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The article "Career Expert Provides DOs and DON'Ts for Job Seekers on Social Networking" (CareerBuilder.com, August 19,2009 ) included data from a survey of 2,667 hiring managers and human resource professionals. The article noted that more employers are now using social networks to screen job applicants. Of the 2,667 people who participated in the survey, 1,200 indicated that they use social networking sites such as Facebook, MySpace, and LinkedIn to research job applicants. Assume that the sample is representative of hiring managers and human resource professionals. Answer the four key questions (QSTN) to confirm that the suggested method in this situation is a confidence interval for a population proportion.

Short Answer

Expert verified
The suggested method i.e., a confidence interval for a population proportion, is valid in this scenario as the outcomes are binary, the sample is representative, and the sample size is sufficiently large.

Step by step solution

01

Identify the sample proportion

In this case, the sample size is 2,667 people who participated in the survey, of which 1,200 use social networking sites to research applicants. Thus the sample proportion (p̂) would be the number of hiring managers who use social networking sites divided by the total number of hiring managers, i.e, \( \frac{1200}{2667} = 0.449 \).
02

Check if the sample is representative

We are given that the managers are representative of all hiring managers and HR professionals. The sample size is sufficiently large and presumably randomly selected, therefore, we can assume it is a representative sample.
03

Find the sample size

We are also given that the sample size is 2,667 and we know that for a confidence interval for a proportion to be the correct method, the sample size needs to be sufficiently large. A rule of thumb for this sufficiency is that both \( np̂ \) and \( n(1 - p̂) \) should be greater than 5. Here, \( 2667⋅0.449 = 1197.83 > 5 \) and \( 2667⋅(1 - 0.449) = 1469.17 > 5 \), thus, the sample size is sufficiently large and the use of a confidence interval for a population proportion is an appropriate method in this situation.
04

Population is binary

We understand that a job applicant is either researched through social networking sites or not. Employers either use social networking sites for hiring or they do not. Hence, the population is binary (divided into two distinct groups) which confirms that the confidence interval for a population proportion is indeed a suitable method.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
When we talk about sample proportion, we're referring to the fraction of individuals in a sample that exhibit a particular trait or characteristic. In the context of the provided exercise, the characteristic of interest is the use of social networking sites by hiring managers to screen job applicants.

The sample proportion, denoted by \( \hat{p} \), is the number of individuals in the sample with the characteristic divided by the total number of individuals in the sample. In our case, with 1,200 hiring managers using social networking sites out of a sample of 2,667, the sample proportion \( \hat{p} \) equals \( \frac{1200}{2667} \), which simplifies to approximately 0.449. This figure serves as an estimate for the true population proportion.
Representative Sample
A representative sample accurately reflects the population from which it's drawn, ensuring that any conclusion drawn from the sample can be generalized to the population. To achieve this, the sample must be randomly selected, and its composition should mirror the diversity of the population in terms of key characteristics.

In our exercise, the survey's respondents are hiring managers and human resource professionals, and we assume that they are a representative sample of all such individuals in the general population. This assumption is crucial because it backs the validity of using the sample proportion to estimate the population proportion, particularly when constructing a confidence interval for that population proportion.
Sample Size
Sample size, denoted by \( n \), is the number of observations or individuals in a sample. The size of the sample plays a significant role in determining the precision of our estimates and the reliability of our statistical inferences.

The chosen sample size in our problem was 2,667, a figure which we assessed using the criteria that \( n\hat{p} \) and \( n(1 - \hat{p}) \) both exceed 5. This rule of thumb ensures that the Central Limit Theorem holds, and our sample proportion's distribution approaches normalcy, allowing us to confidently create a confidence interval for the population proportion. Our sample size of 2,667 satisfies this condition, with both \( 2667\times0.449 \) and \( 2667\times(1 - 0.449) \) being greater than 5.
Binary Population
The term 'binary population' refers to a scenario where each member of the population can be categorized into one of two groups based on a characteristic. This duality is essential when determining proportions since the characteristic is present in some members and absent in others.

In our exercise, the binary groups are hiring managers who do use social networking sites to screen job applicants and those who do not. This clear-cut separation allows for the calculation of the population proportion, which is the foundation for constructing a confidence interval. The binary nature of the population validates the methods used and the interpretability of the results.

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Most popular questions from this chapter

Suppose that county planners are interested in learning about the proportion of county residents who would pay a fee for a curbside recycling service if the county were to offer this service. Two different people independently selected random samples of county residents and used their sample data to construct the following confidence intervals for the proportion who would pay for curbside recycling: Interval 1:(0.68,0.74) Interval 2:(0.68,0.72) a. Explain how it is possible that the two confidence intervals are not centered in the same place. b. Which of the two intervals conveys more precise information about the value of the population proportion? c. If both confidence intervals are associated with a \(95 \%\) confidence level, which confidence interval was based on the smaller sample size? How can you tell? d. If both confidence intervals were based on the same sample size, which interval has the higher confidence level? How can you tell?

The report "2005 Electronic Monitoring \& Surveillance Survey: Many Companies Monitoring, Recording, Videotapingand Firing-Employees" (American Management Association, 2005) summarized a survey of 526 U.S. businesses. The report stated that 137 of the 526 businesses had fired workers for misuse of the Internet, and 131 had fired workers for e-mail misuse. Assume that the sample is representative of businesses in the United States. a. Construct and interpret a \(95 \%\) confidence interval for the proportion of U.S. businesses that have fired workers for misuse of the Internet. b. What are two reasons why a \(90 \%\) confidence interval for the proportion of U.S. businesses that have fired workers for misuse of e-mail would be narrower than the \(95 \%\) confidence interval calculated in Part (a)?

If two statistics are available for estimating a population characteristic, under what circumstances might you choose a biased statistic over an unbiased statistic?

A researcher wants to estimate the proportion of students enrolled at a university who are registered to vote. Would the standard error of the sample proportion \(\hat{p}\) be larger if the actual population proportion was \(p=0.4\) or \(p=0.8\) ?

In a study of 1,710 schoolchildren in Australia (Herald Sun, October 27,1994 ), 1,060 children indicated that they normally watch TV before school in the morning. (Interestingly, only \(35 \%\) of the parents said their children watched TV before school.) Construct and interpret a \(95 \%\) confidence interval for the proportion of all Australian children who say they watch TV before school. In order for the method used to construct the interval to be valid, what assumption about the sample must be reasonable?

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