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Suppose that \(25 \%\) of the fire alarms in a large city are false alarms. Let \(x\) denote the number of false alarms in a random sample of 100 alarms. Approximate the following probabilities: a. \(P(20 \leq x \leq 30)\) b. \(P(20 < x < 30)\) c. \(P(x \geq 35)\) d. The probability that \(x\) is farther than 2 standard deviations from its mean value.

Short Answer

Expert verified
This is a numerical approximation problem based on a binomial distribution and we use normal approximation to solve it. The answers to the questions are found using standard normal distribution tables, with probabilities a, b, and c found directly from the table and probability d found by subtracting from 1. The exact numerical value of each probability depends on the details of the table used.

Step by step solution

01

Compute the Mean and Variance

The mean for a binomial distribution is \(np\) and the variance is \(npq\). Thus, we have mean \(μ = np = 100*0.25 = 25\) and variance \(σ^2 = npq = 100*0.25*0.75 = 18.75\). The standard deviation is the square root of variance i.e. \(σ = \sqrt{18.75} \approx 4.33\).
02

Compute Normalized Variables

Normalized variables are calculated with \((x - μ)/σ\). This needs to be done for each of the x-values in the question before using the normal approximation for the binomial distribution.
03

Approximate the Probabilities and Use Normal Distribution Tables

Once the normalized variables are calculated, we can use standard normal distribution tables (also known as z-tables) to approximate the requested probabilities. These will give us the answers for parts a, b and c of this question.
04

Solve for Each Part

a. For \(P(20 \leq x \leq 30)\) we normalize the values and use the z-table to find \(P(-1.16 \leq z \leq 1.16)\). retrieve the probabilities corresponding to these z-values, subtracting them gives the answer. b. For \(P(20 < x < 30)\), the process is the same except we use \(P(-1.16 < z < 1.16)\). c. For \(P(x \geq 35)\), we normalize the value and use \(P(z \geq 2.31)\), which is 1 minus the value from the z-table.
05

Find Probability for Part d

In this part, we're asked about the probability that \(x\) is farther than 2 standard deviations from its mean value i.e. \(P(x < μ - 2σ) or P(x > μ + 2σ)\). Normalizing these values, we find \(P(z < -2) or P(z > 2)\). These probabilities can be found from the z-table.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Distribution
The binomial distribution is a probability distribution that summarizes the likelihood that a value will take on one of two independent values under a given set of parameters or assumptions. In the context of our example, it reflects the probability of observing a certain number of false alarms (successes) in a series of 100 alarm instances (trials), each with a 25% chance (success probability) of being a false alarm. The defining parameters for a binomial distribution are the number of trials, denoted by 'n', and the probability of success, denoted by 'p'. The mean, or expected value, for a binomial distribution is calculated as the product of the total number of trials (n) and the probability of success (p). The variance, which measures the variability from the mean, is the product of n, p, and q (where 'q' is the probability of failure; q = 1 - p). Understanding the binomial distribution is essential for estimating probabilities of outcomes within a discrete set of events, such as a number of false alarms in a sample.

When solving problems like the one given, you often first establish that the scenario fits a binomial distribution, then calculate the mean (μ) and variance (σ^2) using the formulas provided. Next, you can use these parameters to answer probability questions about the scenario, which sometimes involves utilizing a normal approximation—especially when 'n' is large.
Normal Approximation
Normal approximation, also known as the Central Limit Theorem approximation, allows us to estimate the probabilities of a binomial distribution using the normal distribution when certain conditions are met. These conditions usually include a sufficiently large number of trials (n) which in most cases should be greater than 30, and a product of the probability of success (p) and failure (q) large enough to assume a bell-shaped curve. In our example of false alarms, since the sample size is 100, it is appropriate to use the normal approximation.

The approximation is achieved by transforming the binomial random variable 'x' into a standard normal variable 'z' using the formula \( z = \frac{x - \/mu}{\sigma} \). By following the steps laid out in the solution, we calculate 'z' scores and use these to estimate our probabilities. The technique harnesses the power of the normal distribution due to its symmetric properties and the fact that it's well-tabulated, hence making calculations easier and more accessible.
Standard Deviation
Standard deviation is a measure of the amount of variation or dispersion in a set of values. A low standard deviation indicates that the values tend to be close to the mean (expected value), while a high standard deviation indicates that the values are spread out over a wider range. In the context of our fire alarm example, the standard deviation can be thought of as how much we can expect the number of false alarms to 'deviate' from an average of 25 false alarms in 100 trials.

Mathematically, the standard deviation (σ) is the square root of the variance. Hence, to compute it, we first find the variance (\(σ^2 = npq\)), and then take the positive square root. Standard deviation is crucial in probability and statistics as it gives context to the mean; it adds depth to our understanding of the distribution of our data. For instance, saying there are 25 false alarms on average is informative, but adding that the standard deviation is approximately 4.33 alarms tells us about the typical range of variation we might actually observe.
Z-table
A z-table, also known as the standard normal table or unit normal table, is a mathematical table that allows us to find the probability of a random variable falling within a particular range of a standard normal distribution. The 'z' values represent the distance between a value and the mean, measured in standard deviations. In a perfectly normal distribution, you can look up a 'z-score' to find the percentage of data that falls to the left of this score.

In practical scenarios like our example, once we have calculated z-scores, we use the z-table to find probabilities for events occurring below, above, or between certain values. With the z-table, critical values for different confidence levels can also be determined, which is useful for hypothesis testing. For categorial probability problems involving the binomial distribution such as ours, the z-table simplifies the process of finding probabilities, as it directly provides you with cumulative probabilities, eliminating complex integrations and calculations that would otherwise be required.

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Most popular questions from this chapter

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