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A car manufacturer is interested in learning about the proportion of people purchasing one of its cars who plan to purchase another car of this brand in the future. A random sample of 400 of these people included 267 who said they would purchase this brand again. For each of the three statements below, indicate if the statement is correct or incorrect. If the statement is incorrect, explain what makes it incorrect. Statement 1 : The estimate \(\hat{p}=0.668\) will never differ from the value of the actual population proportion by more than \(0.0462 .\) Statement 2 : It is unlikely that the estimate \(\hat{p}=0.668\) differs from the value of the actual population proportion by more than 0.0235 . Statement 3: It is unlikely that the estimate \(\hat{p}=0.668\) differs from the value of the actual population proportion by more than 0.0462 .

Short Answer

Expert verified
Statement 1 is incorrect, as the actual margin of error is larger than 0.0462. Statement 2 is also incorrect, as it is possible that the difference between \(\hat{p}=0.668\) and the actual population proportion can be larger than 0.0235. Statement 3 is correct, as the likelihood of the difference between \(\hat{p}=0.668\) and the actual population proportion being larger than 0.0462 is quite small.

Step by step solution

01

Analyzing Statement 1

First, we need to calculate the margin of error, let's use the formula \(E = Z * \sqrt{\frac{{\hat{p}*(1 - \hat{p})}}{{n}}}\), where Z is the z-score which usually is 1.96 for a confidence level of 95%, \(\hat{p}\) is the sample proportion and n is the total sample size. Substituting the given values, we get \(E = 1.96 * \sqrt{\frac{{0.668*(1 - 0.668)}}{{400}}}\) which results in E = 0.0471. Comparing this with the value given in statement 1, 0.0462, it is clear that \(E > 0.0462\). Therefore, the statement 1 is incorrect because the margin of error is actually greater than \(0.0462\).
02

Analyzing Statement 2

The margin of error E that we calculated in Step 1 is greater than the difference value in Statement 2, i.e., 0.0235. Hence, it is noticeable that the difference between \(\hat{p}\) and the actual population proportion could be higher than 0.0235. Therefore, statement 2 is incorrect.
03

Analyzing Statement 3

In this case, the difference value in the statement, 0.0462, is less than the margin of error E that we calculated in Step 1. Therefore, it is unlikely that the difference between \(\hat{p}\) and the actual population proportion would be more than the calculated E (0.0471). Hence, Statement 3 is correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Proportion
The population proportion is a measure that tells us what fraction of a total population possesses a certain characteristic. In the context of the given exercise, it refers to the proportion of all customers of a car manufacturer who plan to purchase the same brand again in the future. The population proportion is often unknown and must be estimated using a sample.
It's important to understand that any sample only provides a snapshot of the whole, and the sample proportion, which represents the same characteristic within a group taken from the population, is used as an estimate for the population proportion.
Confidence Interval
A confidence interval provides a range of values that likely contain the true population parameter, such as the population proportion. It is constructed around a sample statistic and gives us an estimate of the degree of certainty—or confidence—we have in the accuracy of that sample statistic.
For example, when we say we are 95% confident, we are stating that if we were to take 100 different samples and compute a confidence interval for each sample, then approximately 95 of the 100 confidence intervals will contain the actual population proportion. The width of the confidence interval relates to the certainty we have regarding the estimate. Narrower intervals suggest a higher precision, whereas wider intervals indicate less precision.
Z-Score
The z-score is a statistical measure that describes a value's relationship to the mean of a group of values. It is measured in terms of standard deviations from the mean. If we know the standard deviation and the sample mean, we can calculate the z-score of a value to find how it compares to the population as a whole.
In the context of constructing confidence intervals and calculating margins of error, z-scores are used to determine how many standard deviations an estimate is away from the mean to ensure a certain level of confidence. The 1.96 z-score used in the exercise corresponds to a 95% confidence level, which is commonly used because it offers a good balance between certainty and precision.
Sample Proportion
The sample proportion, denoted as \(\hat{p}\), is the ratio of the number of favorable outcomes to the total number of cases in a sample. It is an estimate of the population proportion \(p\). For instance, in the car manufacturer exercise, the sample proportion \(\hat{p} = \frac{267}{400} = 0.668\) estimates the actual population proportion of people who would repurchase a car of the same brand.
While \(\hat{p}\) can give us a good estimate, it's vital to remember it's not the exact population proportion, just our best guess based on the sample data. This is why we have a margin of error to communicate the estimate's potential inaccuracy.
Margin of Error Calculation
The margin of error is a statistic expressing the amount of random sampling error in a survey's results. It gives us a range in which we think our estimate from the sample falls within relative to the true population value. Calculating the margin of error (\(E\)) incorporates the z-score for the desired confidence level, the sample proportion (\(\hat{p}\)), and the sample size (\(n\)).
The formula as shown in the exercise is \[E = Z * \sqrt{\frac{{\hat{p}*(1 - \hat{p})}}{{n}}}\].
After the calculation, the resulting margin of error can be applied to the sample proportion, yielding a confidence interval that we use to infer true population values. Understanding the proper application of E is crucial, as it is commonly misunderstood, which can lead to incorrect conclusions, as outlined in the exercise solutions.

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Most popular questions from this chapter

Describe how each of the following factors affects the width of the large- sample confidence interval for \(p\) : a. The confidence level b. The sample size c. The value of \(\hat{p}\)

If two statistics are available for estimating a population characteristic, under what circumstances might you choose a biased statistic over an unbiased statistic?

The report "2005 Electronic Monitoring \& Surveillance Survey: Many Companies Monitoring, Recording, Videotapingand Firing-Employees" (American Management Association, 2005) summarized a survey of 526 U.S. businesses. The report stated that 137 of the 526 businesses had fired workers for misuse of the Internet, and 131 had fired workers for e-mail misuse. Assume that the sample is representative of businesses in the United States. a. Construct and interpret a \(95 \%\) confidence interval for the proportion of U.S. businesses that have fired workers for misuse of the Internet. b. What are two reasons why a \(90 \%\) confidence interval for the proportion of U.S. businesses that have fired workers for misuse of e-mail would be narrower than the \(95 \%\) confidence interval calculated in Part (a)?

Suppose that county planners are interested in learning about the proportion of county residents who would pay a fee for a curbside recycling service if the county were to offer this service. Two different people independently selected random samples of county residents and used their sample data to construct the following confidence intervals for the proportion who would pay for curbside recycling: Interval 1:(0.68,0.74) Interval 2:(0.68,0.72) a. Explain how it is possible that the two confidence intervals are not centered in the same place. b. Which of the two intervals conveys more precise information about the value of the population proportion? c. If both confidence intervals are associated with a \(95 \%\) confidence level, which confidence interval was based on the smaller sample size? How can you tell? d. If both confidence intervals were based on the same sample size, which interval has the higher confidence level? How can you tell?

The formula used to calculate a large-sample confidence interval for \(p\) is $$ \hat{p} \pm(z \text { critial value }) \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} $$ What is the appropriate \(z\) critical value for each of the following confidence levels? a. \(95 \%\) b. \(98 \%\) c. \(85 \%\)

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