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A random sample of 1,000 students at a large college included 428 who had one or more credit cards. For this sample, \(\hat{p}=\frac{428}{1,000}=0.428 .\) If another random sample of 1,000 students from this university were selected, would you expect that \(\hat{p}\) for that sample would also be 0.428 ? Explain why or why not.

Short Answer

Expert verified
No, we would not necessarily expect the proportion \(\hat{p}\) to be exactly 0.428 in a new sample, though the new \(\hat{p}\) would likely be close to 0.428. This variation is due to sampling variability and the nature of random sampling, where each sample is independent and hence may yield a slightly different \(\hat{p}\).

Step by step solution

01

Understanding the nature of random sampling

Random sampling is based on the principle that each sample drawn from the same population should be independent and not influenced by the previous samples. Therefore, a new sample of 1,000 students may or may not result in the proportion \(\hat{p}=0.428\). It could be slightly different due to the randomness of the selection.
02

Understanding sample proportions

The sample proportion \(\hat{p}=0.428\) is an estimate of the actual population proportion. While the same sample proportion could be obtained in a subsequent sample, it is not guaranteed. It could be slightly more or less than 0.428, depending on the sample selected.
03

Using probability theory

According to probability theory, the expected value is the same as the population parameters when dealing with proportions. Therefore, if the actual proportion of students with credit cards in the entire college is 0.428, then we expect that the proportion from another sample would be close to 0.428. However, due to sampling variability, we cannot say with absolute certainty that it would be exactly 0.428.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sampling Variability
When we pull a random sample from a population, like selecting 1,000 students from a college to find out how many have credit cards, each sample can yield different results. This is a fundamental concept known as sampling variability. It refers to the natural fluctuations that occur in statistics, such as a sample proportion, from one sample to another.

These differences are due to the random nature of sampling. Each student has a certain likelihood of holding a credit card, but until they’re actually selected and observed, we can’t know for sure if they will increase or decrease the sample proportion of cardholders, \( \hat{p} \). In practice, this means that if we repeated the sample process multiple times, we'd likely see different values of \( \hat{p} \) each time, even if the underlying proportion in the population remains unchanged.

While we might hope to get the same result of 0.428 each time, sampling variability tells us that this will not always be the case. The variability is influenced by the sample size, the variance in the population, and the sampling method. For educational purposes, it's critical to grasp that \( \hat{p} \) is an estimate of the true population proportion and it's normal for it to vary from sample to sample.
Sample Proportion
The sample proportion, denoted as \( \hat{p} \), is a statistic that estimates the proportion of individuals in a population who have a certain characteristic, based on a sample. In the context of our example, where we found that 428 out of 1,000 randomly sampled students have credit cards, our sample proportion is 0.428.

This number is a snapshot of the larger student body, aimed at giving us a sense of how common credit card ownership is among all students. It's important to understand that the sample proportion is just that—an estimate. It can vary from the true proportion due to the randomness inherent in sampling.

With this in mind, improving our understanding of the sample proportion involves acknowledging that it's a reflection of our specific sample at a specific time. A different random sample could lead to a slightly higher or lower proportion due to the different individuals who make up that sample. Therefore, while \( \hat{p} \) can serve as a useful estimate of the actual proportion, it's essential to consider it within the context of sampling error and respect its limitations as an estimate.
Probability Theory
Probability theory provides the mathematical foundation for understanding random processes, such as random sampling. According to probability theory, we can calculate expectations and make predictions about phenomena like sample proportions.

In the case of our college students and their credit card ownership, probability theory would say that if the true proportion of students with credit cards in the entire college is around 0.428, and we sample students randomly, then on average, our sample proportion should be close to the true proportion. However, 'on average' does not mean 'always.' Each individual sample might still vary due to chance alone.

Expected Value and Variance

Two key concepts from probability theory that help us with this include the expected value, which is what we predict to happen on average, and variance, which tells us how much the results are likely to differ from the expected value. These ideas from probability theory are essential as they allow us to quantify the uncertainty of our sample proportion, \(\hat{p}\), and give us tools to assess the reliability of our estimates.

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Most popular questions from this chapter

The article "Students Increasingly Turn to Credit Cards" (San Luis Obispo Tribune, July 21,2006 ) reported that \(37 \%\) of college freshmen carry a credit card balance from month to month. Suppose that the reported percentage was based on a random sample of 1,000 college freshmen. Suppose you are interested in learning about the value of \(p,\) the proportion of all college freshmen who carry a credit card balance from month to month. The following table is similar to the table that appears in Examples 8.4 and \(8.5,\) and is meant to summarize what you know about the sampling distribution of \(\hat{p}\) in the situation just described. The "What You Know" information has been provided. Complete the table by filling in the "How You Know It" column.

The article "Career Expert Provides DOs and DON'Ts for Job Seekers on Social Networking" (CareerBuilder.com, August 19,2009 ) included data from a survey of 2,667 hiring managers and human resource professionals. The article noted that many employers are using social networks to screen job applicants and that this practice is becoming more common. Of the 2,667 people who participated in the survey, 1,200 indicated that they use social networking sites (such as Facebook, MySpace, and LinkedIn) to research job applicants. For the purposes of this exercise, assume that the sample can be regarded as a random sample of hiring managers and human resource professionals. a. Suppose you are interested in learning about the value of \(p,\) the proportion of all hiring managers and human resource managers who use social networking sites to research job applicants. This proportion can be estimated using the sample proportion, \(p .\) What is the value of \(p\) for this sample? b. Based on what you know about the sampling distribution of \(p,\) is it reasonable to think that this estimate is within 0.02 of the actual value of the population proportion? Explain why or why not.

The article "Thrillers" (Newsweek, April 22,1985 ) stated, "Surveys tell us that more than half of America's college graduates are avid readers of mystery novels." Let \(p\) denote the actual proportion of college graduates who are avid readers of mystery novels. Consider a sample proportion \(\hat{p}\) that is based on a random sample of 225 college graduates. If \(p=0.5,\) what are the mean value and standard deviation of the sampling distribution of \(\hat{p}\) ? Answer this question for \(p=0.6 .\) Is the sampling distribution of \(\hat{p}\) approximately normal in both cases? Explain.

Explain what it means when we say the value of a sample statistic varies from sample to sample.

A random sample of 50 registered voters in a particular city included 32 who favored using city funds for the construction of a new recreational facility. For this sample, \(\hat{p}=\frac{32}{50}=\) 0.64 . If a second random sample of 50 registered voters was selected, would it surprise you if \(\hat{p}\) for that sample was not equal to 0.64 ? Why or why not?

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