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The paper "Effects of Fast-Food Consumption on Energy Intake and Diet Quality Among Children in a National Household Survey" (Pediatrics [2004]: \(112-118\) ) investigated the effect of fast-food consumption on other dietary variables. For a representative sample of 663 teens who reported that they did not eat fast food during a typical day, the mean daily calorie intake was 2,258 and the sample standard deviation was \(1,519 .\) For a representative sample of 413 teens who reported that they did eat fast food on a typical day, the mean calorie intake was 2,637 and the standard deviation was \(1,138 .\) Use the given information and a \(95 \%\) confidence interval to estimate the difference in mean daily calorie intake for teens who do eat fast food on a typical day and those who do not.

Short Answer

Expert verified
The estimated 95% confidence interval for the difference in daily calorie consumption between teens who eat fast food and those who don't is between -202.25 and -555.75 calories per day.

Step by step solution

01

1. Identify the given data

First, we need to identify and organize the given data. We have two groups: group 1 is teens who did not eat fast food (n1 = 663, X̄1 = 2258, s1 = 1519) and group 2 is teens who ate fast food (n2 = 413, X̄2 = 2637, s2 = 1138)
02

2. Calculate the sample difference

The sample mean difference is \(X̄1 - X̄2\), so this is \(2258 - 2637 = -379\)
03

3. Calculate the standard error of the difference

The formula for the standard error of the difference is \(\sqrt{{{s1}^2/n1 + {s2}^2/n2}}\), substituting we get \(\sqrt{{(1519)^2/663 + (1138)^2/413}} = 89.91 \)
04

4. Calculate the 95% confidence interval

For a 95% confidence interval, the critical value is approximately 1.96. The interval is then \((X̄1 - X̄2) ± 1.96(standard error of the difference)\), which gives \(-379 ± 1.96*89.91\), or \(-379 ± 176.25\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean Difference
Understanding the concept of the sample mean difference is fundamental when comparing two different groups in a study. It represents the difference between the average outcomes of these groups. In our dietary study example, we compare the mean daily calorie intake between teens who did eat fast food on a typical day and those who did not. This is a pivotal step as it sets the foundation for estimating how distinct the two groups are from each other in terms of calorie intake. The calculation is straightforward: subtract one group's mean from the other's, which in this case results in a difference of erall calculation.
Standard Error of the Difference
The standard error of the difference is a bit more complex, as it measures the variability in the estimation of the sample mean difference. Put simply, it provides insight into how much we can expect the sample mean difference to vary if we were to repeat the study multiple times. To calculate the standard error of the difference, we use the formula with the sample standard deviations and sizes from both groups. For our specific dietary study, the calculation yielded a standard error of erall calculation.
Statistical Significance
Determining statistical significance is essential in discerning whether the observed difference in our study is likely real or just a result of random chance. It's a measure of how confident we can be in the results. Generally, we look at p-values or confidence intervals to assess this. A 95% confidence interval means we are 95% sure that the real mean difference lies within this range. The calculated interval from the dietary study was quite wide, indicating considerable variability, but still allowed us to infer that there is a meaningful difference in calorie intake between the two groups.
Dietary Study Statistics
In dietary study statistics, it's typical to look at caloric and nutrient intake differences among various groups to understand dietary patterns and their health implications. By calculating measures such as the sample mean difference and standard error, we can make inferences about the population. This is exactly what was done in the example study, where statistical techniques were applied to estimate the difference in calorie intake between teens consuming fast food and those not. Such studies can provide valuable insights for nutrition policy and dietary guidelines.

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Most popular questions from this chapter

The Oregon Department of Health web site provides information on cost-to- charge ratio (the percentage of billed charges that are actual costs to the hospital). The following table gives cost-to-charge ratios for both inpatient and outpatient care in 2002 for a random sample of six hospitals in Oregon. $$ \begin{array}{ccc} & \begin{array}{c} 2002 \\ \text { Inpatient } \end{array} & \begin{array}{c} 2002 \\ \text { Hospital } \end{array} & \begin{array}{c} \text { Ratio } \\ \text { Ratient } \end{array} \\ \hline 1 & 68 & \text { Ratio } \\ 2 & 100 & 54 \\ 3 & 71 & 75 \\ 4 & 74 & 53 \\ 5 & 100 & 56 \\ 6 & 83 & 74 \\ & 88 \end{array} $$ Is there evidence that the mean cost-to-charge ratio for Oregon hospitals is lower for outpatient care than for inpatient care? Use a significance level of \(0.05 .\)

In a study of the effect of college student employment on academic performance, the following summary statistics for GPA were reported for a sample of students who worked and for a sample of students who did not work (University of Central Florida Undergraduate Research Journal, Spring 2005\()\) : $$ \begin{array}{cccc} & \begin{array}{c} \text { Sample } \\ \text { Size } \end{array} & \begin{array}{c} \text { Mean } \\ \text { GPA } \end{array} & \begin{array}{c} \text { Sandard } \\ \text { Deviation } \end{array} \\ \begin{array}{c} \text { Students Who Are } \\ \text { Employed } \end{array} & 184 & 3.12 & 0.485 \\ \begin{array}{c} \text { Students Who Are } \\ \text { Not Employed } \end{array} & 114 & 3.23 & 0.524 \\ \hline \end{array} $$ The samples were selected at random from working and nonworking students at the University of Central Florida. Does this information support the hypothesis that for students at this university, those who are not employed have a higher mean GPA than those who are employed?

The paper "Ladies First?" A Field Study of Discrimination in Coffee Shops" (Applied Economics [2008]: 1-19) describes a study in which researchers observed wait times in coffee shops in Boston. Both wait time and gender of the customer were observed. The mean wait time for a sample of 145 male customers was 85.2 seconds. The mean wait time for a sample of 141 female customers was 113.7 seconds. The sample standard deviations (estimated from graphs in the paper) were 50 seconds for the sample of males and 75 seconds for the sample of females. Suppose that these two samples are representative of the populations of wait times for female coffee shop customers and for male coffee shop customers. Is there convincing evidence that the mean wait time differs for males and females? Test the relevant hypotheses using a significance level of 0.05

The paper "Sodium content of Lunchtime Fast Food Purchases at Major U.S. Chains" (Archives of Internal Medicine [2010]: \(732-734\) ) reported that for a random sample of 850 meal purchases made at Burger King, the mean sodium content was \(1,685 \mathrm{mg}\), and the standard deviation was \(828 \mathrm{mg}\). For a random sample of 2,107 meal purchases made at McDonald's, the mean sodium content was \(1,477 \mathrm{mg},\) and the standard deviation was \(812 \mathrm{mg} .\) Based on these data, is it reasonable to conclude that there is a difference in mean sodium content for meal purchases at Burger King and meal purchases at McDonald's? Use \(\alpha=0.05\).

Do male college students spend more time using a computer than female college students? This was one of the questions investigated by the authors of the paper "An Ecological Momentary Assessment of the Physical Activity and Sedentary Behaviour Patterns of University Students" (Health Education Journal [2010]: \(116-125\) ). Each student in a random sample of 46 male students at a university in England and each student in a random sample of 38 female students from the same university kept a diary of how he or she spent time over a three-week period. For the sample of males, the mean time spent using a computer per day was 45.8 minutes and the standard deviation was 63.3 minutes. For the sample of females, the mean time spent using a computer was 39.4 minutes and the standard deviation was 57.3 minutes. Is there convincing evidence that the mean time male students at this university spend using a computer is greater than the mean time for female students? Test the appropriate hypotheses using \(\alpha=0.05 .\) (Hint: See Example 13.1\()\)

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