Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Suppose you want to estimate the probability that a randomly selected customer at a particular grocery store will pay by credit card. Over the past 3 months, 80,500 payments were made, and 37,100 of them were by credit card. What is the estimated probability that a randomly selected customer will pay by credit card?

Short Answer

Expert verified
The estimated probability that a randomly selected customer will pay by credit card is approximately 0.46 or 46%.

Step by step solution

01

Identify the total number of outcomes

The total number of outcomes is the total payments made at the grocery store which is 80,500.
02

Identify the number of favorable outcomes

The number of favorable outcomes is the number of payments made by credit card which is 37,100.
03

Calculate the Probability

The probability of a randomly selected customer paying by credit card is calculated by dividing the number of favorable outcomes by the total number of outcomes. Using these numbers, the calculation would be \(\frac{37100}{80500}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Sampling
Random sampling is a fundamental method used in the field of statistics to select a subset of individuals or observations from within a statistical population to estimate characteristics of the whole population. Understanding this concept is critical when it comes to tackling real-world problems where it's impractical or impossible to examine an entire population.

In the exercise provided, the grocery store's payments represent the population, and each payment is an individual observation. By collecting data from the entire three months, which involves 80,500 payments, the store ensures that the sample reflects the broad range of customers. The concept assumes that every payment had an equal chance of being included in the data set, which is a key principle of random sampling. It minimizes biases that can skew results and provides a reliable foundation for estimating the probability of future events, such as the likelihood of customers paying with credit cards.

Random sampling's real value lies in its ability to provide accurate estimations that can be generalized to the larger group, which is especially useful when the total population is too large to analyze fully.
Favorable Outcomes
Whether you are calculating the likelihood of rolling a six on a die or estimating the probability of an event in real life, the concept of favorable outcomes is central to probability. Favorable outcomes are those specific results that we're interested in when performing a probability experiment.

In the context of our grocery store example, a favorable outcome refers to an event where a customer pays by credit card. Out of the 80,500 total payments, 37,100 were made with a credit card. These 37,100 payments are our favorable outcomes. They are 'favorable' simply because these are the outcomes we are counting when we aim to estimate the probability of a particular occurrence.

Understanding what constitutes a favorable outcome is essential for accurate probability calculation. It affects the numerator in our probability fraction and thus directly impacts the calculated likelihood of an event occurring. Additionally, providing clarity on what exactly are the favorable outcomes can help students easily grasp the concept, specially in the context of complex, real-world problems.
Probability Calculation
The probability calculation is the mathematical process used to find the likelihood of a particular event happening. This is expressed as a number between 0 and 1, where 0 indicates an impossibility, and 1 represents certainty.

Following the steps solved in the exercise, calculating the probability involves dividing the number of favorable outcomes by the total number of possible outcomes. As seen in the grocery store scenario, the probability that a customer pays by credit card is the quotient of the favorable credit card payments (37,100) over the total payments made (80,500). Therefore, using the formula for probability, \( P(A) = \frac{\text{number of favorable outcomes}}{\text{total number of outcomes}} \) where A is the event of a customer paying by credit card, we get \( P(A) = \frac{37100}{80500} \) which simplifies to a decimal that estimates the probability of the event.

The calculation can be interpreted as the expected frequency of the event occurring in a long series of trials. Probability calculations are vital for decision making in many fields, enabling businesses and individuals to anticipate likely outcomes and plan accordingly.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In an article that appears on the website of the American Statistical Association (www.amstat.org), Carlton Gunn, a public defender in Seattle, Washington, wrote about how he uses statistics in his work as an attorney. He states: I personally have used statistics in trying to challenge the reliability of drug testing results. Suppose the chance of a mistake in the taking and processing of a urine sample for a drug test is just 1 in \(100 .\) And your client has a "dirty" (i.e., positive) test result. Only a 1 in 100 chance that it could be wrong? Not necessarily. If the vast majority of all tests given - say 99 in 100 - are truly clean, then you get one false dirty and one true dirty in every 100 tests, so that half of the dirty tests are false. Define the following events as \(T D=\) event that the test result is dirty \(T C=\) event that the test result is clean \(D=\) event that the person tested is actually dirty \(C=\) event that the person tested is actually clean a. Using the information in the quote, what are the values of i. \(P(T D \mid D)\) iii. \(P(C)\) ii. \(P(T D \mid C)\) iv. \(P(D)\) b. Use the probabilities from Part (a) to construct a "hypothetical 1000 " table. c. What is the value of \(P(T D)\) ? d. Use the table to calculate the probability that a person is clean given that the test result is dirty, \(P(C \mid T D)\). Is this value consistent with the argument given in the quote? Explain.

A company that offers roadside assistance to drivers reports that the probability that a call for assistance will be to help someone who is locked out of his or her car is \(0.18 .\) Give a relative frequency interpretation of this probability.

A large cable TV company reports the following: \- \(80 \%\) of its customers subscribe to its cable TV service \- \(42 \%\) of its customers subscribe to its Internet service \- \(32 \%\) of its customers subscribe to its telephone service \(25 \%\) of its customers subscribe to both its cable TV and Internet service \(21 \%\) of its customers subscribe to both its cable TV and phone service \- \(23 \%\) of its customers subscribe to both its Internet and phone service \- \(15 \%\) of its customers subscribe to all three services Consider the chance experiment that consists of selecting one of the cable company customers at random. Find and interpret the following probabilities: a. \(P(\) cable TV only \()\) b. \(P(\) Internet \(\mid\) cable \(\mathrm{TV})\) c. \(P\) (exactly two services) d. \(P\) (Internet and cable TV only)

The article "Anxiety Increases for Airline Passengers After Plane Crash" (San Luis Obispo Tribune, November 13,2001 ) reported that air passengers have a 1 in 11 million chance of dying in an airplane crash. This probability was then interpreted as "You could fly every day for 26,000 years before your number was up." Comment on why this probability interpretation is misleading.

A study of how people are using online services for medical consulting is described in the paper "Internet Based Consultation to Transfer Knowledge for Patients Requiring Specialized Care" (British Medical Journal [2003]: \(696-699)\). Patients using a particular online site could request one or both (or neither) of two services: specialist opinion and assessment of pathology results. The paper reported that \(98.7 \%\) of those using the service requested a specialist opinion, \(35.4 \%\) requested the assessment of pathology results, and \(34.7 \%\) requested both a specialist opinion and assessment of pathology results. Consider the following two events: \(S=\) event that a specialist opinion is requested \(A=\) event that an assessment of pathology results is requested a. What are the values of \(P(S), P(A)\), and \(P(S \cap A)\) ? b. Use the given probability information to set up a "hypothetical 1000 " table with columns corresponding to \(S\) and not \(S\) and rows corresponding to \(A\) and \(\operatorname{not} A .\) c. Use the table to find the following probabilities: i. the probability that a request is for neither a specialist opinion nor assessment of pathology results. ii. the probability that a request is for a specialist opinion or an assessment of pathology results.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free