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In Exercises \(\mathrm{P} .108\) to \(\mathrm{P} .111,\) calculate the requested binomial probability. Find \(P(X=2)\) if \(X\) is a binomial random variable with \(n=6\) and \(p=0.3\).

Short Answer

Expert verified
The binomial probability \(P(X=2)\) is approximately 0.3241.

Step by step solution

01

Identify the Variables

First, identify the variables from the problem. Here, \(n=6\), \(k=2\) (because we're finding \(P(X=2)\)), and \(p=0.3\).
02

Calculating Combination

Next, calculate the combination \(C(n, k)\), which is \(C(6, 2)\). Using the formula for combinations, we get \[ C(n, k) = \frac{{n!}}{{k!(n-k)!}} = \frac{{6!}}{{2!(6-2)!}} = 15 \]
03

Calculating Binomial Probability

Finally, substitute the values into the binomial probability formula \[P(X=k) = C(n, k) \cdot p^k \cdot (1-p)^{n-k}\] This gives us \[P(X=2) = 15 \cdot 0.3^2 \cdot (1-0.3)^{6-2} \approx 0.3241.\]

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