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Cost per serving (in cents) for 15 high-fiber cereals rated very good or good by Consumer Reports are shown below. \(\begin{array}{llllllllllllllll}46 & 49 & 62 & 41 & 19 & 77 & 71 & 30 & 53 & 53 & 67 & 43 & 48 & 28 & 54\end{array}\) Calculate and interpret the mean and standard deviation for this data set.

Short Answer

Expert verified
The mean represents the average cost per serving of the cereals. The standard deviation indicates how much the prices deviate from the average price, with a higher value indicating a larger variation in prices.

Step by step solution

01

Calculate the Mean

To calculate the mean, sum up all the elements in the data set, and then divide by the number of elements. Here, the elements are the costs per serving in cents. Use this formula: \[ Mean = \frac{\sum of\:costs}{\# of\:observations} \]
02

Calculate the Standard Deviation

The standard deviation indicates how much the values within the data set deviate from the mean. The first step to calculate this is to subtract the mean from each cost (in cents), square the result, then sum up all those squared values. Afterwards, divide this sum by the number of observations minus one. Finally, take the square root of this quotient. The formula to use is: \[ Standard\:Deviation = \sqrt{\frac{\sum (cost - mean)^{2}} {\# of\:observations - 1}} \]
03

Interpret the Results

The interpret the results, remember that the mean represents the average cost per serving, and the standard deviation shows how much the individual costs deviate from this average. A higher standard deviation would indicate a larger spread in the costs per serving.

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Most popular questions from this chapter

The mean reading speed of students completing a speed-reading course is 450 words per minute (wpm). If the standard deviation is 70 wpm, find the z-score associated with each of the following reading speeds. a. \(320 \mathrm{wpm}\) c. \(420 \mathrm{wpm}\) b. \(475 \mathrm{wpm}\) d. \(610 \mathrm{wpm}\)

Fiber content (in grams per serving) and sugar content (in grams per serving) for 18 high-fiber cereals (www .consumerreports.com) are shown. Fiber Content \(\begin{array}{rrrrrrr}7 & 10 & 10 & 7 & 8 & 7 & 12 \\ 12 & 8 & 13 & 10 & 8 & 12 & 7 \\ 14 & 7 & 8 & 8 & & & \end{array}\) Sugar Content \(\begin{array}{rrrrrrr}11 & 6 & 14 & 13 & 0 & 18 & 9 \\ 10 & 19 & 6 & 10 & 17 & 10 & 10 \\ 0 & 9 & 5 & 11 & & & \end{array}\) a. Find the median, quartiles, and interquartile range for the fiber content data set. b. Find the median, quartiles, and interquartile range for the sugar content data set. c. Are there any outliers in the sugar content data set? d. Explain why the minimum value and the lower quartile are equal for the fiber content data set. e. Construct a comparative boxplot and use it to comment on the differences and similarities in the fiber and sugar distributions.

A student took two national aptitude tests. The mean and standard deviation were 475 and 100 , respectively, for the first test, and 30 and 8 , respectively, for the second test. The student scored 625 on the first test and 45 on the second test. Use z-scores to determine on which exam the student performed better relative to the other test takers. (Hint: See Example 3.18 )

A sample of 26 offshore oil workers took part in a simulated escape exercise, resulting in the following data on time (in seconds) to complete the escape ("Oxygen Consumption and Ventilation During Escape from an Offshore Platform," Ergonomics [1997]: \(281-292\) ): \(\begin{array}{lllllllll}389 & 356 & 359 & 363 & 375 & 424 & 325 & 394 & 402 \\\ 373 & 373 & 370 & 364 & 366 & 364 & 325 & 339 & 393 \\ 392 & 369 & 374 & 359 & 356 & 403 & 334 & 397 & \end{array}\) a. Construct a dotplot of the data. Will the mean or the median be larger for this data set? b. Calculate the values of the mean and median. c. By how much could the largest time be increased without affecting the value of the sample median? By how much could this value be decreased without affecting the value of the median?

The San Luis ObispoTelegram-Tribune(October1,1994) reported the following monthly salaries for supervisors from six different counties: \(\$ 5,354\) (Kern), \(\$ 5,166\) (Monterey), \(\$ 4,443\) (Santa Cruz), \(\$ 4,129\) (Santa Barbara), \(\$ 2,500\) (Placer), and \$2,220 (Merced). San Luis Obispo County supervisors are supposed to be paid the average of the two counties in the middle of this salary range. Which measure of center determines this salary, and what is its value? Find the value of the other measure of center featured in this chapter. Why is it not as favorable to the San Luis Obispo County supervisors (although it might appeal to taxpayers)?

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