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The authors of the paper "Adolescents and MP3 Players: Too Many Risks, Too Few Precautions" \((P \mathrm{e}-\) diatrics [2009]: e953-e958) concluded that more boys than girls listen to music at high volumes. This conclusion was based on data from independent random samples of 764 Dutch boys and 748 Dutch girls age 12 to \(19 .\) Of the boys, 397 reported that they almost always listen to music at a high volume setting. Of the girls, 331 reported listening to music at a high volume setting. Do the sample data support the authors' conclusion that the proportion of Dutch boys who listen to music at high volume is greater than this proportion for Dutch girls? Test the relevant hypotheses using a .01 significance level.

Short Answer

Expert verified
Based on the hypothesis test, there is strong evidence to reject the null hypothesis that there is no difference in proportions and conclude that the proportion of boys who listen to music at high volume is significantly greater than that of girls.

Step by step solution

01

State the Null and Alternative Hypotheses

The null hypothesis is that there is no difference in the proportions of boys and girls listening to music at high volumes, so \(p1 = p2\). The alternative hypothesis is that the proportion of boys (p1) listening to music at high volumes is greater than the proportion of girls (p2), so \(p1 > p2\).
02

Calculate the sample proportions

The sample proportion for boys (p1) is 397 out of 764 or 0.52 and for girls (p2) it is 331 out of 748 or 0.44.
03

Calculate the combined proportion

The combined proportion (p) is calculated as (x1+x2) / (n1+n2). Here, x1=397, x2=331, n1=764, n2=748. So, p = (397+331) / (764+748) = 0.48.
04

Calculate the Standard Error

We compute the Standard Error (SE) with the formula \(\sqrt{ p(1-p)(1/n1 + 1/n2)}\). Plugging in p=0.48, n1=764, n2=748 gives us SE = 0.028.
05

Compute the test statistic

The test statistic (z) is calculated as (p1-p2) / SE. Plugging in p1=0.52, p2=0.44, and SE=0.028, we get z=2.86.
06

Obtain the p-value

Using a standard Normal table or a software, we find the one-tailed p-value corresponding to z=2.86. The p-value here is 0.002.
07

Compare the p-value with the significance level

The p-value (0.002) is less than our significance level (0.01). So, we reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In hypothesis testing, the null hypothesis, often denoted as \(H_0\), is a statement that there is no effect or no difference. It serves as the starting assumption for statistical testing. In the context of our exercise, the null hypothesis is that the proportion of boys and girls who listen to music at high volumes is the same: \(p_1 = p_2\). This means we initially presume there is no difference in behavior between boys and girls, similar to a baseline or status quo.

If our calculated evidence (through data analysis) significantly contradicts the null hypothesis, we have reason to reject it. However, unless proven by such evidence, the null hypothesis remains in effect. Think of it as 'innocent until proven guilty'β€”the null hypothesis is "assumed true" unless the data convincingly suggests otherwise.
  • Serves as a baseline or a default position.
  • Assured to be true until statistically disproven.
  • Challenges biases in comparative studies.
Alternative Hypothesis
The alternative hypothesis, denoted as \(H_a\), is the statement we want to test and potentially accept if the null hypothesis is rejected. This hypothesis reflects the researchers' actual expectations. In our case, the alternative hypothesis is that the proportion of boys who listen to music at high volumes is greater than the proportion for girls: \(p_1 > p_2\).

This hypothesis represents a specific claim or effect we believe to be true or wish to provide evidence for. Deciding on an alternative hypothesis is a critical step in hypothesis testing because it guides the direction of the study and the interpretation of results.
  • Represents the expected research outcome.
  • Contradicts the null hypothesis.
  • Drives study objectives and decision-making.
Standard Error
Standard Error (SE) measures the variability or dispersion of a sample statistic from its population mean estimation. In hypothesis testing, the SE indicates how much the sample proportion might vary from the true population proportion. It forms the basis for constructing confidence intervals or computing test statistics.

In this exercise, the SE is computed using the formula:\[ SE = \sqrt{ p(1-p) \left( \frac{1}{n_1} + \frac{1}{n_2} \right)} \]where \(p\) is the combined sample proportion, and \(n_1\) and \(n_2\) are the sample sizes for boys and girls, respectively.

Having a smaller SE typically suggests more reliable estimates, as it means less variability in the sample data. Calculating SE allows researchers to gauge the accuracy of their sample and helps in assessing statistical significance.
  • Quantifies the precision of statistical estimates.
  • Aids in hypothesis testing and confidence interval estimation.
  • Depends inversely on sample size; larger samples usually reduce SE.
Significance Level
The significance level, often denoted as \(\alpha\), is the threshold or "cut-off" point used to determine whether a hypothesis test result is statistically significant. In this exercise, a significance level of 0.01 means there is a 1% risk of concluding that a difference exists when there isn't one (Type I error).

