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Use the fact that we have independent events \(\mathrm{A}\) and \(\mathrm{B}\) with \(P(A)=0.7\) and \(P(B)=0.6\). Find \(P(A\) and \(B)\).

Short Answer

Expert verified
The probability of both events A and B occurring, \(P(A \text{ and } B)\) is 0.42

Step by step solution

01

Understand the given probabilities

We are given that the probability of event A, denoted by \(P(A)\), is 0.7 and the probability of B, denoted by \(P(B)\), is 0.6.
02

Confirm that the events are independent

The problem states that events A and B are independent. Thus, the occurrence or nonoccurrence of event A doesn't affect the probability of event B, and vice versa.
03

Apply the rule for independent events

The rule for independent events states that the probability of both events A and B happening, denoted by \(P(A \text{ and } B)\), is equal to the probability of event A multiplied by the probability of event B. We write this as \(P(A \text{ and } B) = P(A)*P(B)\)
04

Calculate \(P(A \text{ and } B)\)

By substituting our known probabilities into the equation from step 3, we get \(P(A \text{ and } B) = 0.7 * 0.6 = 0.42\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory lies at the heart of many scientific disciplines, offering a formal framework to predict the likelihood of events. It is a branch of mathematics that deals with calculating the chances of a specific outcome. In essence, it helps us quantify uncertainty. Understanding probability can assist in making informed decisions based on the likelihood of various outcomes.

For instance, suppose a weather forecast indicates a 70% chance of rain tomorrow (\(P(\text{{Rain}}) = 0.7\)). This percentage reflects the probability theory in action, providing a measure of how likely it is to rain. The theory accommodates outcomes ranging from the most certain (with probability 1 or 100%) to the impossible (with probability 0 or 0%).

Within the study of probability, events can be classified in multiple ways, such as independent events, which do not influence each other, and dependent events, where the outcome of one can affect the outcome of another. This classification is crucial for applying the correct rules when calculating probabilities.
Independent Events Rule
The independent events rule is a critical concept within probability theory, particularly when considering the relationship between two or more events. Two events are said to be independent if the occurrence of one event does not affect the occurrence of the other. In other words, the outcome of one event gives no information about the other.

For example, when flipping a coin and rolling a die, the result of the coin toss (heads or tails) has no impact on what number the die will land on. This is a classic case of independence between two events. Recognizing when events are independent is essential because it allows us to apply a simplified method of calculating the combined probability of these events occurring. If we improperly assume independence, our probability calculations could lead to incorrect conclusions.

Independent events often appear in various real-world scenarios, such as the probability of drawing an ace from a deck of cards and then rolling a six on a die, where both events do not interfere with each other's outcomes.
Probability Multiplication Rule
The probability multiplication rule is a fundamental concept when dealing with independent events. It states that the probability of two independent events occurring together (concurrently) is equal to the product of their separate probabilities.

To apply this rule, we use the formula: \
\[P(A \text{ and } B) = P(A) \times P(B)\]
where \(P(A)\) and \(P(B)\) are the probabilities of events A and B happening individually. Returning to our textbook example, since events A and B are independent with probabilities 0.7 and 0.6 respectively, we simply multiply these probabilities to get \(P(A \text{ and } B) = 0.7 \times 0.6 = 0.42\).

This approach allows for a streamlined calculation when dealing with independent events, avoiding more complex probability methods needed for dependent events. It's a powerful tool for predicting the likelihood of multiple events occurring in tandem, and is widely used across different fields such as statistics, gambling, finance, and risk assessment.

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Most popular questions from this chapter

Owner-Occupied Household Size Table P.11 gives the probability function for the random variable \(^{14}\) giving the household size for an owneroccupied housing unit in the US. \({ }^{15}\) (a) Verify that the sum of the probabilities is 1 (up to round-off error). (b) What is the probability that a unit has only one or two people in it? (c) What is the probability that a unit has five or more people in it? \begin{tabular}{lccccccc} \hline\(x\) & 1 & 2 & 3 & 4 & 5 & 6 & 7 \\ \hline\(p(x)\) & 0.217 & 0.363 & 0.165 & 0.145 & 0.067 & 0.026 & 0.018 \\ \hline \end{tabular} (d) What is the probability that more than one person lives in a US owner- occupied housing unit?

Owner-Occupied Housing Units In the 2010 US Census, we learn that \(65 \%\) of all housing units are owner-occupied while the rest are rented. If we take a random sample of 20 housing units, find the probability that: (a) Exactly 15 of them are owner-occupied (b) 18 or more of them are owner-occupied

Writing on the SAT Exam In Table P.16 with Exercise P.157, we see that scores on the Writing portion of the SAT (Scholastic Aptitude Test) exam are normally distributed with mean 484 and standard deviation \(115 .\) Use the normal distribution to answer the following questions: (a) What is the estimated percentile for a student who scores 450 on Writing? (b) What is the approximate score for a student who is at the 90 th percentile for Writing?

Each of the following statements demonstrate a common misuse of probability. Explain what is wrong with each statement: (a) Approximately \(10 \%\) of adults are left-handed. So, if we take a simple random sample of 10 adults, 1 of them will be left-handed. (b) A pitch in baseball can be called a ball or a strike or can be hit by the batter. As there are three possible outcomes, the probability of each is \(1 / 3\). (c) The probability that a die lands with a 1 face up is \(1 / 6 .\) So, since rolls of the die are independent, the probability that two consecutive rolls land with a 1 face up is \(1 / 6+1 / 6=1 / 3\). (d) The probability of surviving a heart attack is \(2.35 .\)

Average Household Size for Renter-Occupied Units Table \(\mathrm{P} .12\) in Exercise \(\mathrm{P} .83\) gives the probability function for the random variable giving the household size for a renter-occupied housing unit in the US. (a) Find the mean household size. (b) Find the standard deviation for household size.

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