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Optical fibers are used in telecommunications to transmit light. Suppose current technology allows production of fibers that transmit light about \(50 \mathrm{~km} .\) Researchers are trying to develop a new type of glass fiber that will increase this distance. In evaluating a new fiber, it is of interest to test \(H_{0}: \mu=50\) versus \(H_{a}: \mu>50\), with \(\mu\) denoting the mean transmission distance for the new optical fiber. a. Assuming \(\sigma=10\) and \(n=10,\) use Appendix Table 5 to find \(\beta,\) the probability of a Type II error, for each of the given alternative values of \(\mu\) when a test with significance level .05 is employed: i. 52 ii. 55 \(\begin{array}{ll}\text { iii. } 60 & \text { iv. } 70\end{array}\) b. What happens to \(\beta\) in each of the cases in Part (a) if \(\sigma\) is actually larger than 10? Explain your reasoning.

Short Answer

Expert verified
In Part a, using the formula for z-score and the standard normal distribution table, the beta values for each \( \mu \) can be calculated. In Part b, as the standard deviation increases, the data points become more spread out which could make it harder to reject the null hypothesis when it is false, thus increasing the probability of a Type II error .

Step by step solution

01

Calculate z-score

For each given \( \mu \), calculate the z-score using the formula: \( z = (\mu - \mu_0) / (\sigma / \sqrt{n}) \) where \( \mu_0 \) = 50 km (the hypothesized mean), \( \sigma \) = 10 km (standard deviation), and n = 10 (sample size). For \( \mu \) = 52, 55, 60, and 70 km respectively, the z-scores are: \( z_{52} \), \( z_{55} \), \( z_{60} \), and \( z_{70} \).
02

Calculate beta

Use Appendix Table 5 to find the probability corresponding to each z-score obtained in Step 1. Since the test is one-tailed and considering the test is at .05 level of significance, one should look up the probability of the z-score and subtract from 1 to find \( \beta \). Repeat for all z-scores.
03

Explain variance effect on beta

In Part b, provide a general explanation for how increasing the standard deviation (increasing spread or dispersion of the data) affects the probability of Type II error \( \beta \). This does not involve any calculations.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Type II Error
In hypothesis testing, a Type II error occurs when we fail to reject the null hypothesis, even though the alternative hypothesis is true. In simpler terms, it's like saying the new optical fiber is not better than the current one, even though it actually is.

- **Understanding Beta (\( \beta \))**: The probability of making a Type II error is denoted by \( \beta \). Calculating \( \beta \) helps us understand the likelihood of missing an improvement when evaluating the new fiber.- **Importance in Testing**: Knowing the probability of a Type II error helps researchers decide the value of continuing or stopping research efforts on the new fiber technology.

- **Connected Factors**: The probability \( \beta \) is influenced by factors such as significance level, sample size, and the effect size (how much better or different the new fiber is compared to the old one). Enhance your intuition by imagining a net trying to catch improvements – a larger net (more samples, higher significance) catches more true improvements.
Z-Score Calculation
The z-score is a statistical measurement that indicates how many standard deviations an element is from the mean. In this exercise, it helps compare the observed transmission distances of the optical fibers to the hypothesized mean.

- **Calculation Formula**: To find the z-score, use the formula: \[ z = \frac{\mu - \mu_0}{\sigma / \sqrt{n}} \]where \( \mu \) is the observed mean, \( \mu_0 \) is the hypothesized mean (50 km), \( \sigma \) is the standard deviation, and \( n \) is the sample size (10).

- **Why Z-Scores Matter**: They allow us to determine how far off the sampled mean is from the hypothesized average. A higher z-score implies a greater degree of separation from the hypothesized mean, suggesting significant innovation in the fiber's distance transmission.

- **Using Z-Values**: Once computed, these z-scores help locate the probability of the research data (or more extreme) under the null hypothesis using standard normal distribution tables.
Standard Deviation Effect
Standard deviation reflects the variation or spread of data points around the mean. It plays a crucial role in hypothesis testing and significantly influences the Type II error.

- **Effect on Data Spread**: A smaller standard deviation means the data points are closer to the mean, suggesting more consistent results. Conversely, a larger standard deviation means more diverse outcomes, making it challenging to detect true changes.

- **Relation with \( \beta \)**: When the standard deviation increases, the value of \( \beta \) (probability of Type II error) increases as well, making it harder to detect improvements in the new optical fiber's transmission distance, even if they exist.
- **Reasoning for Variance Effect**: High variability implies samples might overlap with the hypothesized mean, reducing the distinguishability between the current and new fiber technologies.

Understanding how the standard deviation impacts \( \beta \) provides insights into the reliability and precision needed for testing new fibers.
Significance Level
The significance level, typically denoted by alpha (\( \alpha \)), is the threshold for rejecting the null hypothesis. In this exercise, a significance level of 0.05 is used, meaning there is a 5% risk of rejecting the null hypothesis when it is actually true.

- **Setting the Threshold**: Choosing the right significance level depends on the balance between Type I errors (false positives) and Type II errors (false negatives).

- **Impact on Testing Outcomes**: A lower significance level means stronger evidence is needed to reject the null hypothesis, decreasing the probability of a Type I error. However, this can inadvertently raise \( \beta \) if care isn't taken.- **Importance in Fiber Testing**: Since researchers want to confirm the superiority of the new fiber with strong evidence, a 0.05 level balances sensitivity with fairness. If the distance exceeds 50 km consistently, the fiber's potential for better transmission becomes credible.

Selecting a proper significance level helps ensure that the improvements observed in the testing phase are not due to random chance.

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Most popular questions from this chapter

According to a Washington Post-ABC News poll, 331 of 502 randomly selected U.S. adults interviewed said they would not be bothered if the National Security Agency collected records of personal telephone calls they had made. Is there sufficient evidence to conclude that a majority of U.S. adults feel this way? Test the appropriate hypotheses using a .01 significance level.

The city council in a large city has become concerned about the trend toward exclusion of renters with children in apartments within the city. The housing coordinator has decided to select a random sample of 125 apartments and determine for each whether children are permitted. Let \(p\) be the proportion of all apartments that prohibit children. If the city council is convinced that \(p\) is greater than 0.75 , it will consider appropriate legislation. a. If 102 of the 125 sampled apartments exclude renters with children, would a level .05 test lead you to the conclusion that more than \(75 \%\) of all apartments exclude children? b. What is the power of the test when \(p=.8\) and \(\alpha=.05 ?\)

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Suppose that you are an inspector for the Fish and Game Department and that you are given the task of determining whether to prohibit fishing along part of the Oregon coast. You will close an area to fishing if it is determined that fish in that region have an unacceptably high mercury content. a. Assuming that a mercury concentration of \(5 \mathrm{ppm}\) is considered the maximum safe concentration, which of the following pairs of hypotheses would you test: $$ H_{0}: \mu=5 \text { versus } H_{a}: \mu>5 $$ or $$ H_{0}: \mu=5 \text { versus } H_{a}: \mu<5 $$ Give the reasons for your choice. b. Would you prefer a significance level of .1 or .01 for your test? Explain.

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