Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In a study investigating the effect of car speed on accident severity, the vehicle speed at impact was recorded for 5,000 fatal accidents. For these accidents, the mean speed was \(42 \mathrm{mph}\) and the standard deviation was \(15 \mathrm{mph}\). A histogram revealed that the vehicle speed distribution was mound shaped and approximately symmetric. a. Approximately what percentage of the vehicle speeds were between 27 and 57 mph? b. Approximately what percentage of the vehicle speeds exceeded 57 mph?

Short Answer

Expert verified
a. Approximately 68.26% of the vehicle speeds were between 27 and 57 mph. b. Approximately 65.87% of the vehicle speeds exceeded 57 mph.

Step by step solution

01

Calculate the Z-scores

First determine the Z-scores for 27 and 57 mph using the formula: \(Z = \frac{(X - \mu)}{\sigma}\) where X is the speed, \(\mu\) is the mean and \(\sigma\) is the standard deviation. For 27 mph the Z-score would be \(Z_1 = \frac{(27 - 42)}{15} = -1\), and for 57 mph it would be \(Z_2 = \frac{(57 - 42)}{15} = 1\)
02

Use the Z-table to find probabilities

Now we need to use the Z-scores to find probabilities. Using the Z-table, the area for Z=-1 (or equivalently 1) is 0.3413 for both. For Z=1, it's 0.3413 too.
03

Calculating required Probabilities

For part a, we need to find the area between -1 and 1. Because the normal distribution is symmetric, we can simply multiply the area for 1 by 2 giving \(0.3413*2=0.6826\). Thus approximately 68.26% of vehicle speeds were between 27 and 57 mph. For part b, we need the area for Z > 1 which would be \(1-0.3413 = 0.6587\). Thus approximately 65.87% of vehicle speeds exceeded 57 mph.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-scores Calculation
When analyzing statistical data, the concept of Z-scores is pivotal for interpreting the position of a single data point within a distribution. In simple terms, a Z-score indicates how many standard deviations a data point is from the mean. A Z-score of 0 means the data point is exactly at the mean, while a positive or negative value represents a position above or below the mean respectively.

To calculate a Z-score, the formula \(Z = \frac{(X - \mu)}{\sigma}\) is used where \(X\) is the value of interest, \(\mu\) denotes the population mean, and \(\sigma\) is the standard deviation. For example, if you wanted to find out how usual a speed of 27 mph is within our road accident severity study, calculating the Z-score with the given data points yields \(Z_1 = \frac{(27 - 42)}{15} = -1\). This result shows that a vehicle speed of 27 mph is 1 standard deviation below the mean, implying it's less than typical.

Understanding Z-scores can help students visualize the relative position of data points and is a fundamental skill in statistics. It bridges the gap between individual data points and the overall data set distribution, allowing for a deeper comprehension of data analysis.
Normal Distribution
The normal distribution, often referred to as the bell curve because of its distinctive shape, is a continuous probability distribution that is symmetrical about the mean. It's a powerful tool in statistics that allows us to make inferences about populations.

Characterized by its mean (\(\mu\)) and standard deviation (\(\sigma\)), it shows that data near the mean are more frequent in occurrence than data far from the mean. A key property of the normal distribution is that approximately 68% of the data lies within one standard deviation of the mean, 95% within two, and 99.7% within three, which is known as the Empirical Rule.

In our vehicle speed study, since the histogram of speeds was mound-shaped and symmetric, we can confidently apply the normal distribution model. This enables us to use Z-scores and calculate probabilities for specific ranges of speed, which directly correlate to accident severity — an application that showcases how statistical models can provide insights into real-world phenomena.
Histogram Analysis
A histogram is a graphical representation of the distribution of numerical data. It is an estimate of the probability distribution of a continuous variable and was used in our vehicle speed study to show the distribution of different speeds at the time of the accidents.

Histograms are beneficial because they reveal the underlying frequency distribution (shape) of the data set. They're particularly useful for demonstrating the shape of data distribution, like whether it’s skewed or symmetric, as with the approximately normal distribution in the provided vehicle speed data.

For the histogram that displayed the vehicle speeds, the 'mound-shaped' quality suggests the data closely follows a normal distribution, which subsequently justifies our use of Z-scores and normal distribution properties for analysis. Moreover, inspection of a histogram provides intuitive understanding of the data — in this case, most accidents occurred around the average speed, with fewer occurrences of extremely high or low speeds. Students are encouraged to carefully examine such visual data representations to gain insights before proceeding to quantitative analysis.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

3.49 The Los Angeles Times (July \(17,\) 1995) reported that for a sample of 364 lawsuits in which punitive damages were awarded, the median damage award was \(\$ 50,000,\) and the mean was \(\$ 775,000 .\) What does this suggest about the distribution of values in the sample?

