Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A single-elimination tournament with four players is to be held. A total of three games will be played. In Game 1 , the players seeded (rated) first and fourth play. In Game 2 , the players seeded second and third play. In Game \(3,\) the winners of Games 1 and 2 play, with the winner of Game 3 declared the tournament winner. Suppose that the following probabilities are known: \(P(\) Seed 1 defeats Seed 4\()=0.8\) \(P(\) Seed 1 defeats \(\operatorname{Seed} 2)=0.6\) \(P(\) Seed 1 defeats \(\operatorname{Seed} 3)=0.7\) \(P(\) Seed 2 defeats \(\operatorname{Seed} 3)=0.6\) \(P(\) Seed 2 defeats Seed 4\()=0.7\) \(P(\) Seed 3 defeats Seed 4) \(=0.6\) a. How would you use random digits to simulate Game 1 of this tournament? b. How would you use random digits to simulate Game 2 of this tournament? c. How would you use random digits to simulate the third game in the tournament? (This will depend on the outcomes of Games 1 and \(2 .\) ) d. Simulate one complete tournament, giving an explanation for each step in the process. e. Simulate 10 tournaments, and use the resulting information to estimate the probability that the first seed wins the tournament. f. Ask four classmates for their simulation results. Along with your own results, this should give you information on 50 simulated tournaments. Use this information to estimate the probability that the first seed wins the tournament. g. Why do the estimated probabilities from Parts (e) and (f) differ? Which do you think is a better estimate of the actual probability? Explain.

Short Answer

Expert verified
To simulate the tournament, generate random numbers and use them to decide the winners according to the given probabilities. For multiple simulations, repeat this process and then compute the estimated probabilities. Variables in simulation result in differences between estimated probabilities. Probabilities based on more simulations are usually more accurate.

Step by step solution

01

Simulating Game 1

Create a random number from 0 to 1. If it's less than 0.8 then Seed 1 defeats Seed 4, otherwise Seed 4 wins.
02

Simulating Game 2

Generate a random number from 0 to 1. Seed 2 wins if the random number is less than 0.6, if not, Seed 3 wins.
03

Simulating Game 3

The game happens between the winners of Game 1 and Game 2. If Seed 1 won Game 1 and Seed 2 won Game 2, you generate a random number from 0 to 1. If the random number is less than 0.6, Seed 1 wins, otherwise Seed 2 wins. You follow a similar procedure for the other possible matchups.
04

Simulating the complete tournament

To simulate the tournament, repeat Steps 1, 2 and 3. Record the winner of the tournament.
05

Simulating multiple tournaments

For simulating multiple tournaments, repeat Step 4 for as many times as required.
06

Estimating the winning probability

To estimate the winning probability for Seed 1, you calculate the ratio of the number of tournaments won by Seed 1 to the total number of tournaments.
07

Using classmates' simulations

Combine the tournament results from Step 5 with the results of four classmates and repeat Step 6. This would give the chance of Seed 1 winning based on 50 simulated tournaments.
08

Comparing probabilities

Explain why the estimated probabilities for Seed 1 winning, from your simulations and the simulations including your classmates' results could be different and state which one you think would be a better estimate of the actual probability. The difference could arise due to the randomness and variability of the simulations. The one based on a larger number of simulations tends to yield a better estimate.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider the following events: \(C=\) event that a randomly selected driver is observed to be using a cell phone \(A=\) event that a randomly selected driver is observed driving a car \(V=\) event that a randomly selected driver is observed driving a van or SUV \(T=\) event that a randomly selected driver is observed driving a pickup truck Based on the article "Three Percent of Drivers on Hand-Held Cell Phones at Any Given Time" (San Luis Obispo Tribune, July 24,2001 ), the following probability estimates are reasonable: \(P(C)=0.03, P(C \mid A)=0.026, P(C \mid V)=0.048\) and \(P(C \mid T)=0.019 .\) Explain why \(P(C)\) is not just the average of the three given conditional probabilities.

A large cable company reports that \(42 \%\) of its customers subscribe to its Internet service, \(32 \%\) subscribe to its phone service, and \(51 \%\) subscribe to its Internet service or its phone service (or both). a. Use the given probability information to set up a "hypothetical \(1000 "\) table. b. Use the table to find the following: i. the probability that a randomly selected customer subscribes to both the Internet service and the phone service. ii. the probability that a randomly selected customer subscribes to exactly one of the two services.

The paper "Action Bias among Elite Soccer Goalkeepers: The Case of Penalty Kicks" ( Journal of Economic Psychology [2007]: \(606-621\) ) presents an interesting analysis of 286 penalty kicks in televised championship soccer games from around the world. In a penalty kick, the only players involved are the kicker and the goalkeeper from the opposing team. The kicker tries to kick a ball into the goal from a point located 11 meters away. The goalkeeper tries to block the ball from entering the goal. For each penalty kick analyzed, the researchers recorded the direction that the goalkeeper moved (jumped to the left, stayed in the center, or jumped to the right) and whether or not the penalty kick was successfully blocked. Consider the following events: \(L=\) the event that the goalkeeper jumps to the left \(C=\) the event that the goalkeeper stays in the center \(R=\) the event that the goalkeeper jumps to the right \(B=\) the event that the penalty kick is blocked Based on their analysis of the penalty kicks, the authors of the paper gave the following probability estimates: $$ \begin{array}{rrr} P(L)=0.493 & P(C)=0.063 & P(R)=0.444 \\ P(B \mid L)=0.142 & P(B \mid C)=0.333 & P(B \mid R)=0.126 \end{array} $$ a. For each of the given probabilities, write a sentence giving an interpretation of the probability in the context of this problem. b. Use the given probabilities to construct a "hypothetical 1000" table with columns corresponding to whether or not a penalty kick was blocked and rows corresponding to whether the goalkeeper jumped left, stayed in the center, or jumped right. (Hint: See Example 5.14) c. Use the table to calculate the probability that a penalty kick is blocked. d. Based on the given probabilities and the probability calculated in Part (c), what would you recommend to a goalkeeper as the best strategy when trying to defend against a penalty kick? How does this compare to what goalkeepers actually do when defending against a penalty kick?

A rental car company offers two options when a car is rented. A renter can choose to pre-purchase gas or not and can also choose to rent a GPS device or not. Suppose that the events \(A=\) event that gas is pre-purchased \(B=\) event that a GPS is rented are independent with \(P(A)=0.20\) and \(P(B)=0.15\). a. Construct a "hypothetical 1000 " table with columns corresponding to whether or not gas is pre-purchased and rows corresponding to whether or not a GPS is rented. b. Use the table to find \(P(A \cup B)\). Give a long-run relative frequency interpretation of this probability.

According to The Chronicle for Higher Education (Aug. 26, 2011), there were 787,325 Associate degrees awarded by U.S. community colleges in the \(2008-2009\) academic year. A total of 488,142 of these degrees were awarded to women. a. If a person who received an Associate degree in 2008 2009 is selected at random, what is the probability that the selected person will be female? b. What is the probability that the selected person will be male?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free