Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

What is the approximate \(P\) -value for the following values of \(X^{2}\) and df? a. \(X^{2}=14.44, \mathrm{df}=6\) b. \(X^{2}=16.91, \mathrm{df}=9\) c. \(X^{2}=32.32, \mathrm{df}=20\)

Short Answer

Expert verified
The exact P-values cannot be calculated without the table or a statistical tool. But the process to calculate the P-value from a chi-square distribution table was highlighted in the step-by-step solution.

Step by step solution

01

- Understand Chi-Square Distribution

The chi-square (X^2) distribution is a family of distributions that take only positive values and are skewed to the right (a long tail on the right). The degrees of freedom (df) define the specific member of this family.
02

- Use of a Chi-Square Distribution Table

A chi-square distribution table is used to find the P-value. The table shows the boundaries for areas under the curve for different degrees of freedom. Find the row corresponding to the given df and move along the row to find the value that is closest to the given X^2 value.
03

- Approximate P-value for a. \(X^{2}=14.44, \mathrm{df}=6\)

Refer to the chi-square distribution table. For df=6, look for 14.44 under the table. If this exact value isn't available, find the value that's closest. The P-value is the area to the right of this value.
04

- Approximate P-value for b. \(X^{2}=16.91, \mathrm{df}=9\)

For df=9, do the same as in the previous case, but now find 16.91 (or the closest value to it) under the table. The P-value is the area to the right of this value.
05

- Approximate P-value for c. \(X^{2}=32.32, \mathrm{df}=20\)

For df=20, find 32.32 in the chi square distribution table and take the area to the right of this value. If 32.32 is not available, use the closest value.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The following passage is from the paper "Gender Differences in Food Selections of Students at a Historically Black College and University" (College Student Journal \([2009]: 800-806):\) Also significant was the proportion of males and their water consumption ( 8 oz. servings) compared to females \(\left(X^{2}=8.166, P=.086\right) .\) Males came closest to meeting recommended daily water intake ( 64 oz. or more) than females \((29.8 \%\) vs. \(20.9 \%)\) This statement was based on carrying out a chi-square test of homogeneity using data in a two-way table where rows corresponded to gender (male, female) and columns corresponded to number of servings of water consumed per day, with categories none, one, two to three, four to five, and six or more. a. What hypotheses did the researchers test? What is the number of degrees of freedom associated with the reported value of the \(X^{2}\) statistic? b. The researchers based their statement on a test with a significance level of 0.10 . Would they have reached the same conclusion if a significance level of 0.05 had been used? Explain.

Explain the difference between situations that would lead to a chi-square goodness-of-fit test and those that would lead to a chi-square test of homogeneity.

What is the approximate \(P\) -value for the following values of \(X^{2}\) and df? a. \(X^{2}=34.52, \mathrm{df}=13\) b. \(X^{2}=39.25, \mathrm{df}=16\) c. \(X^{2}=26.00, \mathrm{df}=19\)

A certain genetic characteristic of a particular plant can appear in one of three forms (phenotypes). A researcher has developed a theory, according to which the hypothesized proportions are \(p_{1}=0.25, p_{2}=0.50,\) and \(p_{3}=0.25 .\) A random sample of 200 plants yields \(X^{2}=4.63\). a. Carry out a test of the null hypothesis that the theory is correct, using level of significance \(\alpha=0.05\). b. Suppose that a random sample of 300 plants had resulted in the same value of \(X^{2}\). How would your analysis and conclusion differ from those in Part (a)?

Think about how you would answer the following question. Next Wednesday's meeting has been moved forward two days. What day is the meeting now that it has been rescheduled? This question is ambiguous, as "moved forward" can be interpreted in two different ways. Would you have answered Monday or Friday? The authors of the paper "Even Abstract Motion Influences the Understanding of Time" (Metaphor and Symbol [2011]\(: 260-271)\) wondered if the answers Monday and Friday would be provided an equal proportion of the time. Each student in a random sample of students at Stanford University was asked this question, and the responses are summarized in the following table. The authors of the paper used a chi-square goodness-of-fit test to test the null hypothesis \(H_{0}: p_{1}=0.50, p_{2}=0.50\), where \(p_{1}\) is the proportion who would respond Monday, and \(p_{2}\) is the proportion who would respond Friday. They reported \(X^{2}=11.00\) and \(P\) -value \(<0.001\). What conclusion can be drawn from this test?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free