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The article "Anxiety Increases for Airline Passengers After Plane Crash" (San Luis Obispo Tribune, November 13,2001 ) reported that air passengers have a 1 in 11 million chance of dying in an airplane crash. This probability was then interpreted as "You could fly every day for 26,000 years before your number was up." Comment on why this probability interpretation is misleading.

Short Answer

Expert verified
The interpretation 'you could fly every day for 26,000 years before your number was up' is misleading because it implies that risk accumulates over time, whereas in reality, each flight is a separate, independent event with the same probability of a crash - 1 in 11 million.

Step by step solution

01

Understanding the Given Probability

The given odds of dying in a plane crash are 1 in 11 million. This means, statistically, for every 11 million plane rides taken, one might likely result in a fatality.
02

Interpreting The Statement

The statement 'You could fly every day for 26,000 years before your number was up.' assumes a simplistic interpretation of the given probability. It interprets that flying a plane every day over a span of approximately 26,000 years will only then potentially result in a fatal accident. This interpretation is derived by calculating the number of days in 26,000 years, which is approximately 9.5 million (26000 * 365), which is close to the odds mentioned (11 million). However, this does not mean that the actual chance of a crash increases each day an individual flies. It is important to remember that the 1 in 11 million probability is a statistical average calculated over a large number of events and doesn't necessarily predict what will happen in an individual case.
03

Explaining why the interpretation is misleading

It is misleading to interpret the probability this way because, in reality, each flight is an independent event. This means the probability does not accumulate over time. This means, your risk does not increase each time you fly, because each flight is a unique situation and holds the same probability.

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Most popular questions from this chapter

A study of how people are using online services for medical consulting is described in the paper "Internet Based Consultation to Transfer Knowledge for Patients Requiring Specialized Care" (British Medical Journal [2003]: \(696-699)\). Patients using a particular online site could request one or both (or neither) of two services: specialist opinion and assessment of pathology results. The paper reported that \(98.7 \%\) of those using the service requested a specialist opinion, \(35.4 \%\) requested the assessment of pathology results, and \(34.7 \%\) requested both a specialist opinion and assessment of pathology results. Consider the following two events: \(S=\) event that a specialist opinion is requested \(A=\) event that an assessment of pathology results is requested a. What are the values of \(P(S), P(A)\), and \(P(S \cap A)\) ? b. Use the given probability information to set up a "hypothetical 1000 " table with columns corresponding to \(S\) and not \(S\) and rows corresponding to \(A\) and \(\operatorname{not} A .\) c. Use the table to find the following probabilities: i. the probability that a request is for neither a specialist opinion nor assessment of pathology results. ii. the probability that a request is for a specialist opinion or an assessment of pathology results.

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An appliance manufacturer offers extended warranties on its washers and dryers. Based on past sales, the manufacturer reports that of customers buying both a washer and a dryer, \(52 \%\) purchase the extended warranty for the washer, \(47 \%\) purchase the extended warranty for the dryer, and \(59 \%\) purchase at least one of the two extended warranties. a. Use the given probability information to set up a "hypothetical 1000 " table. b. Use the table from Part (a) to find the following probabilities: i. the probability that a randomly selected customer who buys a washer and a dryer purchases an extended warranty for both the washer and the dryer. ii. the probability that a randomly selected customer purchases an extended warranty for neither the washer nor the dryer.

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