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An electronics store sells two different brands of DVD players. The store reports that \(30 \%\) of customers purchasing a DVD choose Brand \(1 .\) Of those that choose Brand \(1,20 \%\) purchase an extended warranty. Consider the chance experiment of randomly selecting a customer who purchased a DVD player at this store. a. One of the percentages given in the problem specifies an unconditional probability, and the other percentage specifies a conditional probability. Which one is the conditional probability, and how can you tell? b. Suppose that two events \(B\) and \(E\) are defined as follows: \(B=\) selected customer purchased Brand 1 \(E=\) selected customer purchased an extended warranty Use probability notation to translate the given information into two probability statements of the form \(P(\underline{ })=\) probability value.

Short Answer

Expert verified
Part a: The unconditional probability is the \(30% \) chance of customers choosing Brand 1. The conditional probability is the \(20% \) chance of a customer purchasing an extended warranty given that they have already chosen Brand 1. Part b: The probability of a customer buying Brand 1 (\(P(B) = 0.30 \)) and the probability of a customer purchasing an extended warranty given they bought Brand 1 (\(P(E | B) = 0.20\)).

Step by step solution

01

Understand the Concept of Conditional and Unconditional Probabilities

An unconditional probability is the chance of an event happening irrespective of any other events. In this exercise, the probability of a client choosing Brand 1 is unconditional. In contrast, a conditional probability is the probability of event A happening given that another event B has already occurred. In this case, the conditional probability is the probability that a customer purchases an extended warranty given that they have chosen Brand 1.
02

Identify the Unconditional and Conditional Probabilities

From the problem, the unconditional probability is the \(30%\) chance of customers choosing Brand 1. The conditional probability is the \(20%\) chance of a customer purchasing an extended warranty given that they have already chosen Brand 1.
03

Translate the Information into Probability Notation

Translate the information into probability notation as stated in the problem. Let event \(B\) represent a customer purchasing Brand 1, and let \(E\) represent a customer purchasing an extended warranty. Therefore, the probability of a customer buying Brand 1 (\(B\)) is \(P(B) = 0.30\) (or \(30% \)), and the probability of a customer purchasing an extended warranty given they bought Brand 1 (\(E | B\)) is \(P(E | B) = 0.20\) (or \(20% \)).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unconditional Probability
Unconditional probability, also known as marginal or simple probability, is the basic concept of how likely an event is to occur without any conditions or restrictions applied. It's like flipping a coin and saying the probability of getting heads is 50%, regardless of any previous coin flips. In the exercise described above, the 30% figure—that is, the chance of a customer choosing Brand 1—is an example of an unconditional probability. This percentage doesn't depend on any other event; it simply reflects the overall likelihood of customers picking this brand from all the DVD players available in the store.

Understanding unconditional probability is vital in making standalone predictions and serves as a building block for more complex probability concepts, such as conditional probability and joint probability. When dealing with more complex scenarios where events might influence one another, unconditional probability provides a baseline from which conditional probabilities can be compared and analyzed.
Probability Notation
Probability notation is the language used to succinctly describe the likelihood of events. In mathematical terms, probabilities are generally expressed as a number between 0 and 1, with 0 meaning an event will definitely not occur, and 1 signifying an event is certain. Fractions, decimals, and percentages are other ways to express probability values. We use the capital letter 'P' to denote probability followed by the event of interest in parentheses. For instance, if we have an event A, the probability of A occurring is written as \( P(A) \).

In the context of our DVD player example, probability notation helps us translate textual descriptions into a mathematical framework, which is crucial for further calculations or inferences. With this notation, we can express the chance of a customer purchasing Brand 1 as \( P(B) = 0.30 \), and similarly, this notation also allows us to define the chance of a customer not purchasing Brand 1 as \( P(eg B) \), where \( eg B \) indicates the event in which Brand 1 is not chosen.
Extended Warranty Probability
Extended warranty probability is a specific type of conditional probability. It tackles the likelihood of a customer purchasing an extended warranty but only among those who have already made a specific purchase—in this case, those who bought Brand 1 DVD players. Here, we're not considering all customers, but just a subsection of them. To find this, we look at what proportion of the customers who chose Brand 1 went on to buy an extended warranty. This probability is expressed as \( P(E | B) \), where 'E' is the event of purchasing an extended warranty, and 'B' is the event of purchasing Brand 1. The vertical bar '|' is read as 'given'.

