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Explain why the standard deviation of \(p\) is equal to 0 when the population proportion is equal to 1 .

Short Answer

Expert verified
The standard deviation of the population proportion (\(p\)) is 0 when the population proportion (\(p\)) is equal to 1, because by substituting this value into the standard deviation formula, we get 0 as a result.

Step by step solution

01

Understanding Population Proportion and Standard Deviation

The standard deviation of the population proportion \(p\) is a statistical measure that shows the dispersion of the data from its mean. The formula for standard deviation is given by, \[\sqrt{ \(p(1-p) / n} \] where \(p\) is the population proportion and \(n\) is the size of the population.
02

Substituting with Given Condition

According to the given condition, the population proportion \(p = 1\) . Substituting this value in the formula for standard deviation: \[\sqrt { 1*(1 - 1)/n } = \sqrt { 0 }\]
03

Final Solution

We know that the square root of 0 is 0. Hence the standard deviation of the population proportion (\(p\)) would be 0 when the population proportion (\(p\)) is equal to 1.

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Most popular questions from this chapter

The report "New Study Shows Need for Americans to Focus on Securing Online Accounts and Backing Up Critical Data" (PRNewswire, October 29,2009 ) reported that only \(25 \%\) of Americans change computer passwords quarterly, in spite of a recommendation from the National Cyber Security Alliance that passwords be changed at least once every 90 days. For purposes of this exercise, assume that the \(25 \%\) figure is correct for the population of adult Americans. a. A random sample of size \(n=200\) will be selected from this population and \(\hat{p}\), the proportion who change passwords quarterly, will be calculated. What are the mean and standard deviation of the sampling distribution of \(\hat{p} ?\) b. Is the sampling distribution of \(\hat{p}\) approximately normal for random samples of size \(n=200 ?\) Explain. c. Suppose that the sample size is \(n=50\) rather than \(n=200 .\) Does the change in sample size affect the mean and standard deviation of the sampling distribution of \(\hat{p} ?\) If so, what are the new values of the mean and standard deviation? If not, explain why not. d. Is the sampling distribution of \(\hat{p}\) approximately normal for random samples of size \(n=50 ?\) Explain.

For which of the following sample sizes would the sampling distribution of \(\hat{p}\) be approximately normal when $$ \begin{array}{rl} p= & 0.2 ? \text { When } p=0.8 ? \text { When } p=0.6 ? \\ n=10 & n=25 \\ n=50 & n=100 \end{array} $$

In a national survey of 2,013 American adults, 1,283 indicated that they believe that rudeness is a more serious problem than in past years (Associated Press, April 3,2002 ). Assume that it is reasonable to regard this sample as a random sample of adult Americans. Is it reasonable to conclude that the proportion of adults who believe that rudeness is a worsening problem is greater than \(0.5 ?\) (Hint: Use what you know about the sampling distribution of \(\hat{p} .\) You might also refer to Example 8.5.)

A random sample is to be selected from a population that has a proportion of successes \(p=0.65\). Determine the mean and standard deviation of the sampling distribution of \(\hat{p}\) for each of the following sample sizes: a. \(n=10\) d. \(n=50\) b. \(n=20\) e. \(n=100\) c. \(n=30\) f. \(n=200\)

A random sample is to be selected from a population that has a proportion of successes \(p=0.25\). Determine the mean and standard deviation of the sampling distribution of \(\hat{p}\) for each of the following sample sizes: a. \(n=10\) d. \(n=50\) b. \(n=20\) e. \(n=100\) c. \(n=30\) f. \(n=200\)

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