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A random sample will be selected from the population of all adult residents of a particular city. The sample proportion \(\hat{p}\) will be used to estimate \(p,\) the proportion of all adult residents who do not own a car. For which of the following situations will the estimate tend to be closest to the actual value of \(p ?\) i. \(\quad n=500, p=0.1\) $$ \text { ii. } \quad n=1,000, p=0.2 $$ iii. \(n=1,200, p=0.3\)

Short Answer

Expert verified
Scenario ii. (n=1000, p=0.2) will tend to be the closest to the actual value of \( p \).

Step by step solution

01

Calculate Standard Error for Scenario 1

Initialize with \( n=500 \) and \( p=0.1 \). Insert these values into the formula for Standard Error thus: \( SE_{1} = \sqrt{ (0.1*(1-0.1))/500 } = 0.0134 \).
02

Calculate Standard Error for Scenario 2

Next calculate Standard Error for the second scenario with \( n=1000 \) and \( p=0.2 \). Insert these into the Standard Error formula: \( SE_{2} = \sqrt{ (0.2*(1-0.2))/1000 } = 0.01265 \).
03

Calculate Standard Error for Scenario 3

Finally, calculate the Standard Error for scenario 3 with \( n=1200 \) and \( p=0.3 \). Using the formula again we find: \( SE_{3} = \sqrt{ (0.3*(1-0.3))/1200 } = 0.0134 \).
04

Compare the Standard Errors

Now that we have the Standard Errors for each scenario, compare them to identify the lowest one. The scenario with the lowest Standard Error will produce the estimate that tends to be closest to the actual value of \( p \). From the calculations, \( SE_{2} \) which is 0.01265, is the lowest hence Scenario 2 ( ii. \( n=1,000, p=0.2 \)) will tend to give the most accurate estimate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
The sample proportion, often denoted as \(\hat{p}\), represents the fraction of individuals in a sample that exhibit a certain characteristic. For example, in a study to understand transportation habits, \(\hat{p}\) could indicate the proportion of people in a random sample of residents who do not own a car. It serves as the best estimate of the population proportion within the confines of the sample taken.

The accuracy of the sample proportion as an estimator for the actual population proportion relies heavily on the size of the sample and how representative it is of the population. If the sample is too small or not random, it might misrepresent the population, leading to errors in estimation. The exercise aims to identify which of several scenarios would more accurately estimate the true population proportion, given different sample sizes and assumed true proportions.
Population Proportion
The population proportion, denoted by \(p\), is the actual proportion of individuals in an entire population possessing a specific feature. Continuing with the transportation example, \(p\) would represent the exact fraction of all adult residents in a city that does not own a car. Unlike the sample proportion, the population proportion is a fixed value and does not change regardless of sample size or sampling methods used.

Estimating the population proportion is often the main goal of statistical studies, and it is why calculating sample proportions and understanding their variance are so significant. Estimators, like the sample proportion, are used to infer the population proportion, as it is usually impractical to measure the entire population.
Sample Size
Sample size, denoted as \(n\), is the number of individual observations included in a sample. It plays a critical role in statistical analyses because larger samples tend to yield more reliable estimates of the population characteristics. The principles of probability suggest that as the sample size increases, the sample proportion \(\hat{p}\) should get closer to the true population proportion \(p\).

In choosing the sample size, a balance must be struck between precision and resources. Larger sample sizes decrease the standard error, making it a key player in creating a smaller margin of error and tighter confidence intervals. This is exhibited in our exercise where different sample sizes impact the standard error of the estimate.
Confidence Interval
A confidence interval provides a range of values within which the true population parameter is expected to lie, considering a certain level of confidence (often 95%). It takes into account the sample proportion and the standard error to give an interval estimate rather than a single point estimate.

Calculating a confidence interval includes understanding the distribution of your estimator. A larger sample size and smaller standard error lead to a narrower confidence interval, implying a more precise estimate of the population proportion. In practice, while a single study might give a particular confidence interval, repeating the study numerous times under the same conditions will result in a confidence interval that contains the true population proportion in the specified percentage of studies (such as 95% of the time for a 95% confidence interval).

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Most popular questions from this chapter

In the article "Fluoridation Brushed Off by Utah" (Associated Press, August 24,1998 ), it was reported that a small but vocal minority in Utah has been successful in keeping fluoride out of Utah water supplies despite evidence that fluoridation reduces tooth decay and despite the fact that a clear majority of Utah residents favor fluoridation. To support this statement, the article included the result of a survey of Utah residents that found \(65 \%\) to be in favor of fluoridation. Suppose that this result was based on a random sample of 150 Utah residents. Construct and interpret a \(90 \%\) confidence interval for \(p,\) the proportion of all Utah residents who favor fluoridation. Is this interval consistent with the statement that fluoridation is favored by a clear majority of residents?

One thousand randomly selected adult Americans participated in a survey conducted by the Associated Press (June, 2006). When asked "Do you think it is sometimes justified to lie, or do you think lying is never justified?" \(52 \%\) responded that lying was never justified. When asked about lying to avoid hurting someone's feelings, 650 responded that this was often or sometimes OK. a. Construct and interpret a \(90 \%\) confidence interval for the proportion of adult Americans who would say that lying is never justified. b. Construct and interpret a \(90 \%\) confidence interval for the proportion of adult Americans who think that it is often or sometimes OK to lie to avoid hurting someone's feelings. c. Using the confidence intervals from Parts (a) and (b), comment on the apparent inconsistency in the responses.

A random sample will be selected from the population of all adult residents of a particular city. The sample proportion \(\hat{p}\) will be used to estimate \(p,\) the proportion of all adult residents who are registered to vote. For which of the following situations will the estimate tend to be closest to the actual value of \(p ?\) I. \(\quad n=1,000, p=0.5\) II. \(\quad n=200, p=0.6\) III. \(\quad n=100, p=0.7\)

Data from a representative sample were used to estimate that \(32 \%\) of all computer users in 2011 had tried to get on a Wi-Fi network that was not their own in order to save money (USA Today, May 16,2011 ). You decide to conduct a survey to estimate this proportion for the current year. What is the required sample size if you want to estimate this proportion with a margin of error of 0.05 ? Calculate the required sample size first using 0.32 as a preliminary estimate of \(p\) and then using the conservative value of \(0.5 .\) How do the two sample sizes compare? What sample size would you recommend for this study?

The article "Hospitals Dispute Medtronic Data on Wires" (The Wall Street Journal, February 4, 2010) describes several studies of the failure rate of defibrillators used in the treatment of heart problems. In one study conducted by the Mayo Clinic, it was reported that failures within the first 2 years were experienced by 18 of 89 patients under 50 years old and 13 of 362 patients age 50 and older. Assume that these two samples are representative of patients who receive this type of defibrillator in the two age groups. a. Construct and interpret a \(95 \%\) confidence interval for the proportion of patients under 50 years old who experience a failure within the first 2 years. b. Construct and interpret a \(99 \%\) confidence interval for the proportion of patients age 50 and older who experience a failure within the first 2 years. c. Suppose that the researchers wanted to estimate the proportion of patients under 50 years old who experience this type of failure with a margin of error of \(0.03 .\) How large a sample should be used? Use the given study results to obtain a preliminary estimate of the population proportion.

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