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Data from a representative sample were used to estimate that \(32 \%\) of all computer users in 2011 had tried to get on a Wi-Fi network that was not their own in order to save money (USA Today, May 16,2011 ). You decide to conduct a survey to estimate this proportion for the current year. What is the required sample size if you want to estimate this proportion with a margin of error of 0.05 ? Calculate the required sample size first using 0.32 as a preliminary estimate of \(p\) and then using the conservative value of \(0.5 .\) How do the two sample sizes compare? What sample size would you recommend for this study?

Short Answer

Expert verified
The required sample sizes for the two cases are 866 and 961, respectively. Given the slight difference and for greater assurance in the results of the survey, a sample size of 961 is recommended.

Step by step solution

01

Find Formula for Sample Size

The formula for finding sample size when you want to estimate a proportion with a certain margin of error is given by \(n = p*(1-p)*(z/E)^2\). Here, 'n' is the sample size, 'p' is the preliminary estimate, 'E' is the margin of error, and 'z' is the z-score for the desired level of confidence.
02

Calculate Sample Size with p=0.32

In this scenario, 'p' is 0.32, 'E' is 0.05, and 'z' is 1.96 (z-score for 95% confidence level, assuming we want to be 95% confident in our estimate). Using these values in the sample size formula, we get \(n = 0.32*(1-0.32)*(1.96/0.05)^2\). Calculating this gives us \(n ≃ 865.2\). Since we can't have a fractional sample size, we round up to the next whole number, resulting in \(n = 866\).
03

Calculate Sample Size with p=0.5

Now, we calculate the sample size using the conservative value of 'p'=0.5. Thus, our formula becomes \(n = 0.5*(1-0.5)*(1.96/0.05)^2\). Calculating this yields \(n ≃ 960.4\). Again, rounding up to the next whole number, we get \(n = 961\).
04

Compare Sample Sizes and Give Recommendation

Note that the sample size required when using 'p'=0.5 is larger than when using 'p'=0.32. This is because a larger 'p' value implies greater variability, and hence, a larger sample size is needed for the same margin of error. The larger sample size can be viewed as a more conservative estimate. Considering the minimal difference in sample size and for greater assurance in the results, it is recommended to use the larger sample size of 961.

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Most popular questions from this chapter

a. Use the given information to estimate the proportion of college students who use the Internet more than 3 hours per day. b. Verify that the conditions needed in order for the margin of error formula to be appropriate are met. c. Calculate the margin of error. d. Interpret the margin of error in the context of this problem.Most American college students make use of the Internet for both academic and social purposes. What proportion of students use it for more than 3 hours a day? The authors of the paper "U.S. College Students" Internet Use: Race, Gender and Digital Divides" (Journal of Computer-Mediated Communication [2009]: 244-264) describe a survey of 7,421 students at 40 colleges and universities. The sample was selected to reflect general demographics of U.S. college students. Of the students surveyed, 2,998 reported Internet use of more than 3 hours per day.

A researcher wants to estimate the proportion of students enrolled at a university who eat fast food more than three times in a typical week. Would the standard error of the sample proportion \(\hat{p}\) be smaller for random samples of size \(n=50\) or random samples of size \(n=200 ?\)

Suppose that a campus bookstore manager wants to know the proportion of students at the college who purchase some or all of their textbooks online. Two different people independently selected random samples of students at the college and used their sample data to construct the following confidence intervals for the population proportion: Interval 1:(0.54,0.57) Interval 2:(0.46,0.62) a. Explain how it is possible that the two confidence intervals are not centered in the same place. b. Which of the two intervals conveys more precise information about the value of the population proportion? c. If both confidence intervals have a \(95 \%\) confidence level, which confidence interval was based on the smaller sample size? How can you tell? d. If both confidence intervals were based on the same sample size, which interval has the higher confidence level? How can you tell?

Use the formula for the standard error of \(\hat{p}\) to explain why a. The standard error is greater when the value of the population proportion \(p\) is near 0.5 than when it is near \(1 .\) b. The standard error of \(\hat{p}\) is the same when the value of the population proportion is \(p=0.2\) as it is when \(p=0.8\)

In the article "Fluoridation Brushed Off by Utah" (Associated Press, August 24,1998 ), it was reported that a small but vocal minority in Utah has been successful in keeping fluoride out of Utah water supplies despite evidence that fluoridation reduces tooth decay and despite the fact that a clear majority of Utah residents favor fluoridation. To support this statement, the article included the result of a survey of Utah residents that found \(65 \%\) to be in favor of fluoridation. Suppose that this result was based on a random sample of 150 Utah residents. Construct and interpret a \(90 \%\) confidence interval for \(p,\) the proportion of all Utah residents who favor fluoridation. Is this interval consistent with the statement that fluoridation is favored by a clear majority of residents?

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