Fiber content (in grams per serving) and sugar content (in grams per serving) for 18 high-fiber cereals (www .consumerreports.com) are shown. Fiber Content \(\begin{array}{rrrrrrr}7 & 10 & 10 & 7 & 8 & 7 & 12 \\ 12 & 8 & 13 & 10 & 8 & 12 & 7 \\ 14 & 7 & 8 & 8 & & & \end{array}\) Sugar Content \(\begin{array}{rrrrrrr}11 & 6 & 14 & 13 & 0 & 18 & 9 \\ 10 & 19 & 6 & 10 & 17 & 10 & 10 \\ 0 & 9 & 5 & 11 & & & \end{array}\) a. Find the median, quartiles, and interquartile range for the fiber content data set. b. Find the median, quartiles, and interquartile range for the sugar content data set. c. Are there any outliers in the sugar content data set? d. Explain why the minimum value and the lower quartile are equal for the fiber content data set. e. Construct a comparative boxplot and use it to comment on the differences and similarities in the fiber and sugar distributions.

Data on weekday exercise time for 20 females, consistent with summary quantities given in the paper "An Ecological Momentary Assessment of the Physical Activity and Sedentary Behaviour Patterns of University Students" (Health Education Journal [2010]: 116-125), are shown below. Female-Weekday \(\begin{array}{rrrrrr}10.0 & 90.6 & 48.5 & 50.4 & 57.4 & 99.6 \\\ 0.0 & 5.0 & 0.0 & 0.0 & 5.0 & 2.0 \\ 10.5 & 5.0 & 47.0 & 0.0 & 5.0 & 54.0 \\\ 0.0 & 48.6 & & & & \end{array}\) a. Calculate and interpret the values of the median and interquartile range. b. How do the values of the median and interquartile range for women compare to those for men calculated in the previous exercise?

Data on manufacturing defects per 100 cars for the 33 brands of cars sold in the United States (USA Today, June 16,2010 ) are: \(\begin{array}{lllllllllll}86 & 111 & 113 & 114 & 111 & 111 & 122 & 130 & 93 & 126 & 95\end{array}\) $$ \begin{array}{lllllllllll} 102 & 107 & 130 & 129 & 126 & 170 & 88 & 106 & 114 & 87 & 113 \end{array} $$ \(\begin{array}{llll}133 & 146 & 111\end{array}\) \(\begin{array}{rllll}3 & 110 & 114 & 1\end{array}\) \(\begin{array}{llllll}121 & 122 & 117 & 135 & 109\end{array}\) 83

For each of the following data sets, construct a graphical display of the data distribution and then indicate what summary measures you would use to describe center and spread. a. The following are data on weekend exercise time for 20 females consistent with summary quantities given in the paper "An Ecological Momentary Assessment of the Physical Activity and Sedentary Behaviour Patterns of University Students" (Health Education Journal [2010]: \(116-125)\) Female-Weekend \(\begin{array}{lrrrrrr}84.0 & 27.0 & 82.5 & 0.0 & 5.0 & 13.0 & 44.5 \\ 3.0 & 0.0 & 14.5 & 45.5 & 39.5 & 6.5 & 34.5 \\ 0.0 & 14.5 & 40.5 & 44.5 & 54.0 & 0.0 & \end{array}\) b. The accompanying data are consistent with summary statistics that appeared in the paper "Shape of Glass and Amount of Alcohol Poured: Comparative Study of Effect of Practice and Concentration" (British Medical Journal [2005]: 1512-1514). Data represent the actual amount (in \(\mathrm{ml}\) ) poured into a tall, slender glass for individuals asked to pour a "shot" of alcohol \((44.3 \mathrm{ml}\) or 1.5 ounces). \(\begin{array}{lllllll}44.0 & 49.6 & 62.3 & 28.4 & 39.1 & 39.8 & 60.5 \\ 73.0 & 57.5 & 56.5 & 65.0 & 56.2 & 57.7 & 73.5 \\ 66.4 & 32.7 & 40.4 & 21.4 & & & \end{array}\) c. The accompanying data are from a graph that appeared in the paper "Ladies First? A Field Study of Discrimination in Coffee Shops" (Applied Economics [April, 2008]). The data are the wait times (in seconds) between orderingand receiving coffee for 19 female customers at a Boston coffee shop. \(\begin{array}{lrrrrrr}60 & 80 & 80 & 100 & 100 & 100 & 120 \\ 120 & 120 & 140 & 140 & 150 & 160 & 180 \\ 200 & 200 & 220 & 240 & 380 & & \end{array}\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free