Chapter 11: Problem 112
In Exercises \(\mathrm{P} .112\) to \(\mathrm{P} .115,\) calculate the mean and standard deviation of the binomial random variable. A binomial random variable with \(n=6\) and \(p=0.4\)
Chapter 11: Problem 112
In Exercises \(\mathrm{P} .112\) to \(\mathrm{P} .115,\) calculate the mean and standard deviation of the binomial random variable. A binomial random variable with \(n=6\) and \(p=0.4\)
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Get started for freeState whether the two events (A and B) described are disjoint, independent, and/or complements. (It is possible that the two events fall into more than one of the three categories, or none of them.) South Africa plays Australia for the championship in the Rugby World Cup. At the same time, Poland plays Russia for the World Team Chess Championship. Let \(\mathrm{A}\) be the event that Australia wins their rugby match and \(\mathrm{B}\) be the event that Poland wins their chess match.
Find the specified areas for a normal density. (a) The area above 200 on a \(N(120,40)\) distribution (b) The area below 49.5 on a \(N(50,0.2)\) distribution (c) The area between 0.8 and 1.5 on a \(N(1,0.3)\) distribution
Use the information that, for events \(\mathrm{A}\) and \(\mathrm{B},\) we have \(P(A)=0.4, P(B)=0.3,\) and \(P(A\) and \(B)=0.1.\) Find \(P(\operatorname{not} B).\)
Heights of Men in the US Heights of adult males in the US are approximately normally distributed with mean 70 inches \((5 \mathrm{ft} 10 \mathrm{in})\) and standard deviation 3 inches. (a) What proportion of US men are between \(5 \mathrm{ft}\) 8 in and \(6 \mathrm{ft}\) tall \((68\) and 72 inches, respectively)? (b) If a man is at the 10 th percentile in height, how tall is he?
In Exercises \(\mathrm{P} .78\) to \(\mathrm{P} .81,\) use the probability function given in the table to calculate: (a) The mean of the random variable (b) The standard deviation of the random variable $$ \begin{array}{lllll} \hline x & 20 & 30 & 40 & 50 \\ \hline p(x) & 0.6 & 0.2 & 0.1 & 0.1 \\ \hline \end{array} $$
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