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Do children diagnosed with attention deficit/ hyperactivity disorder (ADHD) have smaller brains than children without this condition? This question was the topic of a research study described in the paper "Developmental Trajectories of Brain Volume Abnormalities in Children and Adolescents with Attention Deficit/Hyperactivity Disorder" (journal of the American Medical Association [2002]: \(1740-\) 1747). Brain scans were completed for a representative sample of 152 children with ADHD and a representative sample of 139 children without ADHD. Summary values for total cerebral volume (in milliliters) are given in the following table: $$ \begin{array}{lccc} & n & \bar{x} & s \\ \hline \text { Children with ADHD } & 152 & 1,059.4 & 117.5 \\ \text { Children Without ADHD } & 139 & 1,104.5 & 111.3 \end{array} $$ Use a \(95 \%\) confidence interval to estimate the differ- ence in mean brain volume for children with and without ADHD.

Short Answer

Expert verified
The 95% confidence interval calculated from the given data gives the difference in the average brain volume for children with ADHD and those without ADHD with 95% confidence. If the interval contains 0, it suggests that there is no significant difference in mean brain volumes for the two groups.

Step by step solution

01

Identify the given values

First, identify the summary statistics given for each group: \( n_1 = 152, \bar{x_1} = 1059.4, s_1 = 117.5 \) for the ADHD group and \( n_2 = 139, \bar{x_2} = 1104.5, s_2 = 111.3 \) for the non-ADHD group.
02

Calculate the standard error for the difference in means

The formula to compute Standard Error (SE) for difference of two means is \[ SE = \sqrt{\left(\frac{{s_1}^2}{n_1}\right) + \left(\frac{{s_2}^2}{n_2}\right)} \] Substituting the given values, you will obtain the standard error.
03

Calculate the 95% confidence interval for the difference in means

The formula for the 95% confidence interval (\( CI \)) for the difference in two means is \[ CI = (\bar{x_1} - \bar{x_2}) \pm z \cdot SE \] where \( z \) is the z-score corresponding to the desired confidence level (1.96 for 95% confidence level). With the calculated standard error and the given mean values, you will arrive at the confidence interval for the difference in mean brain volume for children with and without ADHD.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

ADHD Brain Volume Research
The relevance of research into the brain volume of children with ADHD lies in its potential to enhance our understanding of ADHD's neurological underpinnings. Brain imaging studies, like the one cited in the journal of the American Medical Association, aim to determine if structural differences exist between individuals with and without ADHD. This can offer insights into how such differences may affect behavior and cognitive functions associated with the disorder. High-quality research in this field can lead to more effective diagnostic methods and interventions, tailoring treatments to specific neurological profiles.
Standard Error Calculation
Understanding the concept of standard error (SE) is critical when interpreting data from studies like the ADHD brain volume research. SE measures the amount of variability in sample statistics from one sample to another if repeated samples were taken. To compute the standard error for the difference in means between two groups, you use the formula: \[ SE = \sqrt{\left(\frac{{s_1}^2}{n_1}\right) + \left(\frac{{s_2}^2}{n_2}\right)} \] This allows researchers to estimate the uncertainty surrounding the difference calculated from the sample means. A lower SE indicates that the sample mean is a more precise reflection of the true population mean.
Difference in Means
In research studies that compare two groups, a common statistic of interest is the difference in means. This measures the discrepancy between the average values of the two groups, providing a simple yet powerful means of assessing the contrast in their central tendencies. For example, in the ADHD brain volume study, the difference in mean brain volume between children with ADHD and those without is a focal outcome that could demonstrate a potential impact of the condition on brain development. By comparing the mean cerebral volumes, \( \bar{x_1} - \bar{x_2} \), we capture a snapshot of how the two groups differ on average.
Statistical Significance
Statistical significance is a cornerstone concept in hypothesis testing, helping us determine if our findings are likely to reflect true differences in the population or merely due to random chance. When calculating a 95% confidence interval for the difference in means, as seen in the ADHD research, we're essentially saying there's a 95% chance that the interval contains the true difference in brain volumes. The '95%' is a level of confidence selected to mitigate the likelihood of false-positive results while still remaining sensitive to true effects. If the confidence interval does not include zero, this suggests that the observed difference is statistically significant and unlikely to have occurred because of random variation alone.

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Most popular questions from this chapter

For each of the following hypothesis testing scenarios, indicate whether or not the appropriate hypothesis test would be for a difference in population means. If not, explain why not. Scenario 1: The authors of the paper "Adolescents and MP3 Players: Too Many Risks, Too Few Precautions" (Pediatrics [2009]: e953-e958) studied independent random samples of 764 Dutch boys and 748 Dutch girls ages 12 to \(19 .\) Of the boys, 397 reported that they almost always listen to music at a high volume setting. Of the girls, 331 reported listening to music at a high volume setting. You would like to determine if there is convincing evidence that the proportion of Dutch boys who listen to music at high volume is greater than this proportion for Dutch girls. Scenario 2: The report "Highest Paying Jobs for \(2009-10\) Bachelor's Degree Graduates" (National Association of Colleges and Employers, February 2010 ) states that the mean yearly salary offer for students graduating with accounting degrees in 2010 is \(\$ 48,722\). A random sample of 50 accounting graduates at a large university resulted in a mean offer of \(\$ 49,850\) and a standard deviation of \(\$ 3,300\). You would like to determine if there is strong support for the claim that the mean salary offer for accounting graduates of this university is higher than the 2010 national average of \(\$ 48,722\). Scenario 3: Each person in a random sample of 228 male teenagers and a random sample of 306 female teenagers was asked how many hours he or she spent online in a typical week (Ipsos, January 25,2006 ). The sample mean and standard deviation were 15.1 hours and 11.4 hours for males and 14.1 and 11.8 for females. You would like to determine if there is convincing evidence that the mean number of hours spent online in a typical week is greater for male teenagers than for female teenagers.

