winning (South Africa winning or event \( B \)) is \( 1 - P(A) \). This is incredibly useful for calculating probabilities quickly, especially in 'either-or' scenarios. Complement events give us a full picture of the possible outcomes in a given situation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For Exercises \(\mathrm{P} .27\) to \(\mathrm{P} .30,\) state whether the two events (A and B) described are disjoint, independent, and/or complements. (It is possible that the two events fall into more than one of the three categories, or none of them.) Draw three skittles (possible colors: yellow, green, red, purple, and orange) from a bag. Let A be the event that all three skittles are green and \(\mathrm{B}\) be the event that at least one skittle is red.

Empirical Rule for Normal Distributions Pick any positive values for the mean and the standard deviation of a normal distribution. Use your selection of a normal distribution to answer the questions below. The results of parts (a) to (c) form what is often called the Empirical Rule for the standard deviation in a normal distribution. (a) Verify that about \(95 \%\) of the values fall within two standard deviations of the mean. (b) What proportion of values fall within one standard deviation of the mean? (c) What proportion of values fall within three standard deviations of the mean? (d) Will the answers to (b) and (c) be the same for any normal distribution? Explain why or why not.

In Exercises \(\mathrm{P} .112\) to \(\mathrm{P} .115,\) calculate the mean and standard deviation of the binomial random variable. A binomial random variable with } n=10 \text { and }\\\ &p=0.8 \end{aligned} $$

Use the information that, for events \(\mathrm{A}\) and \(\mathrm{B}\), we have \(P(A)=0.8, P(B)=0.4\), and \(P(A\) and \(B)=0.25.\) Are events A and B independent?

Curving Grades on an Exam A statistics instructor designed an exam so that the grades would be roughly normally distributed with mean \(\mu=75\) and standard deviation \(\sigma=10 .\) Unfortunately, a fire alarm with ten minutes to go in the exam made it difficult for some students to finish. When the instructor graded the exams, he found they were roughly normally distributed, but the mean grade was 62 and the standard deviation was 18\. To be fair, he decides to "curve" the scores to match the desired \(N(75,10)\) distribution. To do this, he standardizes the actual scores to \(z\) -scores using the \(N(62,18)\) distribution and then "unstandardizes" those \(z\) -scores to shift to \(N(75,10)\). What is the new grade assigned for a student whose original score was 47 ? How about a student who originally scores a \(90 ?\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free