Choosing a significance level involves balancing the risks of Type I and Type II errors. A smaller \(\alpha\) reduces the likelihood of a Type I error but may increase the chance of a Type II error (failing to detect a true effect).

To decide the outcome of the hypothesis test, the p-value obtained from the test statistic is compared to the significance level. A p-value less than \(\alpha\) indicates that the difference is statistically significant, justifying rejecting the null hypothesis.
  • Helps determine statistical significance.
  • A lower level reduces risk of false positives.
  • Critical in validating research findings.

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Most popular questions from this chapter

"Mountain Biking May Reduce Fertility in Men, Study Says" was the headline of an article appearing in the San Luis Obispo Tribune (December 3,2002 ). This conclusion was based on an Austrian study that compared sperm counts of avid mountain bikers (those who ride at least 12 hours per week) and nonbikers. Ninety percent of the avid mountain bikers studied had low sperm counts, as compared to \(26 \%\) of the nonbikers. Suppose that these percentages were based on independent samples of 100 avid mountain bikers and 100 non-bikers and that it is reasonable to view these samples as representative of Austrian avid mountain bikers and nonbikers. a. Do these data provide convincing evidence that the proportion of Austrian avid mountain bikers with low sperm count is higher than the proportion of Austrian nonbikers? b. Based on the outcome of the test in Part (a), is it reasonable to conclude that mountain biking 12 hours per week or more causes low sperm count? Explain.

The paper "Effects of Fast-Food Consumption on Energy Intake and Diet Quality Among Children in a National Household Survey" ( Pediatrics [2004]: 112 118 ) investigated the effect of fast-food consumption on other dietary variables. For a sample of 663 teens who reported that they did not eat fast food during a typical day, the mean daily calorie intake was 2258 and the sample standard deviation was \(1519 .\) For a sample of 413 teens who reported that they did eat fast food on a typical day, the mean calorie intake was 2637 and the standard deviation was 1138 . a. What assumptions about the two samples must be reasonable in order for the use of the two-sample \(t\) confidence interval to be appropriate? b. Use the given information to estimate the difference in mean daily calorie intake for teens who do eat fast food on a typical day and those who do not.

The article "Fish Oil Staves Off Schizophrenia" (USA Today, February 2, \(2 \mathrm{O} 1 \mathrm{O}\) ) describes a study in which 81 patients age 13 to 25 who were considered atrisk for mental illness were randomly assigned to one of two groups. Those in one group took four fish oil capsules daily. The other group took a placebo. After 1 year, \(5 \%\) of those in the fish oil group and \(28 \%\) of those in the placebo group had become psychotic. Is it appropriate to use the two-sample \(z\) test of this section to test hypotheses about the difference in the proportions of patients receiving the fish oil and the placebo treatments who became psychotic? Explain why or why not.

Do girls think they don't need to take as many science classes as boys? The article "Intentions of Young Students to Enroll in Science Courses in the Future: An Examination of Gender Differences" (Science Education [1999]: 55-76) gives information from a survey of children in grades \(4,5,\) and \(6 .\) The 224 girls participating in the survey each indicated the number of science courses they intended to take in the future, and they also indicated the number of science courses they thought boys their age should take in the future. For each girl, the authors calculated the difference between the number of science classes she intends to take and the number she thinks boys should take. a. Explain why these data are paired. b. The mean of the differences was -.83 (indicating girls intended, on average, to take fewer classes than they thought boys should take), and the standard deviation was 1.51. Construct and interpret a \(95 \%\) confidence interval for the mean difference.

The Insurance Institute for Highway Safety issued a press release titled "Teen Drivers Often Ignoring Bans on Using Cell Phones" (June 9,2008 ). The following quote is from the press release: Just \(1-2\) months prior to the ban's Dec. 1,2006 start, 11 percent of teen drivers were observed using cell phones as they left school in the afternoon. About 5 months after the ban took effect, \(12 \%\) of teen drivers were observed using cell phones. Suppose that the two samples of teen drivers (before the ban, after the ban) can be regarded as representative of these populations of teen drivers. Suppose also that 200 teen drivers were observed before the ban (so \(n_{1}=200\) and \(\hat{p}_{1}=.11\) ) and 150 teen drivers were observed after the ban. a. Construct and interpret a \(95 \%\) confidence interval for the difference in the proportion using a cell phone while driving before the ban and the proportion after the ban. b. Is zero included in the confidence interval of Part (c)? What does this imply about the difference in the population proportions?

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