Do children diagnosed with attention deficit/hyperactivity disorder (ADHD) have smaller brains than children without this condition? This question was the topic of a research study described in the paper "Developmental Trajectories of Brain Volume Abnormalities in Children and Adolescents with Attention Deficit/Hyperactivity Disorder" ( Journal of the American Medical Association [2002]: \(1740-1747\) ). Brain scans were completed for a representative sample of 152 children with ADHD and a representative sample of 139 children without ADHD. Summary values for total cerebral volume (in cubic milliliters) are given in the following table:$$ \begin{array}{lccc} & n & \bar{x} & s \\ \hline \text { Children with ADHD } & 152 & 1,059.4 & 117.5 \\ \text { Children without ADHD } & 139 & 1,104.5 & 111.3 \\ \hline \end{array} $$ Is there convincing evidence that the mean brain volume for children with ADHD is smaller than the mean for children without ADHD? Test the relevant hypotheses using a 0.05 level of significance.

Head movement evaluations are important because disabled individuals may be able to operate communications aids using head motion. The paper "Constancy of Head Turning Recorded in Healthy Young Humans" (Journal of Biomedical Engineering [2008]\(: 428-436)\) reported the accompanying data on neck rotation (in degrees) both in the clockwise direction (CL) and in the counterclockwise direction (CO) for 14 subjects. For purposes of this exercise, you may assume that the 14 subjects are representative of the population of adult Americans. Based on these data, is it reasonable to conclude that mean neck rotation is greater in the clockwise direction than in the counterclockwise direction? Carry out a hypothesis test using a significance level of 0.01 . $$ \begin{array}{lccccccc} \text { Subject: } & 1 & 2 & 3 & 4 & 5 & 6 & 7 \\ \text { CL: } & 57.9 & 35.7 & 54.5 & 56.8 & 51.1 & 70.8 & 77.3 \\ \text { CO: } & 44.2 & 52.1 & 60.2 & 52.7 & 47.2 & 65.6 & 71.4 \\ \text { Subject: } & 8 & 9 & 10 & 11 & 12 & 13 & 14 \\ \text { CL: } & 51.6 & 54.7 & 63.6 & 59.2 & 59.2 & 55.8 & 38.5 \\ \text { CO: } & 48.8 & 53.1 & 66.3 & 59.8 & 47.5 & 64.5 & 34.5 \end{array} $$

The authors of the paper "Ultrasound Techniques Applied to Body Fat Measurement in Male and Female Athletes" (Journal of Athletic Training [2009]: \(142-147\) ) compared two different methods for measuring body fat percentage. One method uses ultrasound and the other method uses X-ray technology. The accompanying table gives body fat percentages for 16 athletes using each of these methods (a subset of the data given in a graph that appeared in the paper). For purposes of this exercise, you can assume that the 16 athletes who participated in this study are representative of the population of athletes. Do these data provide convincing evidence that the mean body fat percentage measurement differs for the two methods? Test the appropriate hypotheses using \(\alpha=0.05\). $$ \begin{array}{crr} \text { Athlete } & \text { X-ray } & \text { Ultrasound } \\ \hline 1 & 5.00 & 4.75 \\ 2 & 7.00 & 3.75 \\ 3 & 9.25 & 9.00 \\ 4 & 12.00 & 11.75 \\ 5 & 17.25 & 17.00 \\ 6 & 29.50 & 27.50 \\ 7 & 5.50 & 6.50 \\ 8 & 6.00 & 6.75 \\ 9 & 8.00 & 8.75 \\ 10 & 8.50 & 9.50 \\ 11 & 9.25 & 9.50 \\ 12 & 11.00 & 12.00 \\ 13 & 12.00 & 12.25 \\ 14 & 14.00 & 15.50 \\ 15 & 17.00 & 18.00 \\ 16 & 18.00 & 18.25 \end{array} $$

The Oregon Department of Health web site provides information on cost-to- charge ratio (the percentage of billed charges that are actual costs to the hospital). The following table gives cost-to-charge ratios for both inpatient and outpatient care in 2002 for a random sample of six hospitals in Oregon. $$ \begin{array}{ccc} & \begin{array}{c} 2002 \\ \text { Inpatient } \end{array} & \begin{array}{c} 2002 \\ \text { Hospital } \end{array} & \begin{array}{c} \text { Ratio } \\ \text { Ratient } \end{array} \\ \hline 1 & 68 & \text { Ratio } \\ 2 & 100 & 54 \\ 3 & 71 & 75 \\ 4 & 74 & 53 \\ 5 & 100 & 56 \\ 6 & 83 & 74 \\ & 88 \end{array} $$ Is there evidence that the mean cost-to-charge ratio for Oregon hospitals is lower for outpatient care than for inpatient care? Use a significance level of \(0.05 .\)

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