Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

USA Today (May 9,2006 ) published the weekday circulation numbers for the top 20 newspapers in the country. Here are the data for the 6 -month period ending March 31,2006 : \(\begin{array}{rrrrr}2,272,815 & 2,049,786 & 1,142,464 & 851,832 & 724,242 \\\ 708,477 & 673,379 & 579,079 & 513,387 & 438,722 \\ 427,771 & 398,329 & 398,246 & 397,288 & 365,011 \\ 362,964 & 350,457 & 345,861 & 343,163 & 323,031\end{array}\) a. Calculate and interpret the value of the median of this data set. b. Explain why the median is preferable to the mean for describing center for this data set. c. Explain why it would be unreasonable to generalize from this sample of 20 newspapers to the population of daily newspapers in the United States.

Short Answer

Expert verified
Median: 433246.5. It is more suitable to use median instead of mean as our data is skewed with few high values. The sample only includes top newspapers by circulation and misses out on a large number of smaller newspapers. Thus, it won't represent an accurate estimate for the population of all U.S. newspapers.

Step by step solution

01

Calculate the Median

Given the dataset is already sorted, find the middle value. Since there are 20 numbers, the median would be the average of the 10th and 11th elements in the series. The 10th and 11th numbers in this collection are 438,722 and 427,771. Average these two to find the median. Median = \(\frac{(438,722 + 427,771)}{2}\).
02

Interpret the Median

Calculate the value from Step 1. This is the median circulation number which means that half the newspapers have a circulation greater than this number and half have a circulation less than this number.
03

Understanding Median vs Mean for this data

The dataset seems to have a few high values relative to the others. This makes the dataset skewed. In skewed distributions, the mean, being highly sensitive to extreme values, is not a good measure of central tendency. The median, in such cases, gives a better idea of the central value as it is not affected by extreme values.
04

Inappropriateness of Generalization

The sample of top 20 newspapers in terms of circulation does not include many small to medium scale newspapers, which are going to have significantly smaller circulation numbers. This sample only represents the larger newspapers with a higher circulation, and cannot be used to provide an accurate estimate of the mean or median circulation for the general population of newspapers in the U.S.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Data on manufacturing defects per 100 cars for the 33 brands of cars sold in the United States (USA Today, June 16,2010 ) are: \(\begin{array}{lllllllllll}86 & 111 & 113 & 114 & 111 & 111 & 122 & 130 & 93 & 126 & 95\end{array}\) $$ \begin{array}{lllllllllll} 102 & 107 & 130 & 129 & 126 & 170 & 88 & 106 & 114 & 87 & 113 \end{array} $$ \(\begin{array}{llll}133 & 146 & 111\end{array}\) \(\begin{array}{rllll}3 & 110 & 114 & 1\end{array}\) \(\begin{array}{llllll}121 & 122 & 117 & 135 & 109\end{array}\) 83

The National Climate Data Center gave the accompanying annual rainfall (in inches) for Medford, Oregon, from 1950 to 2008 (www.ncdc.noaa.gov/oa/climate/ research/cag3/city): \(\begin{array}{lllll}28.84 & 20.15 & 18.88 & 25.72 & 16.42 \\ 20.18 & 28.96 & 20.72 & 23.58 & 10.62 \\ 20.85 & 19.86 & 23.34 & 19.08 & 29.23 \\ 18.32 & 21.27 & 18.93 & 15.47 & 20.68 \\ 23.43 & 19.55 & 20.82 & 19.04 & 18.77 \\\ 19.63 & 12.39 & 22.39 & 15.95 & 20.46 \\ 16.05 & 22.08 & 19.44 & 30.38 & 18.79 \\ 10.89 & 17.25 & 14.95 & 13.86 & 15.30 \\ 13.71 & 14.68 & 15.16 & 16.77 & 12.33 \\ 21.93 & 31.57 & 18.13 & 28.87 & 16.69 \\ 18.81 & 15.15 & 18.16 & 19.99 & 19.00 \\ 23.97 & 21.99 & 17.25 & 14.07 & \end{array}\) a. Calculate the quartiles and the interquartile range. b. Are there outliers in this data set? If so, which observations are outliers? c. Draw a modified boxplot for this data set and comment on the interesting features of this plot.

The following data on weekend exercise time for 20 males and 20 females are consistent with summary quantities in the paper "An Ecological Momentary Assessment of the Physical Activity and Sedentary Behaviour Patterns of University Students" (Health Education Journal [2010]: \(116-125)\). \(\begin{array}{lrrrrrr}\text { Male-Weekend } & & & & \\ 43.5 & 91.5 & 7.5 & 0.0 & 0.0 & 28.5 & 199.5 \\ 57.0 & 142.5 & 8.0 & 9.0 & 36.0 & 0.0 & 78.0 \\\ 34.5 & 0.0 & 57.0 & 151.5 & 8.0 & 0.0 & \end{array}\) \(\begin{array}{lrrrrr}\text { Female-Weekend } & & & & \\ 10.0 & 90.6 & 48.5 & 50.4 & 57.4 & 99.6 \\ 0.0 & 5.0 & 0.0 & 0.0 & 5.0 & 2.0 \\ 10.5 & 5.0 & 47.0 & 0.0 & 5.0 & 54.0 \\ 0.0 & 48.6 & & & & \end{array}\) Construct a comparative boxplot and comment on the differences and similarities in the two data distributions.

Data on a customer satisfaction rating (called the APEAL rating) are given for each brand of car sold in the United States (USA Today, July 17,2010 ). The APEAL rating is a score between 0 and 1,000 , with higher values indicating greater satisfaction. \(\begin{array}{lllllllll}822 & 832 & 845 & 802 & 818 & 789 & 748 & 751 & 794 \\ 792 & 766 & 760 & 805 & 854 & 727 & 761 & 836 & 822 \\\ 820 & 774 & 842 & 769 & 815 & 767 & 763 & 877 & 780 \\ 764 & 755 & 750 & 745 & 797 & 795 & & & \end{array}\) Calculate and interpret the mean and standard deviation for this data set.

Cost per serving (in cents) for 15 high-fiber cereals rated very good or good by Consumer Reports are shown below. \(\begin{array}{llllllllllllllll}46 & 49 & 62 & 41 & 19 & 77 & 71 & 30 & 53 & 53 & 67 & 43 & 48 & 28 & 54\end{array}\) Calculate and interpret the mean and standard deviation for this data set.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free