The probability of someone buying an extended warranty given they bought a Brand 1 DVD player—\( P(E | B) = 0.20 \) or 20% in this case—is helpful for the store in understanding how their additional offerings like extended warranties are performing among the different customer segments. Knowing this can drive decisions on marketing strategies or product pair offerings to enhance sales and customer satisfaction.

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Most popular questions from this chapter

The same issue of The Chronicle for Higher Education referenced in Exercise 5.17 also reported the following information for degrees awarded to Hispanic students by U.S. colleges in the \(2008-2009\) academic year: A total of 274,515 degrees were awarded to Hispanic students. \- 97,921 of these degrees were Associate degrees. \- 129,526 of these degrees were Bachelor's degrees. \- The remaining degrees were either graduate or professional degrees. What is the probability that a randomly selected Hispanic student who received a degree in \(2008-2009\) a. received an associate degree? b. received a graduate or professional degree? c. did not receive a bachelor's degree?

The article "Checks Halt over 200,000 Gun Sales" (San Luis Obispo Tribune, June 5,2000 ) reported that required background checks blocked 204,000 gun sales in \(1999 .\) The article also indicated that state and local police reject a higher percentage of would-be gun buyers than does the FBI, stating, "The FBI performed 4.5 million of the 8.6 million checks, compared with 4.1 million by state and local agencies. The rejection rate among state and local agencies was \(3 \%,\) compared with \(1.8 \%\) for the FBI." a. Use the given information to estimate \(P(F), P(S)\), \(P(R \mid F),\) and \(P(R \mid S),\) where \(F=\) event that a randomly selected gun purchase background check is performed by the \(\mathrm{FBI}, S=\) event that a randomly selected gun purchase background check is performed by a state or local agency, and \(R=\) event that a randomly selected gun purchase background check results in a blocked sale. b. Use the probabilities from Part (a) to create a "hypothetical \(1000 "\) table. Use the table to calculate \(P(S \mid R),\) and write a sentence interpreting this value in the context of this problem.

A large cable company reports that \(80 \%\) of its customers subscribe to its cable TV service, \(42 \%\) subscribe to its Internet service, and \(97 \%\) subscribe to at least one of these two services. (Hint: See Example 5.6\()\) a. Use the given probability information to set up a "hypothetical \(1000 "\) table. b. Use the table from Part (a) to find the following probabilities: i. the probability that a randomly selected customer subscribes to both cable TV and Internet service. ii. the probability that a randomly selected customer subscribes to exactly one of these services.

Four students must work together on a group project. They decide that each will take responsibility for a particular part of the project, as follows: Because of the way the tasks have been divided, one student must finish before the next student can begin work. To ensure that the project is completed on time, a time line is established, with a deadline for each team member. If any one of the team members is late, the timely completion of the project is jeopardized. Assume the following probabilities: 1\. The probability that Maria completes her part on time is 0.8 2\. If Maria completes her part on time, the probability that Alex completes on time is \(0.9,\) but if Maria is late, the probability that Alex completes on time is only 0.6 . 3\. If Alex completes his part on time, the probability that Juan completes on time is \(0.8,\) but if \(\mathrm{Alex}\) is late, the probability that Juan completes on time is only 0.5 . 4\. If Juan completes his part on time, the probability that Jacob completes on time is \(0.9,\) but if Juan is late, the probability that Jacob completes on time is only 0.7 . Use simulation (with at least 20 trials) to estimate the probability that the project is completed on time. Think carefully about this one. For example, you might use a random digit to represent each part of the project (four in all). For the first digit (Maria's part), \(1-8\) could represent on time, and 9 and 0 could represent late. Depending on what happened with Maria (late or on time), you would then look at the digit representing Alex's part. If Maria was on time, \(1-9\) would represent on time for Alex, but if Maria was late, only \(1-6\) would represent on time. The parts for Juan and Jacob could be handled similarly.

A deck of 52 cards is mixed well, and 5 cards are dealt. a. It can be shown that (disregarding the order in which the cards are dealt) there are 2,598,960 possible hands, of which only 1,287 are hands consisting entirely of spades. What is the probability that a hand will consist entirely of spades? What is the probability that a hand will consist entirely of a single suit? b. It can be shown that 63,206 of the possible hands contain only spades and clubs, with both suits represented. What is the probability that a hand consists entirely of spades and clubs with both suits represented?

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